I have a home.php file which references fileA using php require command which is in the same folder i.e. localhost. the code is:
<?php // /localhost/home.php
require ('/fileA.php');
?>
fileA references another file in its code fileB.
so far its workin properly
when i access fileC.php
i reference fileA using
<?php // /localhost/A/B/fileC.php
require ('../../fileA.php');
?>
the code is able to acquire fileA but only works properly when fileB is in the same folder as fileC else produces a 404 error.I am not able to understand why is this happening since fileB is called by fileA.
thanks.
When using relative file paths, keep in mind that they are relative to your current working directory, not to file that performs inclusion. current working directory is set automatically on the first request (A/B in your case).
Some simple solutions: always use dirname(__FILE__) before including file, this way it be relative to the file the is in:
<?php
require(dirname(__FILE__)."/FileA.php");
require(dirname(__FILE__)."/../../FileB.php");
Related
What is the difference between these two in PHP?
require "./vendor/autoload.php";
vs
require "vendor/autoload.php";
For both statements the autoload.php script is found, but in certain environment the autoloader itself does not find classes. I'm not trying to solve the autoloader problem itself, but try to understand why these two make it behave differently.
The . refers to the folder that you are in, it's most a unix syntax for files them for the php. I think you should use __DIR__ to prefix the included files, so you can avoid some problems with relative paths
The . gives you the ability to set the path of the included files relatively to the path of the original file that run (the file that included them).
Lets take the following structure:
/index.php
/file2.php
/folder/
/file1.php
If index.php includes file1.php, and you want file1.php to include file2.php - you can do this using require './file2.php'; (inside file1.php, which is in the inner folder).
If you use require 'file2.php'; inside file1.php you are looking for file2.php inside the folder (which will give you an error, because the file is not there).
I have two files in the same folder, let's call them file1 and file2. Each of them use the same path to an include file called dbgeneral.php. They each then call the function admin_page_init() to check session information and bar access to non admins. One of the files works fine, however the other throws up an error on the require. If I copy paste the included file into the file which throws the error it works fine. If I include a copy of the file from a different folder it works fine. For some reason it refuses to find the file if it is in the same folder. I can use file_exists() and it returns positive. As far as I know there is no reason for this behaviour.
Folder Structure:
html/
/ dbgeneral.php
/ file1.php
/ file2.php
code:
require_once 'dbgeneral.php';
admin_page_init();
Also note that I tried using the superglobal $_SERVER to acquire the real absolute path. Also, this works on my local test server, but does not work on my web host.
include_once 'dbgeneral.php';
include_once 'file1.php';
include_once 'file2.php';
This will work. If it does not, it will show you an error as to why it did not work; require will not show you an error in the same fashion.
I'm having a spot of bother with php includes. I have the following file structure
htdocs
index.php
login.php
php_includes
db_conx.php
check_user_status.php
within the db_conx.php file i've creates a variable $number = 10; for testing.
The db_conx file is included in the check_user_status.php file with the following code:
include_once("db_conx.php");
and that is working fine - i.e. i can echo $number and get 10.
However, I'm including the check_user_status.php file at the top of login.php with this code:
include_once("php_includes/db_conx.php");
and on this page I'm unable to echo out $number on this page (check_user_status.php).
I'm going to need this script included in many pages (since it checks whether the user is logged in or not). Am I doing something strange with the paths?
For relative paths you need to do this.
include_once("../php_includes/db_conx.php");
To break this down.
Your Current working directory is initially going to be htdocs/ if your hit that file in your browser.
the .. back you up one directory level (so the directory that contains both htdocs and php_includes)
then you want to follow down php_includes to get to db_conx.php.
This will become a problem when you do a file in a subdirectory. Assuming you and a page2.php to a htdocs/subpages/
Now if we follow those same steps we are not going to arrive at the same location.
A better approach is to get the path relative to an absolute location. I like using the document root (htdocs in your case), so:
include($_SERVER["DOCUMENT_ROOT"]."/../php_includes/db_conx.php");
will refer to the same place on the file system regardless of where it is used.
