How to do + or - in php? - php

I want to have a form in following way:
[-] [value] [+]
I don't know how to script the logic to get the value 1 higher or 1 lower in PHP.
I assumed something like following would work:
<?php
$i = 0;
if($_SERVER['REQUEST_METHOD'] == 'POST')
{
if(isset($_POST['plus']))
{
$i++;
}
if(isset($_POST['min']))
{
$i--;
}
}
?>
and my form is as following:
<form action="" method="post">
<input type="submit" name="min" value="-"> <input type="text" value=<?php echo $i ?> > <input type="submit" name="plus" value="+">
</form>
But I'm only getting either a 1 or a -1. Can someone show me how to do this in a good way?

Try this:
<?php
if($_SERVER['REQUEST_METHOD'] == 'POST')
{
$i = $_POST['current_value'] || 1;
if(isset($_POST['plus']))
{
$i++;
}
if(isset($_POST['min']))
{
$i--;
}
}
?>
and this:
<form action="" method="post">
<input type="submit" name="min" value="-"> <input name="current_value" type="text" value=<?php echo $i ?> > <input type="submit" name="plus" value="+">
</form>
You need some way to get the current value to persist between requests - depending on your use case, you may need database storage as Rocket mentions, or this simple passing back of the current value may be enough.

PHP will simply load code on the server-side and run when the page is loaded. If you are looking to dynamically increment/decrement the value while remaining on the same page, I suggest you look into learning Javascript and jQuery.
Reference: https://developer.mozilla.org/en/JavaScript/
Reference: http://jQuery.com/

What is happening with your code is that you are incrementing a global variable that you set to 0 in the beginning. That is why the only values you get back or 1 or -1. This can be fixed by passing the variable you increment each time instead of using a global variable. That way it keeps the value between each plus and minus and doesn't keep resetting it.

Related

Form Inputs and PHP

Need a little help with my coding. I'm working on a project in which it will accept 5 different numbers and insert them into a PHP array. The codes I have tried are written below. Both of them would make all the 5 contents of my array the same number, appreciate a little help please? Never dealt with array in PHP yet.
<form action="activity_1.php" method="post">
<input type="text" name="number">
<input type="submit" value="Submit" name="submit">
</form>
So far these are the ones I've tried:
$no = array();
for($i=1; $i<=5; $i++){
array_push($no, $_POST['number']);
}
Also
$no = array();
for($i=1; $i<=5; $i++){
//$no[$i]= $_POST['number'];
}
You may use one session variable to store the posted data.
So slightly amend your code into the following :
<?php session_start(); ?>
<form action="#" method="post">
<input type="text" name="number">
<input type="submit" value="Submit" name="submit">
</form>
<?php
if ( !isset($_SESSION["no"]) ) {
$_SESSION["no"]=array();
}
if (isset($_POST["number"])){
array_push($_SESSION["no"], $_POST['number']);
}
for($i=0; $i<5; $i++){
if (isset($_SESSION["no"][$i])) {
if ($_SESSION["no"][$i]!="") {
echo " Number you entered was: " .$_SESSION["no"][$i] . "<br>";
}
}
}
?>
In my opinion the code can be further amended so that
a) you should have a button to "clear" all the previous entered number;
b) I don't know whether it is necessary, but you may wish to add a function to check whether a newly entered number is the same as one of the past numbers entered, and if they are the same, do not put it into the array.

