I am trying to extract a portion of a URL using regex.
An example of my url would be:
http://www.google.com/search?sourceid=chrome&ie=UTF-8&q=food
Using php, how could I extract the data in the q variable or the sourceid variable?
Don't use a regex for this. Instead, use parse_url() and parse_str().
$params = array();
$url= "http://www.google.com/search?sourceid=chrome&ie=UTF-8&q=food";
$url_query = parse_url($url, PHP_URL_QUERY);
parse_str($url_query, $params);
echo $params['q']; // Outputs food
Demo
A perfect tutorial for what you're trying to accomplish:
$parts = parse_url('http://www.google.com/search?sourceid=chrome&ie=UTF-8&q=food');
parse_str($parts['query'], $query);
echo $query['q'];
Related
I need to extract only the 'id' from an URL. The url format is given below. Currently, I use parse_url and substr function, which works. However, it is not a good choice if the length of 'id' changes, where regex comes into play. I am not well-conversant with regex, so I need an idea how to do it in other way e.g. regex.
$url = 'http://www.example.com/stock-footage/53833534/portrait-lifestyle-leisure-caucasian-parents-children-snow-v.html';
$URLParts = parse_url($url);
// echo $URLParts['path'];
$substring = substr($URLParts['path'],15,8);
echo $substring;
You can use the following regular expression:
preg_match("/.+\/([0-9]+).+/", $url, $matches);
echo $matches[1];
live example
you can use this :
<?php
$url = 'http://www.example.com/stock-footage/53833534/portrait-lifestyle-leisure-caucasian-parents-children-snow-v.html';
$URLParts = parse_url($url);
$exploded = explode('/',$URLParts['path']);
echo $exploded[2];
?>
Well sorry for the probably misleading title. Wasn't sure how to describe it better.
When accessing the status page I want to get the attached ID. But I don't want to use GET fields (wordpress makes /status?id=2134 to /status/?id=1234 - that's the only reason actually).
So this is my url
http://foo.bar.com/status/1234/
I want to get 1234
Okay fine. I could use something like $_SERVER["REQUEST_URI"] + trim() for example. Probably regex would be the key to get this job done since one could do something like /status/1234/foo/bar/baz/.. But I'm wondering if there is something builtin with PHP to get this part of the url.
Use the parse_url() function, and extract it:
$url = 'http://foo.bar.com/status/1234/';
$path = trim(parse_url($url, PHP_URL_PATH), '/');
$items = explode('/', $path);
$num = array_pop($items);
var_dump($num);
You can also use a regular expression, if that tickles your fancy:
$url = 'http://foo.bar.com/status/1234/';
$path = parse_url($url, PHP_URL_PATH);
preg_match('~/status/(?P<num>\d+)/?~', $path, $result);
$num = isset($result['num']) ? $result['num'] : null;
var_dump($num);
Try to parses a URL and returns an associative array containing any of the various components of the URL that are present using parse_url, explode it using explode and finally select status id using end
Try like this
$url = 'http://foo.bar.com/status/1234/';
$statusId = explode('/',trim(parse_url($url, PHP_URL_PATH), '/'));
print end($statusId);
Demo Ex http://ideone.com/34iDnh
trim- http://php.net/trim
explode-http://php.net/explode
parse_url-[1]: http://php.net/manual/en/function.parse-url.php
I want to extract id from an url using php preg_match..
For eg: $string = 'http://www.mysite.com/profile.php?id=1111'; I need output as '1111'
using preg_match.
I tried this :
if(preg_match('/(?:https?):\/\/www\.mysite\.com\/profile\.php\?id\=[0-9]/', $string, $match) > 0){
$id = $match[1];
}
But am getting output as 'profile.php'
Can someone help me please?
Why not use parse_url with parse_str
$url_component = parse_url($string);
parse_str($url_component['query'], $output);
echo $output['id'];
if there is only one parameter in the url you can use explode function to do that easily, like
$string = 'http://www.mysite.com/profile.php?id=1111';
$ex=explode('=',$string);
$id=$ex[1];
You may also use parse_url function of php.
Hope this help,
$pattern = '/(?:https?):\/\/www\.mysite\.com\/profile\.php\?id\=([0-9]+)/';
This should work fine!
But do this with parse_url
I need to get the ID part of a pastebin link,
which is setup like http://pastebin.com/{id}, i have tired alot of different regex i am also using preg_match in php
preg_match("~http://pastebin.com/([0-9a-zA-Z]+)~", $url, $match);
print_r($match);
or
$url = "http://pastebin.com/a65d46";
$parsed = parse_url($url);
echo trim($parsed['path'])." is ID you needed";
Instead of regex, try using parse_url to extract the path
regex would be overkill for this.
$url = "http://pastebin.com/Ugj1eqCN"
$pos = strpos($url,"pastebin.com/");
echo substr($url,$pos+13);
Hi all i know preg_replace can be used for formatting string but i need help in that concerned area my url will be like this
http://www.example.com/index.php/
also remove the http,https,ftp....sites also
what i want is to get
result as
example.com/index.php
echo preg_replace("~(([a-z]*[:](//))|(www.))~", '', "ftp://www.example.com");
$url = 'http://www.example.com/index.php/';
$strpos = strpos($url,'.');
$output = substr($url,$strpos+1);
$parts=parse_url($url);
unset($parts['scheme']);
//echo http_build_url($parts);
echo implode("",$parts);
EDIT
To use http_build_url you needs pecl_http you can use implode as alternate
Something like this
$url = "http://www.example.com/index.php";
$parts = parse_url($url);
unset($parts['scheme']);
echo preg_replace('/^((ww)[a-z\d][\x2E])/i', '', join('', $parts));
Output
example.com/index.php
Example #2
$url = "http://ww3.nysif.com/Workers_Compensation.aspx";
Output
nysif.com/Workers_Compensation.aspx