I think you can use __DIR__ magic constant
The directory of the file. If used inside an include, the directory of the included file is returned. This is equivalent to dirname(FILE). This directory name does not have a trailing slash unless it is the root directory. (Added in PHP 5.3.0.)
This will help you with nested included files, infact the file path will be always set automatically and you don't have to deal with absolute paths.
If your file structure is correct, assuming that php_includes is NOT a directory within htdocs, you would need to do:
include_once("../php_includes/db_conx.php");
I have a directory root:
index.php
includes/
template.php
testfile.php
phpFiles/
processInput.php
testfile.php
index.php:
require_once("includes/template.php");
template.php:
require_once("includes/phpFiles/processInput.php")
processInput.php:
require_once("testfile.php")
require_once("../testfile.php")
This code will work when you run index.php, of course it will not work when you run template.php.
As you can see, index.php includes template.php like normal. But in template.php, you have to include like if you are in the directory that index.php is in. But then, in processInput.php, you include as if you are in the directory that processInput.php is in.
Why is this happening, and how can I fix it so that the include path is always the directory of the file that the require is done in? The second included file have the same include path as the requested file, but the next one does not.
Thanks for your help!
EDIT: The strange thing is that I've included classes in a class folder. And it included other files as it is supposed to, even though the paths are relative. WHY does this happen, and how can I fix it?
VERY IMPORTANT EDIT: I just realized that all this is because in my example, the inclusion in includes/phpFiles/processInput.php includes a file in the same directory: require_once("file in same dir.php"); This is the reason. If you are including a file with out specifying anything more than the filename, the include_path is actually the dir where the file the require is written in is in. Can anyone confirm this?
Use an absolute path.
require_once($_SERVER['DOCUMENT_ROOT']."/includes/phpFiles/processInput.php");
Use a similar form for all your required files and they will work no matter where you are.
You can do this in a few ways, amongst others:
Use set_include_path to control the directories from where to perform require() calls.
Define a common absolute base path in a constant that you define in index.php and use that in every require() statement (e.g. require(BASEPATH . '/includes/template.php')).
Use relative paths everywhere and leverage dirname(__FILE__) or __DIR__ to turn them into absolute paths. For instance: require(__DIR__ . '/phpFiles/processInput.php');
By default, the current working directory is used in the include path; you can verify this by inspecting the output of get_include_path(). However, this is not relative to where the include() is made from; it's relative to the main executing script.
You're using relative paths. You need to use absolute paths: $_SERVER['DOCUMENT_ROOT'].
When you include/require, you are basically temporarily moving all code from one file, to another.
so if file1.php (which is located in root) contains:
require("folder/file.php");
and you include file1.php in file2.php (which is in a different location (say folder directory for example):
file2.php:
require("../file1.php");
Now all of file1.php code is in file2.php. So file2.php will look like this:
require("../file1.php");
require("folder/file.php");//but because file2.php is already in the `folder` directory, this path does not exist...
index.php:
require_once("includes/template.php");
template.php:
require_once("includes/phpFiles/processInput.php")
Your directory structure is off. The file inclusion is being seen from the file you're using it from. So, "template.php" is looking for an "includes/" folder in its current folder (/includes/).
As others are saying, use absolute paths, which will make sure you're always going at it from the file system root, or use:
require_once("phpFiles/processInput.php")
In your template.php file (which is far more likely to break if you ever move things around, which is why others all recommend using absolute paths from the file system root).
BTW, if you're using "index.php" as some kind of framework system, you can consider defining a variable that stores the address of common files such as:
define('APPLICATION_PATH', realpath(dirname(__FILE__));
define('PHPFILES_PATH', APPLICAITON_PATH . '/includes/phpFiles/');
I have seen this:
<?php
include( dirname(__FILE__) . DIRECTORY_SEPARATOR . 'my_file.php');
?>
Why would I ever need to do this? Why would I go to the trouble of getting the dirname and then concatenating that with a directory separator, and a new filename?
Is the code above not equivalent to this:
<?php
include( 'my_file.php' );
?>
??
The PHP doc says,
Files are included based on the file path given or, if none is given, the include_path specified. If the file isn't found in the include_path, include() will finally check in the calling script's own directory and the current working directory before failing. The include() construct will emit a warning if it cannot find a file; this is different behavior from require(), which will emit a fatal error.
