yii manage sub table's data in form - php

I am working on YII framework, and I am a newbie.
I have user register form as shown below:
Username: [Textbox]
Email: [Textbox]
Address: [Text area]
User Loan Type: (Checkbox list as below)
Loan Type 1
Loan Type 2
Loan Type 3
Loan Type 4
Loan Type 5
Status [yes/no]
Now I have 3 models:
1) User (for user data)
2) LoanType (just for loan type list)
3) UserLoanType (mapping between user and loan type)
All 3 models have HAS_MANY and BELONGS_TO relations as we generally do in YII.
Now when user click on register button I want to save data in user_loan_type table as well. I can simply add core php logic in actionCreate. But is there any standard YII practice for this?? Because I need validation, remain form selected during edit etc. Can anyone guide me how to do this? Or point me any example link, I have googled but did't help.
Thanks.
I am able to save data in database,
Now during edit I want to retrieve 3rd table's(tbl_user_loan_request_type) data. I have used below code.
$user = User::model()->findByPk(5);
print_r($user->UserLoanTypes);
But it is giving me blank array.
Where I am wrong??

You may define afterSave methods in your class, like this:
Model User
public function relations()
{
return array(
'UserLoanTypes' => array(self::MANY_MANY, 'LoanType', 'UserLoanType(userId, loanId)'),
);
}
// relation
array('UserLoanTypes', 'safe'),
// label
'UserLoanTypes' => 'User Loan Type'
protected function afterSave()
{
parent::afterSave();
UserLoanType::model()->deleteAll('userId=:id', array(':id' => $this->id));
foreach ($this->UserLoanTypes as $loanId) {
$userLoanType = new UserLoanType();
$userLoanType->userId = $this->id;
$userLoanType->loadId = $loadId;
$userLoanType->save();
}
}
protected function afterDelete()
{
parent::afterDelete();
UserLoanType::model()->deleteAll('userId=:id', array(':id' => $this->id));
}
In form:
<div class="row">
<?php echo $form->labelEx($model,'UserLoanTypes'); ?>
<?php echo $form->checkBoxList($model,'UserLoanTypes', CHtml::listData($LoanTypes, 'id', 'loanName')); ?>
<?php echo $form->error($model,'UserLoanTypes'); ?>
</div>
In view you may:
<?php $this->widget('zii.widgets.CDetailView', array(
'data'=>$model,
'attributes'=>array(
'id',
'name',
'UserLoanTypes' => array(
'name' => 'UserLoanTypes',
'value' => implode(',', CHtml::listData($model->UserLoanTypes, 'id', 'name')),
),
),
)); ?>

If you don't need to assign multiple loanTypes to one User, it would be easier. All you need is the User model for the form visualization:
<?php $form = $this->beginWidget('CActiveForm', array(
'id'=>'user-form',
)); ?>
<?php echo $form->errorSummary($model); ?>
<div class="row">
<?php echo $form->labelEx($model,'Username'); ?>
<?php echo $form->textField($model,'Username'); ?>
<?php echo $form->error($model,'Username'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($model,'Email'); ?>
<?php echo $form->textField($model,'Email'); ?>
<?php echo $form->error($model,'Email'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($model,'Address'); ?>
<?php echo $form->textArea($model,'Address'); ?>
<?php echo $form->error($model,'Address'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($model,'UserLoanType'); ?>
<?php echo $form->checkBoxList($model,'idLoanType', CHtml::listData(LoanType::model()->findAll, 'id', 'name')); ?>
<?php echo $form->error($model,'UserLoanTypes'); ?>
</div>
<?php $this->endWidget(); ?>

