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I have a question, if in my page I want to search:
- Last 10 registered users
- Last 10 login users
- Last 10 users that have inserted a product
These query are more than one, well in my controller I have to make more query and every query put it into a variable right?
something like that?
$first_query = $this->User->find ('all', array(
'conditions' => array(...)
));
$second_query = $this->User->find ('all', array(
'conditions' => array(...)
));
$third_query = $this->User->find ('all', array(
'conditions' => array(...)
));
And in my view I'll use the variables $first_query, $second_query, $third_query
Is correct or is better to divide into more function on the controller the query?
No, the way you do it is "the" way. You should probably name them differently, though, since the variables do not contain any queries, but results, and "first", "second" etc. says nothing about the content. I'd call them $lastRegisteredUsers, $lastLoggedInUsersetc.
If the conditions are very similar, like if you want to select users from only one category, or some such, you could store that condition in a variable and reuse it, instead of copy-pasting.
You can use the following code in your controller's action method:
You can map the model association with itself. And this will return you the expected result.
$this->User->bindModel(array('belongsTo' => array('LastRegUser' =>
array(
'className' => 'User',
'foreignKey' => 'id',
'conditions' => array(...)),
'LoggedInUser' => array(
'className' => 'User',
'foreignKey' => 'id',
'conditions' => array(...)) ..... )));
And then you can simple use the following code to fetch all the users using following code.
$users = $this->User->find('all');
Related
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I have to use data table with server side scripting. i have met problem when i have null value in database for particular field. I need to show '-' instead of null value then corresponding value from db if not null.my particular line is
array('db' => 'custname',
'dt' => 2,
'formatter' => function($d,$row) {
return($d == '')?'-': 'db' => 'custname';
})
in fixed condition i have used similar without db values its worked. like,
array('db' => 'status',
'dt' => 4,
'formatter' => function($d,$row) {
return($d == 'a')?'Active':'Hold';
})
But when i need db value if data not null i have struggled.Thanks in advance
Try this
array('db' => 'custname',
'dt' => 2,
'formatter' => function($d,$row) {
return(!isset($d))?'-': $d;
})
updated answer because empty would return true for more cases than only null
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I have an array which I am using some method to make an api call. I have 2 methods out of which I need to select 1 based on the session value.
My array looks like this.
$order_params = array(
'username' => 'test1',
'password' => 'test2',
'method' => 'Gateway1');
So if session value is not null than method needs to be Gateway2 and need to pass one more parameter. What I am doing is using this way to update the array.
$order_params = array(
'username' => 'test1',
'password' => 'test2',
'method' => 'Gateway1');
if($_SESSION['userid'] != ''){
$order_params['method'] = 'Gateway2';
$order_params['proid'] = '222'
}
I need to confirm if I am doing the right way, OR if there is a more better way to do this.
I need to confirm if I am doing the right way, OR if there is a more
better way to do this.
This is really hard to say without seeing all of your code, but you can tidy up the code a bit and approach it slightly differently by setting your values in one go:
$order_params = [
'username' => 'test1',
'password' => 'test2',
'method' => $_SESSION['userid'] != '' ? 'Gateway2' : 'Gateway1',
'proid' => $_SESSION['userid'] != '' ? '222' : null,
];
So set it in one go.
method is set to "Gateway2" if you have a userid, else set to the default "Gateway1"
proid is set to "222" if you have a userid, else set to the default empty (just so the array key is set and you don't later need to do if (isset($order_params['proid'])))
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I have an array what consist of arrays. Have a looks into this file gist.
How you can see each array repeats two times. I need to delete the second, I need to compare them by 'key' value of array.
Thanks!
The easiest way to get the result you expect is in my opinion this way:
$data = array(
array(
'domain' => 'messages',
'key' => 'test.testik',
'message' => array()
),
array(
'domain' => 'messages',
'key' => 'test2313.tes31231tik',
'message' => array()
),
array(
'domain' => 'validators',
'key' => 'valid.validik',
'message' => array()
),
array(
'domain' => 'validators',
'key' => 'joga.jimbo',
'message' => array()
),
array(
'domain' => 'validators',
'key' => 'valid.validik',
'message' => array()
)
);
$newdata = array();
foreach ($data as $subdata) {
$newdata[$subdata['key']] = $subdata;
}
$newdata = array_values($newdata); // reset array indizes
print_r($newdata);
The undefined offset 6 error is telling you that there isnt an array element at position 6. Without seeing your error message and your code I cant tell you where the error is But you would need to see if the element exists using something like this:
if (isset($array[index]))
{
//do something
}
This will handle the error, meaning you wont get the message, but you should see why the element doesnt exist, like Was there a problem when the arrays were made.
Your error message will tell you which line the problem was on and therefore which array variables are causing these errors.
UPDATE:
your code will always return true as you are comparing a value to itself therefore it will be an empty array.
$transll['key'] == $transll['key']
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I have a config files which store variable like this:
<?php
return array(
'debug' => true,
'url' => 'http://localhost',
'timezone' => 'UTC',
'locale' => 'en',
);
How can I retrieve it in object oriented way from main file? Thank you.
I'm not quite sure what sort of answer you're expecting when you say "in an object oriented way", but the way I'd do it would be something like the following:
$config = include("configfile.php");
And then you can just access the values like so:
echo $config["timezone"]; //prints "UTC"
i am guessing you wanted to convert this array to an object if so then use this.
<?php
return (object) array(
'debug' => true,
'url' => 'http://localhost',
'timezone' => 'UTC',
'locale' => 'en',
);
in the other page do this:
$config = include("configfile.php");
echo $config->locale;
This is not really a OOP concept, rather a PHP concept
Simply include the file:
$config = include 'config.php';
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I got a problem for a script I'm working on: I need the array that normaly gets generated in the query_person() function to be saved in protected static $users to be used across the script. This is just a quick test I made, normally the array gets generated by a query.
The script works if I do it like this:
protected static $users = array('paul' => array('p_gebruikersnaam' => "paul", 'p_wachtwoord' => "de3c41cc7918c25822f1fb840a86a84b", 'p_id' => "10000000", 'p_md5' => "d1ca3aaf52b41acd68ebb3bf69079bd1")
);
but since the array gets generated by a db query I had to put the query in a function but it doesn't work like this then:
protected static $users = array();
public function query_personen(){
$users = array('paul' => array('p_gebruikersnaam' => "paul", 'p_wachtwoord' => "de3c41cc7918c25822f140a86a84b", 'p_id' => "100000", 'p_md5' => "d1ca3aaf52b41acd68e9079bd1")
);
}
How do I make it work so that the second script generates the same output as the first?
public function query_personen(){
$this->users = array('paul' => array('p_gebruikersnaam' => "paul", 'p_wachtwoord' => "de3c41cc7918c25822f140a86a84b", 'p_id' => "100000", 'p_md5' => "d1ca3aaf52b41acd68e9079bd1")
);
You need to use $this to refer to the object.
If you want it to be static, you should use:
public static function query_personen(){
self::$users = array('paul' => array('p_gebruikersnaam' => "paul", 'p_wachtwoord' => "de3c41cc7918c25822f140a86a84b", 'p_id' => "100000", 'p_md5' => "d1ca3aaf52b41acd68e9079bd1")
);
Note that the second function is a static function (Yours in the example isn't so you should use the first version).