How to retrieve complete URL from address bar using PHP? [duplicate] - php

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Closed 10 years ago.
Possible Duplicate:
How to get full URL on the address bar using PHP
I use this function, but it does not work all the time. Can anyone give a hint?
function sofa_get_uri() {
$host = $_SERVER['SERVER_NAME'];
$self = $_SERVER["REQUEST_URI"];
$query = !empty($_SERVER['QUERY_STRING']) ? $_SERVER['QUERY_STRING'] : null;
$ref = !empty($query) ? "http://$host$self?$query" : "http://$host$self";
return $ref;
}
I want to retrieve the link in address bar (exactly) to use it to refer user back when he sign out. The urls are different:
http://domain.com/sample/address/?arg=bla
http://domain.com/?show=bla&act=bla&view=bla
http://domain.com/nice/permalinks/setup
But I can't get a function that works on all cases and give me the true referrer.
Hint please.

Answer 1

How about this?
function getAddress() {
$protocol = $_SERVER['HTTPS'] == 'on' ? 'https' : 'http';
return $protocol.'://'.$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI'];
}
echo getAddress();

Answer 2

You could use functions above to retrieve URL till GET parameters.
So You have string like = 'localhost/site/tmp' (example).
After that you could just loop through GET parameters if can't get anything else to work.
Add '?' at the end of string manually.
$str = 'localhost/site/tmp/?'
foreach ($_GET as $key => $value) {
$str .= $key.'='.$value.'&';
}
substr_replace($str, "", -1);
echo $str;
At the end You are deleting last symbol which is '&' and is not needed.