Javascript Multiple Value Call - php

Question

I'm calling a function from an input radio button and have this:
onClick=\"changeBilling('".$results['id']."', this.value)\"
But my this.value isn't working properly. When I look it up in the page, the id is filling properly, but the second value still says this.value, and not the value of the button that is calling the function.
I see this in the browser element manager:
onclick="changeBilling('149', this.value)"
What am I doing wrong?
Radio Button:
<input type='radio' name='billed' value='Yes' onClick=\"changeBilling('".$results['id']."', this.value)\"/> Yes<br /><input type='radio' name='billed' value='No' onClick=\"changebilling('".$results['id']."', this.value)\" checked/> No
Ideal Output:
onclick="changeBilling('149', 'Yes')"

Answer 1

this.value will be evaluate by the client, as its javascrpt, so you will not see the "baked" value in there from your php, you need to check this at runtime, your best bet is to alert the value of this.value and check if it is what you expect, because this is what will be passed to changeBilling
onClick=\"alert('The value is: '+this.value)\"
the issue you may be getting is that this may not be evaluating to the thing you expect it to, to find out (if you have a good debugger like Element inspector (chrome) or firebug (firefox)) will be to put:
onClick=\"console.log(this)\"

Answer 2

Why don't you just output the literal value in your PHP:
echo "<input type='radio' name='billed' value='Yes' onClick=\"changeBilling('".$results['id']."', 'Yes')\"/> Yes<br /><input type='radio' name='billed' value='No' onClick=\"changebilling('".$results['id']."', 'No')\" checked/> No";
EDIT
I'm not entirely sure what you're expecting to happen, but there does not appear to be anything wrong with the code you have written. To demonstrate this point, see this JSFiddle which shows how this.value works (note that this has got nothing to do with PHP).