PHP - Multiple MySQL result, in separate variables - php

Question

I need to do a MySQL query to search for an inexact match / match containing the submitted value.
The following is an example of what is in my database:
id img
1 1001_ABC_01.jpg
2 1001_ABC_02.jpg
3 1002_ABC_01.jpg
4 1002_ABC_02.jpg
5 1002_ABC_03.jpg
6 1002_ABC_04.jpg
7 1002_ABC_05.jpg
8 1003_ABC_01.jpg
9 1003_ABC_02.jpg
10 1003_ABC_03.jpg
I need the query to search for the first part of the filename (1002) and and assign each returned result in the img field a different variable. The maximum amount of variables would be 5.
For example, if I search 1002, it should assign the following variables:
<?php
$img1 = '1002_ABC_01.jpg';
$img2 = '1002_ABC_02.jpg';
$img3 = '1002_ABC_03.jpg';
$img4 = '1002_ABC_04.jpg';
$img5 = '1002_ABC_05.jpg';
?>
so that way I can echo each filename result individually.
Again, the maximum amount of variables here will be 5, so if more than 5 results are returned, only the first 5 will be assigned variables.
Please let me know if this is possible and how to write a PHP script to do it.

Answer 1

SELECT img FROM <table_name> WHERE img LIKE '%search%' ORDER BY ID DESC LIMIT 5;
You could substring function, if the first four integers are fixed like this:
select substring(img,1,4) from <table_name> where img = 'search' order by ID DESC limit 5;

Answer 2

I hope this will help you. Always try to use latest apis and function like MySqli try to avoid mysql_* functions because they are depreciated and MySqli is also faster then mysql_ functions
$img = '1002'; // For example
$connection = new Mysqli(host, user, password, database);
$sql = "SELECT img FROM <table_name> WHERE img LIKE '$img%' LIMIT 5";
if($connection->query($sql)){
$counter = 1;
while ($row = $connection->fetch_object()){
${'img'.$counter} = $row->img;
$counter++;
}
}

Answer 3

$query = "SELECT * FROM my_table WHERE img_name LIKE '%1002%' LIMIT 5";
foreach ( $fetched_row as $value ) {
echo $value [ 'img_name' ]; // or whatever you want to do
}
Something like that.

Answer 4

Use this query
SELECT img as IMG
FROM my_table
WHERE img LIKE '1002%'
order by id desc
LIMIT 5

Answer 5

<?php
$query="SELECT id,img as image FROM image_table
where img like '%$keyword%' limit 5";
$res=mysql_query($query) or die(mysql_error());
while ($img = mysql_fetch_array($res)) {
echo $img['image'];
}
?>

Answer 6

$con = new Mysqli(host, user, password, database);
$result = $con->query("SELECT * FROM table WHERE image LIKE %$search% ORDER BY id DESC LIMIT 5");
if($result){
while ($row = $con->fetch_object()){
$img_arr[] = $row;
}
}

Answer 7

I hope this will help you.
$queryStr = "SELECT img FROM table_name WHERE search_str LIKE '1002%'";
$query = mysql_query($queryStr);
while($row = mysql_fetch_assoc($query)){
$imageArray[] = $row;
}
// Print the array
echo '<pre>';
print_r($imageArray);
echo '</pre>';
// How to use the array
foreach($imageArray as $key=>$val){
echo 'File Name: '.$val;
echo '<br />';
echo '<img src="'.$val.'" />';
echo '<hr />';
}
// Now show first five result
// Alternet: You can use LIMIT and order by with mysql
// With php
for($i=0;$i<5;$i++){
echo 'File Name: '.$imageArray[$i];
echo '<br />';
echo '<img src="'.$imageArray[$i].'" />';
echo '<hr />';
}

Answer 8

To search for a partial match you can use the LIKE operator in SQL. In this case you could write:
$sql = "SELECT img FROM tablename WHERE img like '1002%'";
How to perform this query and obtain the results in PHP depends on the database API you are using: old MySQL? MySQLi? PDO? Also, 1002 is probably user input, in which case you have to protect your program against SQL injection attacks.
As to the second part, are you sure you want different variable names and not an array? Arrays are much easier to use. You can get different variable names if you first accumulate the data in an array and then use extract:
$result = array();
$counter = 1;
$rs = mysql_query($sql); // using old mysql API
while ($row = mysql_fetch_array($rs)) {
$result["img".$counter] = $row[0];
$counter = $counter + 1;
}
extract($result);
// now $img1, $img2, $img3, ... are defined

Answer 9

your code will look like this:
$input = '1002'; // For example
$query = "SELECT id, img FROM table_blah WHERE img LIKE '$input%' LIMIT 5";
This query is basically selecting id, and img from the table table_blah, and img must be the same as 1002, and % meaning absolutely anything from there on. Limited to 5 results.
Then:
$result = mysql_query($query);
while ($row = mysql_fetch_array($result)) {
// Code for each result here.
// id = $row['id']
// img = $row['img']
}

Answer 10

$query = "SELECT * FROM img_table WHERE img_name regexp concat('1002', '%')"
$results = mysql_query($query);
then $results is an array of img strings