This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
Strip All Urls From A Mixed String ( php )
i need a way to remove url strings from var but not with finding the . then remove it. no, i need it by finding http and finding .com or .net or .info then remove the whole link
here is my previoys code
function cleaner($url) {
$U = explode(' ',$url);
$W =array();
foreach ($U as $k => $u) {
if (stristr($u,'http') || (count(explode('.',$u)) > 1)) {
unset($U[$k]);
return cleaner( implode(' ',$U));
}
}
return implode(' ',$U);
}
$url = "$first";
but that one remove the . not .com
You can use preg_match method to catch the stuff between http and .com
preg_match('%^((https?://)|(www\.))([a-z0-9-].?)+(:[0-9]+)?(/.*)?$%i', $url);
I think the simplest way to accomplish this but not error free is:
$url="http://codepad.org/";
$arry=explode(".",$url);
$arry1= explode("//",$arry[0]);
echo $arry1[1];
Related
This question already has answers here:
Extracting the last segment on an URI
(4 answers)
Closed 6 years ago.
I have a URL like http://localhost/m/2016/05/05/sebut-gubernur.
If link is clicked, I want get sebut-gubernur.
The $_SERVER variable helps your. and also explode function.
$part = explode("/", urldecode($_SERVER['REQUEST_URI']));
echo $part[(count($part) - 1)]; //sebut-gubernur
Note: You also need .htaccess code for this kind of url.
OR
If you have the link as a string and want to get sebut-gubernur then try:
$link = 'http://localhost/m/2016/05/05/sebut-gubernur';
$part = explode("/", urldecode($link));
echo $part[(count($part) - 1)]; //sebut-gubernur
echo substr($url, strrpos($url, '/') + 1);
This question already has answers here:
My regex is matching too much. How do I make it stop? [duplicate]
(5 answers)
Closed 2 years ago.
I have to modify an URL like this:
$string = "/st:1/sc:RsrlYQhSQvs=/fp:1/g:3/start:2015-07-01/end:2015-07-30";
Namely, I want to delete st:1 with a regex. I used:
preg_replace("/\/st:(.*)\//",'',$string)
but I got
end:2015-07-30
while I would like to get:
/sc:RsrlYQhSQvs=/fp:1/g:3/start:2015-07-01/end:2015-07-30
Same if I would like to delete fp:1.
You can use:
$string = preg_replace('~/st:[^/]*~','',$string);
[^/]* will only match till next /
You are using greedy matching with . that matches any character.
Use a more restricted pattern:
preg_replace("/\/st:[^\/]*/",'',$string)
The [^\/]* negated character class only matches 0 or more characters other than /.
Another solution would be to use lazy matching with *? quantifier, but it is not that efficient as with the negated character class.
FULL REGEX EXPLANATION:
\/st: - literal /st:
[^\/]* - 0 or more characters other than /.
You need to add ? in your regex:-
<?php
$string = "/st:1/sc:RsrlYQhSQvs=/fp:1/g:3/start:2015-07-01/end:2015-07-30";
echo preg_replace("/\/st:(.*?)\//",'',$string)
?>
Output:- https://eval.in/397658
Based on this same you can do for next things also.
Instead of using regex here you should make parsing utility functions for your special format string, they are simple, they don't take to long to write and they will make your life a lot easier:
function readPath($path) {
$parameters = array();
foreach(explode('/', $path) as $piece) {
// Here we make sure we have something
if ($piece == "") {
continue;
}
// This here is just a fancy way of splitting the array returned
// into two variables.
list($key, $value) = explode(':', $piece);
$parameters[$key] = $value;
}
return $parameters;
}
function writePath($parameters) {
$path = "";
foreach($parameters as $key => $value) {
$path .= "/" . implode(":", array($key, $value));
}
return $path;
}
Now you can just work on it as a php array, in this case you would go:
$parameters = readPath($string);
unset($parameters['st']);
$string = writePath($parameters);
This makes for much more readable and reusable code, additionally since most of the time you are dealing with only slight variations of this format you can just change the delimiters each time or even abstract these functions to using different delimiters.
Another way to deal with this is to convert the string to conform to a normal path query, using something like:
function readPath($path) {
return parse_str(strtr($path, "/:", "&="));
}
In your case though since you are using the "=" character in a url you would also need to url encode each value so as to not conflict with the format, this would involve similarly structured code to above though.
This question already has answers here:
Search in array with relevance
(5 answers)
Closed 9 years ago.
I am trying to search an array for a list of words(areas).
But sometime the word(area) in the array is 2 words.
i.e in the array is "Milton Keynes" so "Milton" is not being matched
Is there any way i can do this, without splitting any double words in the array (as i assume this will be a big load on the server)
Below is an example of what i am doing
foreach (preg_split("/(\s)|(\/)|(\W)/", $words) as $word){
if (in_array($word, $areaArray)){
$AreaID[] = array_search($word, $areaArray);
}
}
Grateful, as always for any advice!
You could use preg_grep():
$re = sprintf('/\b%s\b/', preg_quote($search, '/'));
// ...
if (preg_grep($re, $areaArray)) {
// we have a match
}
You can opt to make the match case insensitive by adding the /i modifier.
You can use regular expression to find a value, this will work similar to MySQL like function
$search='Milton Keynes';
foreach ($areaArray as $key => $value) {
if (preg_match('~'.preg_quote($search).'~i',$value)) {
echo "$key";
}
}
This question already has answers here:
Extract domain from url (including the hard ones) [duplicate]
(3 answers)
Closed 9 years ago.
I want to get the domain extension from the url. eg. .com, .net etc.
I have used this:
$extension = pathinfo($_SERVER['SERVER_NAME'], PATHINFO_EXTENSION);
I was just wondering if there was a better way using parse_url?
Use parse_url(). Something like:
$host = parse_url('http://www.google.co.uk/test.html');
preg_match('/(.*?)((\.co)?.[a-z]{2,4})$/i', $host['host'], $m);
$ext = isset($m[2]) ? $m[2]: '';
Edit: Fixed with regex from this answer. Extension like .co.uk are supported too.
You can easily split the requested URI like this:
function tld( $uri ) {
$parts = explode('.', $uri);
return (sizeof($parts) ? ('.' . end($parts)) : false;
}
So you can do this:
if(!tld('googlecom')) // does not contain an ending TLD
if(tld('google.com')) // this is a valid domain name; output: ".com"
Or you can just use:
echo $_SERVER['SERVER_NAME'];
So in my oppinion the most best example of usage is:
echo tld($_SERVER['SERVER_NAME']);
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
Parsing Domain From URL In PHP
How do I parse a URL in PHP?
I have this code:
$url = preg_replace("/^(http:\/\/)*(www.)*/is", "", $url);
$url = preg_replace("/\/.*$/is" , "" ,$url);
It work good get domain name where after .com is / . I got problem if there is url like this:
http://www.something.com?id=21213
What do I need to add to regex to cut ?id=21213 so there remains only something.com
See the magical build in function of parse_url().
Using parse_url(), you can retrieve the domain name solely by:
$domain = parse_url($url, PHP_URL_HOST);
if(0 === strpos('www.', $domain)){
$domain = substr($domain, 4);
}