Related

undefined variable model in yii

I am getting the error undefined variable model. I have the following codes in my view and controller. My aim is to search the results and show it in same page. I have tried the following things but its not working.
Again,I this this the conventional yii method to do so,or do I have to use a search() function from model SearchEmployee().?
public function actionSearch()
{
$model = new SearchEmployee();
/*Getting Data From Search Form For Processing */
if (isset($_POST['SearchEmployee'])) {
$category = $_POST['SearchEmployee']['category_id'];
$skills = $_POST['SearchEmployee']['skills'];
$experience = $_POST['SearchEmployee']['experience'];
$model = SearchEmployee::model()->find(array(
'select' => array('*'), "condition" => "category_id=$category AND key_skills like '%$skills%' AND experience=$experience",
));
$this->render('search',$model);
}
/*Getting Data From Search Form For Processing */
$this->render('search', array('model' => $model));
}
In View Section: search.php//To display and search the desired result
<div class="row">
<?php echo $form->labelEx($model,'Category'); ?>
<?php echo $form->dropDownList($model,'category_id',$list,array('empty' =>'(Select a Category')); ?>
<?php echo $form->error($model,'category'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($model,'Experience'); ?>
<?php echo $form->textField($model,'experience'); ?>
<?php echo $form->error($model,'experience'); ?>
</div>
<div class="row buttons">
<?php echo CHtml::submitButton('Search'); ?>
</div>
<div class="view">
<h1>Results </h1>
<div class="view" id="id">
<h1> Records Display </h1>
<h4>Name: <?php echo $form->labelEx($model,'name'); ?></h4>
<h4>Skills: <?php echo $form->labelEx($model,'experience'); ?></h4>
<h4>Experience: <?php echo $form->labelEx($model,'skills'); ?></h4>
<h5> &nbsp ;<?php echo $form->labelEx('VIew Details'); ?></h5>
</div>
</div>
In view section I am using the search and view results option in the same form.I am getting the error after clicking the search button.Is this the correct way to do
$model = SearchEmployee::model()->find(array(
'select' => array('*'), "condition" => "category_id=$category AND
key_skills like '%$skills%' AND experience=$experience",
));
There is error here. You can't use find in that way.
public function find($condition='',$params=array())
$model = SearchEmployee::model()->find("category_id=$category AND
key_skills like '%$skills%' AND experience=$experience");
But better
$model = SearchEmployee::model()->find("category_id=:category AND key_skills like :skill AND experience=:experience", array(
'category'=>$category,
'skill'=>'%'.$skills.'%',
'experience'=>$experience
));
Remove this line:
$this->render('search',$model);
First it's invalid because it should be:
$this->render('search', array('model' => $model));
But also it's unnecessary because you already have it lower in your code.

