I've a simple question.
I've this 7310093341976450848 number which I needed to echo.But when I echo it gives me this 7.3100933419765E+18.
I tried echo (string)$data; to cast it to string and then print it but it's still giving the same result.
The number is initially of type double.
I've this 7310093341976450848 number which I needed to echo.
The number is initially of type double.
Because of the floating point representation used in PHP, once it's stored as a double, you cannot print out that exact number anymore.
This is one of the (many) ways to print out the value:
printf("%.0f", $data);
echo number_format($data, 0, '', '');
If you don't want to lose precision, store it as a string, or use one of the arbitrary precision libraries: BC Math / GMP.
Use number_format(). Here's how:
echo number_format( $data, 0, '', '' );
Related
I have a number in php formatted as 5299, and I'd like for it to be converted to a number that's decimal formatted as 52.99 to resemble money. I've messed around with php's number_format() but it doesn't seem like there is a way to add decimals for converting to cents. This number is dynamically calculated, so the 5299 might be 12122, where 5299 would be 52.99 and 12122 would be converted to 121.22.
Just use a simple function like this.
<?php
$value = 50;
echo number_format(($value /100), 2, '.', ' ');
?>
I know the question is very basic but it seems nothing working for me.
I have a number (either or float or integer) which I want to be formatted upto two decimal point. For this purpose I'm using PHP function number_format but it converts my number to string.
To convert it back to float I am using (float) or floatval(). But these functions just truncates the number after converting it to float from string.
Here is my code
$revenue_sum = array_sum(array_column($val2, 'weighted_revenue')); //23722
$test = number_format($revenue_sum, 2); //"23,722.00"
$test = (float)number_format($revenue_sum, 2); //23.0
$test = floatval(number_format($revenue_sum, 2)); //23.0
I want the $test to be 23722.00 for the $revenue_sum = 23722
If $revenue_sum = 2372.2 the $test should be 2372.20
number_format() function can be used as follows:
echo number_format($revenue_sum, 2,'.',''); // will return 23722.00 for the $revenue_sum = 23722
You are trying to type cast with ',' value, it is truncating the string.
you can try this
<?php echo sprintf("%2.2f", 8900.258); ?>
which will output as
8900.26
If you assign a floating point value to a variable, then it is converted to an internal binary format (usually using IEEE 754). Not all possible values has an internal representation. So while scanning a text, the float is rounded to the nearest possible value. So for example 1.23 is rounded to 1.22999999999999998.
Because of the internal representation, there is no difference between 100 or 1e2 or 100.0 or 100.0000.
And when printing a floating point value without any formatting instruction, PHP guess a good format and rounding some digits. So 1.22999999999999 is displayed as 1.23(may varies on different systems).
In general: As long you are calculating, formatting doesn't matter. It is mostly the best, to ignore the decimal fragments on debugging. But when printing (=converting to text), use functions like format_number() or any of the printf() functions.
To be more pragmatic:
I have a string ($maxDeposit) which is a numeric monetary value. So, for example:
123.00
This string is being passed in to jQuery, it needs to be passed in as a numeric data type. I'm achieving this using the following:
$maxDeposit = floatval($maxDeposit);
This loses the last last decimal place however, so my number looks like:
123.0
I have this method of converting the number to two decimal places:
$maxDeposit = sprintf('%0.2f', round($maxDeposit, 2));
However this also converts the number back to a string. Is there a way I can convert the string to a float but keep the last decimal place? Thanks
No, float is a numeric value, and 123.00 is its representation with 2 decimal places. It is responsibility of view layer to format numbers. In your case it is jQuery, e.g. console.log(maxDeposit.toFixed(2)).
I think, You can use floatval/float and number_format.
$maxDeposit = number_format(floatval($maxDeposit), 2);
or
number_format((float)$maxDeposit, 2, '.', '');
http://php.net/manual/pt_BR/function.number-format.php
In PHP I have the following code:
<?PHP
$var = .000021;
echo $var;
?>
the output is 2.1E-5 !
Why? it should print .000021
Use number_format() to get what you're after:
print number_format($var, 5);
Also check sprintf()
2.1E-5 is the same number as 0.000021. That's how it prints numbers below 0.001. Use printf() if you want it in a particular format.