First element in array keeps getting overwritten, will not add onto array

I am trying to create a quiz, in order to do this I am using a form which users will input information into, once they submit this form it should add the input to an array/list.
The user should then be able to enter information and the process would repeat.
The finished product would be an array with each element corresponding to the order the answers were given.
-
I have tried so far using both array_push() and declaring elements, eg: $my_array[0] = $input;.
The current problem I am experiencing is that each time I submit the form, the $count variable doesn't seem to increment.
Instead it simply stores the data in the first element and overwrites which was previously there.
I am inclined to believe this is a problem with the posting of the submit button.
-
Here is my code:
<html>
<body>
<form action="" method="POST">
<input type="text" name="INPUT" placeholder="Input something"; required /><br><br>
<input type="submit" name="Submit" /><br><br>
<?PHP
$my_array = array();
$count = 0;
if(isset($_POST['Submit'])){
global $count;
$input = $_POST['INPUT'];
$my_array[$count] = $input;
print_r($my_array);
echo "Count:" . $count;
$count++;
}
?>
</form>
</body>
</html>
The crux of the issue here is that variable values do not persist across PHP requests. Every time you submit the form, you are throwing away your old $count and $my_array variables and initializing new variables with the same names.
Here is a working version of your code snippet, which takes advantage of the PHP $_SESSION variable to have persistent information between requests:
<?php
session_start();
if (!isset($_SESSION["my_array"])) {
$_SESSION["my_array"] = array();
}
?>
<html>
<body>
<form action="" method="POST">
<input type="text" name="INPUT" placeholder="Input something"; required /><br><br>
<input type="submit" name="Submit" /><br><br>
<?php
if(isset($_POST['Submit'])){
array_push($_SESSION["my_array"], $_POST['INPUT']);
print_r($_SESSION["my_array"]);
echo "Count:" . count($_SESSION["my_array"]);
}
?>
</form>
</body>
</html>

Can't use a form's value in a different php file

Having issues with using a form's value in a different php file:
my firstpage.php
<form method="post">
<input type="radio" name="rdbbtn" value="1"> One
<input type="radio" name="rdbbtn" value="2"> Two
</form>
my secondpage.php is here
<?php
include("firstpage.php");
$result = $_POST['rdbbtn'];
if ($result == "1") {
echo 'thirdpage.php';
}
else {
echo 'fourthpage.php';
}
?>
problem:
Notice: Undefined index: rdbbtn in
how come I can't use "rdbbtn"? Should I have something like
$rdbbtn = $_POST['rdbbtn'];
in secondpage.php? Tried this but didn't solve my problem.
firstpage.php and secondpage.php are in the same directory.
Probably it's some pretty obvious thing that I don't see...thanks!
EDIT: I have accepted pradeep's answer as that helped me the most to figure what the problem should be. would like to say thank you for everybody else showing up here and trying to help!
When you change current page it reset the value and $_POST is empty.
You can try with set form action to next page . It will work
<form method="post" action="secondpage.php">
<input type="radio" name="rdbbtn" value="1"> One
<input type="radio" name="rdbbtn" value="2"> Two
<input type="submit" name="" value="Next">
</form>
Other wise you can make a function in a class and set each page action
to this function.
And set your each form data to session.
Finally when you change the page you read data form session.
Class FormAction{
public function setFormDataToSession(){
if(isset($_POST['rdbbtn']){
$_SESSION['rdbbtn'] = $_POST['rdbbtn'];
}
}
}
In your page simply get the session value.
echo $_SESSION['rdbbtn'];
Should be like this :
Check with isset method in
<?php
include("firstpage.php");
$result = isset($_POST['rdbbtn']) ? $_POST['rdbbtn'] : NULL;
if ($result == 1) {
echo 'thirdpage.php';
}
else {
echo 'fourthpage.php';
}
?>
and your form should be like this :
<form method="post">
<input type="radio" name="rdbbtn" value="1"> One
<input type="radio" name="rdbbtn" value="2"> Two
<input type="submit" name="submit" value="submit">
</form>
Sorry for not being able to comment in this post(less reputations). But seems like you are asking about storing the variables of the session. This way you can use the variables for a whole session. Just start the session by putting session_start() in the very beginning of secondpage.php file and then you can access the variables at any time during the session by simply calling $_SESSION['rdbutton] in any page like fourthpage.php or anything. Just make sure u put the session_start() at the top of each page where you want to use the variables. Don't forget the semicolons at the end. 😜 Hope this helps.