display view page with data from two models in yii

I have two models Register and Login.I insert data into these two tables from a single form,I want to display the entered data in a single view page,ie data from two models in a single view.php.
RegisterController.php
public function actionCreate()
{
$model = new Register;
$modelLogin = new Login;
$modelGenerate = new Generate;
$row = Generate::model()->findByPk('1') ;
$gen_reg = $row['gen_reg'];
$gen_log = $row['gen_log'];
// Uncomment the following line if AJAX validation is needed
// $this->performAjaxValidation($model);
if(isset($_POST['btnRegister']))
{
$model->attributes=$_POST['Register'];
$modelLogin->attributes=$_POST['Login'];
$modelLogin->reg_id=$model->reg_id;
$valid = $model->validate();
$valid = $modelLogin->validate() && $valid;
if($model->save()&& $modelLogin->save())
$this->redirect(array('view','id'=>$modelLogin->log_id)
);
}
$this->render('create',array(
'model'=>$model,
'modelLogin'=>$modelLogin,
'gen_reg'=>$gen_reg,
'gen_log'=>$gen_log
));
}
_form.php
<?php $form=$this->beginWidget('CActiveForm', array(
'id'=>'register-form',
// Please note: When you enable ajax validation, make sure the corresponding
// controller action is handling ajax validation correctly.
// There is a call to performAjaxValidation() commented in generated controller code.
// See class documentation of CActiveForm for details on this.
'enableAjaxValidation'=>true,
)); ?>
<div class="row">
<?php echo $form->textField($model,'reg_id',array('size'=>10,'maxlength'=>10,'class'=>'txt'));?>
</div>
<div class="row">
<?php echo $form->labelEx($model,'username'); ?>
<?php echo $form->textField($model,'username',array('size'=>50,'maxlength'=>50,'class'=>'txt')); ?>
<?php echo $form->error($model,'username'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($modelLogin,'email'); ?>
<?php echo $form->textField($modelLogin,'email',array('size'=>60,'maxlength'=>100,'class'=>'txt')); ?>
<?php echo $form->error($modelLogin,'email'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($modelLogin,'password'); ?>
<?php echo $form->passwordField($modelLogin,'password',array('size'=>50,'maxlength'=>50,'class'=>'txt')); ?>
<?php echo $form->error($modelLogin,'password'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($modelLogin,'passwordCompare'); ?>
<?php echo $form->passwordField($modelLogin,'passwordCompare',array('size'=>60,'maxlength'=>64,'class'=>'txt')); ?>
</div>
<div class="row">
<?php echo $form->labelEx($model,'mobile'); ?>
<?php echo $form->textField($model,'mobile',array('size'=>10,'maxlength'=>10,'class'=>'txt')); ?>
<?php echo $form->error($model,'mobile'); ?>
</div>
<div class="row">
<?php echo $form->textField($modelLogin,'log_id',array('size'=>10,'maxlength'=>10,'class'=>'txt'));?>
</div>
<div class="row buttons">
<?php echo CHtml::submitButton($model->isNewRecord ? 'Register' : 'Save',array('name'=>'btnRegister','class'=>'btn')); ?>
</div>
<?php $this->endWidget(); ?>
Relation in register model
public function relations()
{
// NOTE: you may need to adjust the relation name and the related
// class name for the relations automatically generated below.
return array(
'logins' => array(self::HAS_MANY, 'Login', 'reg_id'),
);
}
Relation in login model
public function relations()
{
// NOTE: you may need to adjust the relation name and the related
// class name for the relations automatically generated below.
return array(
'reg' => array(self::BELONGS_TO, 'Register', 'reg_id'),
);
}
I want to display data from two models(that i just inserted before)to be displayed on my view.php page.how can i achive this??? now i got the output as not set for fields from Login model.
view.php
$this->breadcrumbs=array(
'Register'=>array('index'),
$model->reg_id,
);
$this->menu=array(
array('label'=>'List Register', 'url'=>array('index')),
array('label'=>'Create Register', 'url'=>array('create')),
array('label'=>'Update Register', 'url'=>array('update', 'id'=>$model->reg_id)),
array('label'=>'Delete Register', 'url'=>'#', 'linkOptions'=>array('submit'=>array('delete','id'=>$model->reg_id),'confirm'=>'Are you sure you want to delete this item?')),
array('label'=>'Manage Register', 'url'=>array('admin')),
);
?>
<h1>View Register #<?php echo $model->reg_id; ?></h1>
<?php $this->widget('zii.widgets.CDetailView', array(
'data'=>$model,
'attributes'=>array(
'reg_id',
'username',
'mobile',
),
)); ?>
<?php $this->widget('zii.widgets.CDetailView', array(
'data'=>$row,
'attributes'=>array(
'log_id',
'password',
'email',
),
)); ?>

