I'm generating auto incremental code through a PHP script. The sequence goes like this, L001, L002....L039, L040. Below is the PHP code I have written. The comments show the output of each statement.
<?php
require_once("db_handler.php");
$conn = iniCon();
$db = selectDB($conn);
$query = "SELECT LID FROM locations ORDER BY LID DESC LIMIT 1";
$result = mysql_query($query, $conn);
$row = mysql_fetch_array($result);
$last_id = $row['LID']; //L040
$id_letter = substr($last_id, 0, 1); //L
$id_num = substr($last_id, 1) + 1; //040 + 1
$new_id = $id_letter . $id_num;
mysql_close($conn);
?>
I'm displaying the $new_id in a HTML textbox. though everything works fine up to this point, the new generated code shows as L41, cutting off the leading zero.
How can I stop this from happening? I need to have that zero in the front.
Thank you.
Use either str_pad or sprintf function:
$id_num = str_pad($id_num, 3, "0", STR_PAD_LEFT);
or
$id_num = sprintf("%03d", $id_num);
$id_num = substr($last_id, 1) + 1; //40 + 1
$id_num = str_pad($id_num, 3, "0", STR_PAD_LEFT); //return 041
$new_id = $id_letter . $id_num;
take a look at sprintf[1]. hint: %03d
[1] http://br2.php.net/sprintf
Related
In my php code, while inserting new record, invoice number should be 0001. Here I want to add characters/a word(for example 'optical') and it should be like optical0001. How can I add this before the number?
$query = "select * from cust_report_invoices order by invoiceID desc limit 1";
$result = $link->query($query);
$row = $result->fetch_assoc();
$invoiceNo = $row['invoiceNo'];
$prefix = 'Baopt_';
$getinvoiceNo = $prefix . str_pad($invoiceNo + 1, 4, 0, STR_PAD_LEFT);
$sql = "INSERT INTO cust_report_invoices (invoiceNo,invoiceDate)
VALUES ('$getinvoiceNo', '$getinvoiceDate' )";
str_pad return string (doc). So just concat with .:
$prefix = 'optical';
$invoice = $prefix . str_pad($invoiceNo + 1, 4, 0, STR_PAD_LEFT);
Edit
When adding new element you need to cut the prefix out - you can use this:
$prefix = 'Baopt_';
$invoiceNo = $row['invoiceNo'];
if (substr($invoiceNo, 0, strlen($prefix)) == $prefix) // if already has prefix
$invoiceNo = substr($invoiceNo, strlen($prefix)); // remove it
$getinvoiceNo = $prefix . str_pad($invoiceNo + 1, 4, 0, STR_PAD_LEFT);
When working in PHP you can use the . as concatenation-operator. I see that you use the function str_pad that returns as string.
So you can just concat the prefix with the invoice number like this.
$prefix = 'optical';
$invoice = $prefix . str_pad($invoiceNo + 1, 4, 0, STR_PAD_LEFT);
$prefix can be anything you want.
When invoice = 0001 this example will return optical0001
Just "Opticals".$getinvoiceNo
Dot is concatenating strings.
Not sure if I understand correctly, you want to prepend "optical" to $getinvoiceNo?
If yes then it is simple,
invoiceId = "optical$getinvoiceNo"
I have the code from the database, the data should appear automatically in sequence. the code is composed of text and number like this CO-00001 but when I generate the code it just adds one digit in the back but not add the value of example CO-00001 to CO-000001 how to solve it?
ex :
$id = 0902340
$query = "SELECT substr(code_id,3,5) as cd FROM tb_inv WHERE substr(code_id,3,5) = '".$id."' ORDER BY code_id DESC LIMIT 1";
$get_id = $this->db->query($query);
$show_id = $get_id->num_rows();
$new_code = $get_id->row();
if($show_id > 0){
$new = $new_code->cd + 1;
$fix_code = $new;
}else{
$fix_code = 'CO-00001';
}
you can't do algebra on alphabets, therefore you need to split the alphabets and the numerics like so:
$id = 0902340
$query = "SELECT substr(code_id,3,5) as cd FROM tb_inv WHERE substr(code_id,3,5) = '".$id."' ORDER BY code_id DESC LIMIT 1";
$get_id = $this->db->query($query);
$show_id = $get_id->num_rows();
$new_code = $get_id->row();
if($show_id > 0){
$prefix = substr($new_code->cd, 0, 3); // get the prefix 3 chars at front
$number = substr($new_code->cd, 3); // get the remaining chars
$new = $number + 1; // add it with 1, php automatically convert strings that can be converted to numbers
$fix_code = $prefix . substr("00000" . $number, -5); // re-assemble the code
}else{
$fix_code = 'CO-00001';
}
you can split the id into two parts, the string one, and the digit one. then increment the digit part then re concat the two parts again
list($strPrefix, $digitPart) = split('-', $oldId);
$digitPart++;
$newCode = $strPrefix . '-' . $digitPart;
I would like to sum 2 values, like 3,07 + 5.1 and I am getting result 8,10 €, not 8,17 €. What am I doing wrong?