Trying PHP IF Else Statements for the first time

I'm learning PHP and trying to understand the if .. else statements a little better, so I'm creating a little quiz. However, I have come across an issue and I don't seem to know what the issue is. My problem is that whenever I type in the age in the input area, it will give me the $yes variable every time even if I enter the wrong age.
Here is my code so far:
My html file:
<form action="questions.php" method="post">
<p>How old is Kenny?<input></input>
<input type="submit" name="age" value="Submit"/>
</p></form>
My php file:
<?php
$age = 25;
$yes = "Awesome! Congrats!";
$no = "haha try again";
if ($age == 25){
echo "$yes";
}else{
echo "$no";
}
?>
You catch the user input inside the $_POST superglobal var (because the method of your form is POST.
So
<?php
$age = 25;
should be
<?php
$age = $_POST['age'];
There is an error in HTML too. This
<input type="submit" name="age" value="Submit"/>
should be
<input type="text" name="age" value=""/>
<input type="submit" value="Click to submit"/>
Because you want one input and one button. So one html element for each element.
and <input></input> must be cleared because it's not valid syntax :-)
<form action="questions.php" method="post">
<p>How old is Kenny?</p><input type="text" name="age"></input>
<input type="submit" value="Submit"/>
</form>
$age = (int) $_POST["age"];
$yes = "Awesome! Congrats!";
$no = "haha try again";
if ($age == 25) {
echo $yes;
} else {
echo $no;
}
<?php
/* Test that the request is made via POST and that the age has been submitted too */
if( $_SERVER['REQUEST_METHOD']=='POST' && isset( $_POST['age'] ) ){
/*
ensure the age is an integer rather than a string ..
though for this not overly important
*/
$age=intval( $_POST['age'] );
if( $age==25 ) echo "Congratulations";
else echo "Bad luck!";
}
?>
<form action="questions.php" method="post">
<p>How old is Kenny?
<input type='text' name='age' placeholder='eg: 16' />
<input type="submit" value="Submit" />
</p>
</form>
A simple html form, note that the submit button does not carry the values you want to process, they are supplied via the input text element.
First of all, you need to echo the variable; echoing "$no" will keep it as a string. Remove the quotes from "$no" and "$yes" in your if then statement. Otherwise, your code seems sound!

keep adding value in php

Initially,the $number = 0. After 1st time clicking Add button, the value becomes 10. When 2nd time clicking, the value is changed to 20. then 3rd time is 30, 4th time 40.
Below is my code, is there anyone know how to fix it? Thanks!
<?php
$number = 0;
if(isset($_POST['add'])){
$number = $number +10;
}
?>
<html>
<head>
</head>
<body>
<form method="post" action="<?php echo $_SERVER['SCRIPT_NAME']; ?>">
<?php echo $number; ?>
<input type="submit" name="add" value="Add" />
</form>
</body>
</html>
<input type="hidden" value="<?php echo $number ?>" name="number" />
Now change the $_POST['add'] to $_POST['number']
And $number = $_POST['number'] + 10;
This is fundamental to how PHP works.
There is no 'state' in between requests. This means that everything will be forgotten for every request. So if you want to retain data, you have to store it somewhere.
A couple of options:
A database such as MySQL
A session
A cookie
A caching system such as APC
First of all, your PHP needs a little adjusting:
<?php
$number = ($_POST['add'] != '') ? 0 : $_POST['add'];
$number += 10;
?>
<html>
Then add a hidden input above the <input type="submit">, like so:
<input type="hidden" name="add" value="<?php echo $number; ?>">
Use the session variable to retain the value per page request. Simple variable values is destroyed once script finish execution. Session variable will keep the value.
Read more about session
or use the database.
You need to save the value somehow. Either you use a database, like MySql, or you could save the value in a session variable.

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