Php foreach echo issue - php

Question

I have this code which produces me a number which is equal to the number of id's i've got in my database of star rating system.
This code generates me a five star voting for each id i've got, but the problem is, it generates them all in a div, while i need them specifically in different div's. let's suppose i print out in a div information for each hostess i've got, i print out their photo and name with the following code:
$sql =" select * from hostess";
$query = mysql_query($sql);
while ($row = mysql_fetch_array($query)) {
echo "<div id='photo'>";
echo "<div id='picture'>";
echo "<div id='scotch'><img src='images/Scotch.png'></div>";
echo "<td> <img src=foto/photo1/".$row['photo'] . "></td>";
echo "</div>";
echo "<div id='text'>";
echo '<td>'. $row['first_name_en']." ". $row['family_name_en']."</td>";
echo "</div>";
echo "</div>";
echo "<div id='photo2'>";
echo "<div id='picture'>";
echo "<div id='notes'>";
echo '<form action="index.php" method="post" >';
echo "<label>Notes</label></br><textarea>".$row['courrent_occupation'] . "</textarea></br>";
echo '<input type="submit" value="edit" name="edit"></div>';
echo "</div>";
echo "<div id='notes'>";
echo "<label>profile</label></br><textarea>".$row['profile_en'] . "</textarea>";
echo "</div>";
echo "</div>";
}
?>
</div>
Now, i've got this other php which generates me all the star ratings for all hostess id's
<?php
// include update.php
include_once 'update.php';
// get all data from tabel
$arr_star = fetchStar();
?>
<?php
// start looping datas
foreach($arr_star as $star){ ?>
<h2>Star Rater - <?php echo $star['id'];?></h2>
<ul class='star-rating' id="star-rating-<?php echo $star['id'];?>">
<?php /* getRating($id) is to generate current rating */?>
<li class="current-rating" id="current-rating-<?php echo $star['id'];?>" style="width:<?php echo getRating($star['id'])?>%"><!-- will show current rating --></li>
<?php
/* we need to generate 'id' for star rating.. this 'id' will identify which data to execute */
/* we will pass it in ajax later */
?>
<span class="ratelinks" id="<?php echo $star['id'];?>">
<li>1</li>
<li>1.5</li>
<li>2</li>
<li>2.5</li>
<li>3</li>
<li>3.5</li>
<li>4</li>
<li>4.5</li>
<li>5</li>
</span>
</ul>
<?php } ?>
What i need is to assign each hostess profile i print their system rating.
I try to insert the foreach inside the first script but it then shows me just one profile, not all profiles.
The fetchstar() code is:
function fetchStar(){
$sql = "select * from `hostess`";
$result=#mysql_query($sql);
while($rs = #mysql_fetch_array($result,MYSQL_ASSOC)){
$arr_data[] = $rs;
}
return $arr_data;
}

Answer 1

First, you probably shouldn't use SELECT *. That aside I would combine the two queries you have to return a multidimensional array with MySQL and then use nested for each loops to echo out the data you want.
Someone answered a similar question for me here.
Looping through MySQL left join in php vs. 2 separate queries
$sql =" select * from hostess";
$query = mysql_query($sql);
while ($row = mysql_fetch_array($query)) {
if ($lastID <> $row['id']) {
$lastID = $row['id'];
$hostess[$lastID] = array('id' => $row['id'],
'first_name_en' => $row['first_name_en'],
etc
'arr_star' => array() );
}
$hostess[$lastID]['arr_star'][] = array('star_id' => $row['star_id'] etc);
}
Then you would use nested for each statements
for each($row as $rows){
//echo your hostess information
for each ($arr_star as $star){
//echo your star rating information
}
}