Let's say I have a (fake) directory structure like:
.../root/
/app
bootstrap.php
/scripts
something/
somescript.php
/public
index.php
Now assume that bootstrap.php has some code included for setting up database connections or some other kind of boostrapping stuff.
Assume you want to include a file in boostrap.php's folder called init.php. Now, to avoid scanning the entire include path with include 'init.php', you could use include './init.php'.
There's a problem though. That ./ will be relative to the script that included bootstrap.php, not bootstrap.php. (Technically speaking, it will be relative to the working directory.)
dirname(__FILE__) allows you to get an absolute path (and thus avoid an include path search) without relying on the working directory being the directory in which bootstrap.php resides.
(Note: since PHP 5.3, you can use __DIR__ in place of dirname(__FILE__).)
Now, why not just use include 'init.php';?
As odd as it is at first though, . is not guaranteed to be in the include path. Sometimes to avoid useless stat()'s people remove it from the include path when they are rarely include files in the same directory (why search the current directory when you know includes are never going to be there?).
Note: About half of this answer is address in a rather old post: What's better of require(dirname(__FILE__).'/'.'myParent.php') than just require('myParent.php')?
I might have even a simpler explanation to this question compared to the accepted answer so I'm going to give it a go: Assume this is the structure of the files and directories of a project:
Project root directory:
file1.php
file3.php
dir1/
file2.php
(dir1 is a directory and file2.php is inside it)
And this is the content of each of the three files above:
//file1.php:
<?php include "dir1/file2.php"
//file2.php:
<?php include "../file3.php"
//file3.php:
<?php echo "Hello, Test!";
Now run file1.php and try to guess what should happen. You might expect to see "Hello, Test!", however, it won't be shown! What you'll get instead will be an error indicating that the file you have requested(file3.php) does not exist!
The reason is that, inside file1.php when you include file2.php, the content of it is getting copied and then pasted back directly into file1.php which is inside the root directory, thus this part "../file3.php" runs from the root directory and thus goes one directory up the root! (and obviously it won't find the file3.php).
Now, what should we do ?!
Relative paths of course have the problem above, so we have to use absolute paths. However, absolute paths have also one problem. If you (for example) copy the root folder (containing your whole project) and paste it in anywhere else on your computer, the paths will be invalid from that point on! And that'll be a REAL MESS!
So we kind of need paths that are both absolute and dynamic(Each file dynamically finds the absolute path of itself wherever we place it)!
The way we do that is by getting help from PHP, and dirname() is the function to go for, which gives the absolute path to the directory in which a file exists in. And each file name could also be easily accessed using the __FILE__ constant. So dirname(__FILE__) would easily give you the absolute (while dynamic!) path to the file we're typing in the above code. Now move your whole project to a new place, or even a new system, and tada! it works!
So now if we turn the project above to this:
//file1.php:
<?php include(dirname(__FILE__)."/dir1/file2.php");
//file2.php:
<?php include(dirname(__FILE__)."/../file3.php");
//file3.php:
<?php echo "Hello, Test!";
if you run it, you'll see the almighty Hello, Test!! (hopefully, if you've not done anything else wrong).
It's also worth mentioning that from PHP5, a nicer way(with regards to readability and preventing eye boilage!) has been provided by PHP as well which is the constant __DIR__ which does exactly the same thing as dirname(__FILE__)!
Hope that helps.
I used this below if this is what you are thinking. It it worked well for me.
<?php
include $_SERVER['DOCUMENT_ROOT']."/head_lib.php";
?>
What I was trying to do was pulla file called /head_lib.php from the root folder. It would not pull anything to build the webpage. The header, footer and other key features in sub directories would never show up. Until I did above it worked like a champ.
If you want code is running on multiple servers with different environments,then we have need
to use dirname(FILE) in an include or include_once statement.
reason is follows.
1. Do not give absolute path to include files on your server.
2. Dynamically calculate the full path like absolute path.
Use a combination of dirname(FILE) and subsequent calls to itself until you reach to the home of your '/myfile.php'.
Then attach this variable that contains the path to your included files.