Yii Framework One to many relationship

Im having a bit of a headache with trying to input data into a one to many relationship table (videos) from one form which has access to the main database called movie.. so one movie can have lots of videos attached to it.. I have one form which can add more than one video through the users being able to add more text fields for the amount of videos they want to store..tried various option. but the records dont seem to store inside the youtube_video table..
this is what I have got so far...
Movie Model (Movie)
public function relations()
{
// NOTE: you may need to adjust the relation name and the related
// class name for the relations automatically generated below.
return array(
'competitions' => array(self::HAS_MANY, 'Competition', 'movie_id'),
'studio' => array(self::BELONGS_TO, 'Studio', 'studio_id'),
'country' => array(self::BELONGS_TO, 'Country', 'country_id'),
'movieRating' => array(self::BELONGS_TO, 'MovieRating', 'movie_rating_id'),
'mapPin' => array(self::BELONGS_TO, 'MapPin', 'map_pin_id'),
'twitterFeeds' => array(self::HAS_MANY, 'TwitterFeed', 'movie_id'),
'YoutubeVideo' => array(self::HAS_MANY, 'YoutubeVideo', 'movie_id'),
);
}
Movie Form Part of the Form -
<div class="row">
<?php echo $form->labelEx($model,'description'); ?>
<?php echo $form->textArea($model,'description',array('rows'=>6, 'cols'=>50)); ?>
<?php echo $form->error($model,'description'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($model,'title_trailer_youtube_code'); ?>
<?php echo $form->textField($model,'title_trailer_youtube_code',array('size'=>50,'maxlength'=>50)); ?>
<?php echo $form->error($model,'title_trailer_youtube_code'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($model,'title_image'); ?>
<?php echo CHtml::activeFileField($model, 'title_image'); ?>
<?php echo $form->error($model,'title_image'); ?>
</div>
<div class="row clone">
<?php echo $form->labelEx($modelYoutubeVideo,'embed_code'); ?>
<?php echo $form->textField($modelYoutubeVideo,'embed_code',array('size'=>50,'maxlength'=>50)); ?>
<?php echo $form->error($modelYoutubeVideo,'embed_code'); ?>
<?php echo $form->labelEx($modelYoutubeVideo,'description'); ?>
<?php echo $form->textField($modelYoutubeVideo,'description',array('size'=>50,'maxlength'=>250)); ?>
<?php echo $form->error($modelYoutubeVideo,'description'); ?>
</div>
Movie Controller -
public function actionCreate()
{
$model=new Movie; // this is my model related to table
$modelYoutubeVideo=new YoutubeVideo;
if(isset($_POST['Movie']))
{
$model->attributes=$_POST['Movie'];
// Save Title Image and store file name in database
$_POST['Movie']['title_image'] = $model->title_image;
$uploadedFile=CUploadedFile::getInstance($model,'title_image');
$name = $uploadedFile->getName();
$model->title_image = $name;
if($model->save())
{
if(!empty($uploadedFile)) // check if uploaded file is set or not
{
$uploadedFile->saveAs(Yii::getPathOfAlias('webroot')."/title_image/".$name);
}
$modelYoutubeVideo = new YoutubeVideo();
$modelYoutubeVideo->attributes=$_POST['youtube_video'];
// Redirect to admin
$this->redirect(array('admin'));
}
}
$this->render('create',array(
'model'=>$model,
'modelYoutubeVideo'=>$modelYoutubeVideo,
));
}
Well, are you duplicating <div class="row clone"> many times to allow people to link more videos? Because if you are then you are not saving them in the DB.
After you save the the main record "foreach" through the videos and save each of them. Also you never save $modelYoutubeVideo so ....
After
$modelYoutubeVideo->attributes=$_POST['youtube_video'];
you should put
$modelYoutubeVideo->save();