Edit If you're not familiar with the 2.1E-5 syntax, you should know it is shorthand for 2.1×10-5. It is how most programming languages represent numbers in scientific notation.
Use number_format or sprintf if you want to see the number as you expect.
echo sprintf('%f', $var);
echo number_format($var, 6);
To show a number up to 8 decimal spaces, without extra zeroes to the right (as number_format does, which can be annoying), use this:
echo rtrim(rtrim(sprintf('%.8F', $var), '0'), ".");
In general, a number is a number, not a string, and this means that any programming language treats a number as a number. Thus, the number by itself doesn't imply any specific format (like using .000021 instead of 2.1e-5). This is nothing different to displaying a number with leading zeros (like 0.000021) or aligning lists of numbers. This is a general issue you'll find in any programming language: if you want a specific format you need to specify it, using the format functions of your programming language.
Unless you specify the number as string and convert it to a real number when needed, of course. Some languages can do this implicitly.
The previous answers responded to OP question, but none offered the code to do it.
Use this function to format any number with E- format.
function format_amount_with_no_e($amount) {
$amount = (string)$amount; // cast the number in string
$pos = stripos($amount, 'E-'); // get the E- position
$there_is_e = $pos !== false; // E- is found
if ($there_is_e) {
$decimals = intval(substr($amount, $pos + 2, strlen($amount))); // extract the decimals
$amount = number_format($amount, $decimals, '.', ','); // format the number without E-
}
return $amount;
}
Please note the function will always return a string.
Programming languages have different methods for storing numbers in memory. This is determined by the type of number that is being used. In your case, you have a floating point number (a fraction) that is to large to be stored as a fixed point number ( fractions are stored in this manner depending on their size).
This is a very important feature especially when working with very large or very small numbers. For instance, NASA or spaceX uses special storage methods for its calculations to ensure that the rockets the re-enter earths orbit land where they should.
Also, different storage methods take up different amounts of memory. However, the solution provided above should work. Just remember round off errors might occur with very big or small numbers.
In PHP I have the following code:
<?PHP
$var = .000021;
echo $var;
?>
the output is 2.1E-5 !
Why? it should print .000021
Use number_format() to get what you're after:
print number_format($var, 5);
Also check sprintf()
2.1E-5 is the same number as 0.000021. That's how it prints numbers below 0.001. Use printf() if you want it in a particular format.
Edit If you're not familiar with the 2.1E-5 syntax, you should know it is shorthand for 2.1×10-5. It is how most programming languages represent numbers in scientific notation.
Use number_format or sprintf if you want to see the number as you expect.
echo sprintf('%f', $var);
echo number_format($var, 6);
To show a number up to 8 decimal spaces, without extra zeroes to the right (as number_format does, which can be annoying), use this:
echo rtrim(rtrim(sprintf('%.8F', $var), '0'), ".");
In general, a number is a number, not a string, and this means that any programming language treats a number as a number. Thus, the number by itself doesn't imply any specific format (like using .000021 instead of 2.1e-5). This is nothing different to displaying a number with leading zeros (like 0.000021) or aligning lists of numbers. This is a general issue you'll find in any programming language: if you want a specific format you need to specify it, using the format functions of your programming language.
Unless you specify the number as string and convert it to a real number when needed, of course. Some languages can do this implicitly.
The previous answers responded to OP question, but none offered the code to do it.
Use this function to format any number with E- format.
function format_amount_with_no_e($amount) {
$amount = (string)$amount; // cast the number in string
$pos = stripos($amount, 'E-'); // get the E- position
$there_is_e = $pos !== false; // E- is found
if ($there_is_e) {
$decimals = intval(substr($amount, $pos + 2, strlen($amount))); // extract the decimals
$amount = number_format($amount, $decimals, '.', ','); // format the number without E-
}
return $amount;
}
Please note the function will always return a string.
Programming languages have different methods for storing numbers in memory. This is determined by the type of number that is being used. In your case, you have a floating point number (a fraction) that is to large to be stored as a fixed point number ( fractions are stored in this manner depending on their size).
This is a very important feature especially when working with very large or very small numbers. For instance, NASA or spaceX uses special storage methods for its calculations to ensure that the rockets the re-enter earths orbit land where they should.
Also, different storage methods take up different amounts of memory. However, the solution provided above should work. Just remember round off errors might occur with very big or small numbers.