<?php
$rezultat = "SELECT sum(value) as value FROM values";
$result = mysqli_query($link, $res) or die (mysqli_error($link));
$sum= mysqli_fetch_object($result);
echo number_format($sum->value, 2, ",", "");
mysqli_close($link);
?>
it seems a decimal separator issue. try replace "," by "." like this:
echo number_format($sum->value, 2, ".", "");
number_format(number,decimals,decimalpoint,separator)
see: http://www.w3schools.com/php/func_string_number_format.asp
This works for me:
$kategorija = mysqli_real_escape_string($link, $_POST['kategorija']);
$vrednost = number_format(str_replace("#", ".", preg_replace("/[^0-9#]/i", "", preg_replace("/[\.\,](?!.*[\.\,])/i", "#", $_POST['kolicina']))), 2, ".", "");
$vrednost = mysqli_real_escape_string($link, $vrednost);
I have a field (demo_field)(varchar) in mysql table. I want to increment this field value with a pre defined prefix.
For example my field first value is demo001. Now when ever new values inserted I want to increment the numeric numbers like demo002, demo003.
How can I do this with PHP.
try this -
//fetch data from table
$sql = $mysqli->query('select count(demo_field) as total,demo_field from tablename limit 1');
$res = $sql->fetch_assoc();
//generate string from existing data
$str = substr($res['demo_field'], 0, 4);
$dig = str_replace($str, '', $res['demo_field']);
$dig = $dig+$res['total'];
//add padding if needed
$dig = str_pad($dig, 3, '0', STR_PAD_LEFT);
//concatenate string & digits
$newStr = $str.$dig;
var_dump($newStr);
Another way without count
$sql = $mysqli->query('select max(demo_field) as demo_field from demo');
$res = $sql->fetch_assoc();
$str = substr($res['demo_field'], 0, 4);
$dig = str_replace($str, '', $res['demo_field']);
$dig += 1;
$dig = str_pad($dig, 3, '0', STR_PAD_LEFT);
$newStr = $str.$dig;
var_dump($newStr);
hope this might solve the problem with count.
another solution with max count for alphanumeric string and without padding -
$sql = $mysqli->query('select max(cast(substring(demo_field, 5) as unsigned)) as digit, demo_field from demo');
$res = $sql->fetch_assoc();
$str = substr($res['demo_field'], 0, 4);
$dig = $res['digit'] + 1;
$newStr = $str.$dig;
var_dump($newStr);
//use PHP not mysql
$pre = 'demo';
$num = 0;
define('MAX', 100);
for($num = 0; $num < MAX; $num++)
{
$pre_str = $pre . sprintf("%03d", $num);
//insert here
}
you have to use an INT field
and translate it to whatever format you want at "select" time.
In MySQL we cannot use AutoIncrement for Varchar.
how to set if price row is comming soon than show update soon
how to set if price row is comming soon than show update soon
mysql
<?
//connect to database
mysql_connect('localhost','phone','pasword');
mysql_select_db('phone');
//////Displaying Data/////////////
$id=$_GET['id']; // Collecting data from query string
if(!is_numeric($id)){ // Checking data it is a number or not
echo "Data Error";
exit;
}
$result = mysql_query("SET NAMES utf8"); //the main trick
$q=mysql_query("select * from price where id=$id AND TRIM(model) IS NOT NULL");
//Adds one to the counter
mysql_query("UPDATE price SET counter = counter + 1 where id=$id ");
//Retreives the current count
$count = mysql_fetch_row(mysql_query("SELECT counter FROM price"));
$row=mysql_fetch_object($q);
echo mysql_error();
echo "<table class='hovertable'><tr><td><img src='admin/media/$row->photo' ></td></tr>";
echo "</table>";
?>
example
my rows
2000
3000
comming soon
4900
and this code is showing like this
2000
2000
3000
Warning: number_format() expects parameter 1 to be double, string given in
4900
and i want like this
2000
2000
3000
update soon
4900
how to solve this problem please help me to solve this issue
<?php if($row->price):?><tr class=\"style1\"><td width='200'><b>Price US $:</b></td><td>Price in Dollar:
<?php
function currencyExchange($amount,$baseCurrency,$quoteCurrency) {
$open = fopen("http://quote.yahoo.com/d/quotes.csv?s=$baseCurrency[0]$quoteCurrency[0]=X&f=sl1d1t1c1ohgv&e=.csv", "r");
$exchangeRate = fread($open, 2000);
fclose($open);
$exchangeRate = str_replace("\"", "", $exchangeRate);
$exchangeRate = explode(",", $exchangeRate);
$results = ($exchangeRate[1]*$amount);
$results = number_format ($results, 2);
$amount = number_format ($amount);
$timeStamp = strtotime($exchangeRate[2]);
$timeStamp = date('F d, Y', $timeStamp);
$timeStamp = "$timeStamp $exchangeRate[3]";
echo "$results\n";
}
// for additional currency ticker symbols visit: http://finance.yahoo.com/currency-converter
$usd = array('USD','US Dollars');
$INR = array('INR','Indian Rupees');
$usd = array('usd','US DOLLARS');
$b = str_replace( ',', '', $row->price );
if( is_numeric( $b ) ) {
$row->price = $b;
}
currencyExchange("$b",$INR,$usd);
?></td></tr><?php endif; ?>
Test if the amount is numeric before trying to use functions that only work for numbers.
Replace:
$results = ($exchangeRate[1]*$amount);
$results = number_format ($results, 2);
$amount = number_format ($amount);
with:
if (is_numeric($amount)) {
$results = ($exchangeRate[1]*$amount);
$results = number_format ($results, 2);
} else {
$results = 'update soon';
}
You don't need to call number_format() on $amount because you never print that value.
What about setting the column to something like 9999999999 ( which will get around numbers problem ) then testing the incoming for these numbers and if found then echo coming soon