Setting default values and Creating into Database using Yii

I'm trying to create a new user but I'm having trouble trying to create the user because some of the values that are needed to create a user must be default values that I'm not quite sure how to set. I also need to input into a different table while the actual "create" happens from a different controller.
Here is my form code:
<?php
/* #var $this SystemUserController */
/* #var $model SystemUser */
/* #var $form CActiveForm */
?>
<div class="form">
<?php $form=$this->beginWidget('CActiveForm', array(
'id'=>'system-user-form',
'enableAjaxValidation'=>false,
)); ?>
<p class="note">Fields with <span class="required">*</span> are required.</p>
<?php echo $form->errorSummary($model); ?>
<!--
<div class="row">
<?php echo $form->labelEx($model,'party_id'); ?>
<?php echo $form->textField($model,'party_id',array('size'=>20,'maxlength'=>20)); ?>
<?php echo $form->error($model,'party_id'); ?>
</div>
!-->
<div class="row" id="toshow" style="display:none" name="suppliers"> <?php $supplier = SupplierHead::model()->findAll();
$list = CHtml::listData($supplier ,'head_id','head_name');
echo $form->DropDownList($model,'party_id',
$list, array('prompt'=>'Select Supplier')); ?>
</div>
<button id="abutton">Already a Supplier</button>
<script>
$(document).ready(function() {
$("#abutton").click(function(e){
e.preventDefault();
$("#toshow").css('display', 'block');
});
});
</script>
<div class="row">
<?php echo $form->labelEx($model,'username'); ?>
<?php echo $form->textField($model,'username',array('size'=>60,'maxlength'=>200)); ?>
<?php echo $form->error($model,'username'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($model,'password'); ?>
<?php echo $form->passwordField($model,'password',array('size'=>60,'maxlength'=>255)); ?>
<?php echo $form->error($model,'password'); ?>
</div>
<script>
$("#supplier").click(function () {
$("#suppliers").show("slow");
});
</script>
<!--
<div class="row">
<?php echo $form->labelEx($model,'date_last_login'); ?>
<?php echo $form->textField($model,'date_last_login'); ?>
<?php echo $form->error($model,'date_last_login'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($model,'status'); ?>
<?php echo $form->textField($model,'status',array('size'=>50,'maxlength'=>50)); ?>
<?php echo $form->error($model,'status'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($model,'date_created'); ?>
<?php echo $form->textField($model,'date_created'); ?>
<?php echo $form->error($model,'date_created'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($model,'date_modified'); ?>
<?php echo $form->textField($model,'date_modified'); ?>
<?php echo $form->error($model,'date_modified'); ?>
</div>
--!>
<div class="row">
<?php echo $form->labelEx($model,'user_role'); ?>
<?php echo $form->textField($model,'user_role',array('size'=>60,'maxlength'=>255)); ?>
<?php echo $form->error($model,'user_role'); ?>
</div>
<!--
<div class="row">
<?php echo $form->labelEx($model,'isLogin'); ?>
<?php echo $form->textField($model,'isLogin'); ?>
<?php echo $form->error($model,'isLogin'); ?>
</div>
--!>
<div class="row buttons">
<?php echo CHtml::submitButton($model->isNewRecord ? 'Create' : 'Save'); ?>
</div>
<?php $this->endWidget(); ?>
</div><!-- form -->
As you can see, I've commented out the attributes that I don't want to use. I also fixed the SystemUser model attributes rules() to define which attributes won't be needed for user input here:
public function rules()
{
// NOTE: you should only define rules for those attributes that
// will receive user inputs.
return array(
array('party_id, username, password', 'required'),
//array('isLogin', 'numerical', 'integerOnly'=>true),
array('party_id', 'length', 'max'=>20),
array('username', 'length', 'max'=>200),
array('password, user_role', 'length', 'max'=>255),
// The following rule is used by search().
// Please remove those attributes that should not be searched.
array('party_id, username' 'on'=>'search'),
);
}
Finally, there's also a drop down list I included above from the form that is required to be inserted into a model of a different controller. How do I go about this?
The attributes that need default values are as follows:
date_last_login
status
date_created
date_modified
EDIT
I've uploaded a picture of what happens when I select "Create"
I decided not to add defaults try keeping them NULL just to see if the rules() would work. I
Any help?
Yii's model has methods such as:
beforeSave()
afterSave()
beforeValidate()
afterValidate()
and so on ...
which can be overridden into your model. If you want to set any default value before saving/validating you can use from mentioned methods in your model. Please take a look at the following example:
public function beforeSave() {
if (parent::beforeSave()) {
//Example
$this->date_modified=new New CDbExpression('NOW()');
//ANOTHER EXAMPLE
$this->date=date('Y-m-d',time());
// YOU CAN EVEN CALLING A WEBSERVICE
// ANYTHING THAT YOU WANT TO DO BEFORE SAVING INTO DATABASE
return true;
}
}
other methods such as afterSave and ... work like above.
I hope it help :)
You can use the rules for it like
public function rules()
{
return array(
// your other rules
array('myField','default','value'=>'my Name'),
// for date type use new CDbExpression('NOW()')
array('date_modified','default',
'value'=>new CDbExpression('NOW()'),
),
// rest of your rules
);
}
Try with this data type:
date_last_login : timestamp
status : enum('active','inactive')
date_created : timestamp
date_modified : timestamp
Defult Time stamp: current_timestamp

Auto complete fields of a previous values

I am doing a small application in Yii Framework for that my database is something like this
=== Invoices ===
id (PK)
customer_id
invoice_title
order_no
invoice_issue_date
due_date
description
=== Customers ===
id (PK)
email_address
customer_name
address
city
state
postal_code
description
I have rendered the Customer model in Invoice model so that I can enter all the values for both models in a single Invoice form.But there is one problem,let us assume that I have a customer name xyz which I had saved before.Now when I am going to again fill the Customer name with xyz,it should show all the fields of both models like invoice_title,order_no,invoice_issue_date,due_date,description,email_address,customer_name,address etc. in that input fields of the form so that I don't have to re-enter all the fields again.So how this can be achive in Yii framework.Any help and suggestions will be highly appreciable.More clarification on codes that I have done can be shared if needed.
Please help me out.I am totally stuck here.
To do this as everyone has already mentioned you need ajax, and some javascript. The logic is something like this:
When a value is selected in the dropdown for customer name, trigger an ajax call to retrieve the information about that user. This can be easily done with the ajax option, which is available as an additional htmlOption for some html element helpers in CHtml, as part of clientChange.
echo $form->dropDownList($model,'customer_name',CHtml::listData(Customers::model()->findAll(),'id','customer_name'),
array(// htmlOptions
'ajax'=>array(// special htmlOption through clientChange, for ajax
'type'=>'GET',
'url'=>$this->createUrl('controllername/customerdetails'),// action that will generate the data
'data'=>'js:"id="+$(this).val()',// this is the data that we are sending to the action in the controller
'dataType'=>'json',// type of data we expect back from the server
'success'=>'js:updateFields'// a javascript function that will execute when the request completes successfully
)
)
);
The documentation for the above options for ajax can be seen in jquery's ajax documentation.
Then in the server side find the particular customer, and send a response to the browser. Example:
// in the controllername code an action that will return the values as json
public function actionCustomerdetails($id){
$var=Customers::model()->findByPk($id);
echo CJSON::encode($var);
}
When you receive the server response populate the respective fields. This can be done in the success function callback for ajax, in the above code it was updateFields:
Yii::app()->clientScript->registerScript('update','
function updateFields(data, textStatus, jqXHR){
// select each input field by id, and update its value
$("#Customers_postal_code").val(data.postal_code);
$("#Customers_city").val(data.city);
$("#Customers_address").val(data.address);
// similarly update the fields for the other inputs
}
');
Notes:
Your customer can have many invoices, so the question will be which invoice to select given a customer name. That's something you'll have to handle, i think my answer has enough code to get you going.
To know the input field ids, you can simply check the generated html.
You could do this in two stages, so that:
When the view is initially displayed, the customer is asked for their email address or customer_name.
The Controller Action that the form is submitted to then retrieves data from the Customer model for the submitted email address or customer_name (I'll use email_address in my example below). Once retrieved, you can display your Single Invoice Form View with the data pre-populated for the customer if available.
This concept could then be implemented as follows:
<?php
// file: controllers/InvoiceController.php
class InvoiceController extends CController
{
// ... other controller functions
public function actionCreate($step = null)
{
$invoice = new Invoice;
$customer = new Customer;
# Form has been submitted:
if ( isset($_POST['Customer']) )
{
# The submitted form was Step 1:
if ( $step == 1 )
{
# make sure the submitted email address is valid
$customer->setAttributes($_POST['Customer']);
if ( $customer->validate(array('email_address')) )
{
# retrieve the customer by email_address
$customer = Customer::model()->findByAttributes(array('email_address' => $_POST['Customer']['email_address']));
}
$this->render('createstep2', array('invoice' => $invoice, 'customer' => $customer));
}
# The submitted form was Step 2:
elseif ( $step == 2 )
{
$income->setAttributes($_POST['Invoice']);
$customer->setAttributes($_POST['Customer']);
# save the data
if ( $customer->save() )
{
$invoice->customer_id = $customer->id;
if ( $invoice->save() )
{
$this->redirect(array('view', 'id' => $invoice->id));
}
}
# display any errors
$this->render('createstep2', array('invoice' => $invoice, 'customer' => $customer));
}
}
$this->render('createstep1', array('invoice' => $invoice, 'customer' => $customer));
}
// ... other controller functions
}
?>
You could split that to two separate Controller Actions if you wish.
For Step 1 View, you could then have the following:
<!-- file: views/invoice/createstep1.php -->
<h1>Create Invoice: Step 1</h1>
<div class="form">
<?php
$form = $this->beginWidget('CActiveForm', array(
'id'=>'invoice-form',
'enableAjaxValidation'=>false,
'action'=>array('invoice/create','step' => 1)
));
?>
<?php echo $form->errorSummary($customer); ?>
<div class="row">
<?php echo $form->labelEx($customer,'email_address'); ?>
<?php echo $form->textField($customer,'email_address', array('size'=>60,'maxlength'=>255)); ?>
<?php echo $form->error($customer,'email_address'); ?>
</div>
<div class="row buttons">
<?php echo CHtml::submitButton('Next'); ?>
</div>
<?php $this->endWidget(); ?>
</div><!-- form -->
Step 2 view, you could then look like what you already have. Maybe something like:
<!-- file: views/invoice/createstep2.php -->
<h1>Create Invoice: Step 2</h1>
<div class="form">
<?php
$form = $this->beginWidget('CActiveForm', array(
'id'=>'invoice-form',
'enableAjaxValidation'=>false,
'action'=>array('invoice/create','step' => 2)
));
?>
<?php echo $form->errorSummary($invoce); ?>
<?php echo $form->errorSummary($customer); ?>
<h2>Customer Details</h2>
<div class="row">
<?php echo $form->labelEx($customer,'email_address'); ?>
<?php echo $form->textField($customer,'email_address', array('size'=>60,'maxlength'=>255)); ?>
<?php echo $form->error($customer,'email_address'); ?>
</div>
<!-- If the customer already exists, these field should be pre-populated: -->
<div class="row">
<?php echo $form->labelEx($customer,'customer_name'); ?>
<?php echo $form->textField($customer,'customer_name', array('size'=>60,'maxlength'=>255)); ?>
<?php echo $form->error($customer,'customer_name'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($customer,'address'); ?>
<?php echo $form->textField($customer,'address', array('size'=>60,'maxlength'=>255)); ?>
<?php echo $form->error($customer,'address'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($customer,'city'); ?>
<?php echo $form->textField($customer,'city', array('size'=>60,'maxlength'=>255)); ?>
<?php echo $form->error($customer,'city'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($customer,'state'); ?>
<?php echo $form->textField($customer,'state', array('size'=>60,'maxlength'=>255)); ?>
<?php echo $form->error($customer,'state'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($customer,'postal_code'); ?>
<?php echo $form->textField($customer,'postal_code', array('size'=>60,'maxlength'=>255)); ?>
<?php echo $form->error($customer,'postal_code'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($customer,'description'); ?>
<?php echo $form->textField($customer,'description', array('size'=>60,'maxlength'=>255)); ?>
<?php echo $form->error($customer,'description'); ?>
</div>
<h2>Order Details</h2>
<div class="row">
<?php echo $form->labelEx($invoice,'invoice_title'); ?>
<?php echo $form->textField($invoice,'invoice_title', array('size'=>60,'maxlength'=>255)); ?>
<?php echo $form->error($invoice,'invoice_title'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($invoice,'order_no'); ?>
<?php echo $form->textField($invoice,'order_no', array('size'=>60,'maxlength'=>255)); ?>
<?php echo $form->error($invoice,'order_no'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($invoice,'invoice_issue_date'); ?>
<?php $form->widget('zii.widgets.jui.CJuiDatePicker', array(
'model' => $invoice,
'attribute' => 'invoice_issue_date',
'value' => $invoice->invoice_issue_date,
'options' => array(
'showButtonPanel' => false,
'changeYear' => true,
'dateFormat' => 'yy-mm-dd',
),
)); ?>
<?php echo $form->error($invoice,'invoice_issue_date'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($invoice,'due_date'); ?>
<?php $form->widget('zii.widgets.jui.CJuiDatePicker', array(
'model' => $invoice,
'attribute' => 'due_date',
'value' => $invoice->due_date,
'options' => array(
'showButtonPanel' => false,
'changeYear' => true,
'dateFormat' => 'yy-mm-dd',
),
)); ?>
<?php echo $form->error($invoice,'due_date'); ?>
</div>
<div class="row">
<?php echo $form->labelEx($invoice,'description'); ?>
<?php echo $form->textField($invoice,'description', array('size'=>60,'maxlength'=>255)); ?>
<?php echo $form->error($invoice,'description'); ?>
</div>
<div class="row buttons">
<?php echo CHtml::submitButton('Create'); ?>
</div>
<?php $this->endWidget(); ?>
</div><!-- form -->
Have you checked the Yii Autocomplete widget? And you wouldn't have to worry about AJAX implementation. It does it for you.
Yii Framework: CJui AutoComplete
A more customized autocomplete solution in this link.
Yii Framework: custom-autocomplete-display-and-value-submission

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