I have the following code
<?
php drupal_set_message("Your registration submission has been received.");
drupal_goto("/events-initiatives/events-listing");
?>
And I want to remove everything but the Your registration submission has been received. and this message will change, so I need it to be a wildcard. So it would also make say
<?php
drupal_set_message("Testing!!!");
drupal_goto("/events-initiatives/events-listing");
?>
But I can't figure out how to do the PHP code, my current one is
preg_replace('#(<?php drupal_set_message(").*?("); drupal_goto("/guidelines-resources/professionals/lending-library"); ?>)#', '$1$2', $string);
but that isn't working, it seems to have problems with the ( in it.
Any idea how I could do this?
From looking at your original post, (before your regex was changed into a PHP snippet) I'd suggest you are looking for a regex along these lines:
#<\?php\s+drupal_set_message\(".*?"\);\s+drupal_goto\("/guidelines-resources/professionals/lending-library"\);\s+\?>#
Note that this regex:
escapes all special characters (e.g., ?, ( and )) with preceding slashes
replaces a single space with \s+ which matches one or more consecutive whitespace characters
EDIT
After rereading your question, if the only thing you want left is the text that is passed as an argument to drupal_set_message, then try this:
$pattern = '#\bdrupal_set_message\("(.*?)"\)#';
$found = preg_match($pattern, $subject, $matches);
// if found, $matches[1] will contain the argument to drupal_set_message
You can escape the special characters (though really, just the open and close parentheses) with backslashes. On a side note, if you have a decent IDE then it should have sophisticated regex-capable search-and-replace; use it (although if you do, you'll probably need to also escape the forward slashes, as those are the most likely delimiters that your IDE would use).
Related
I have the following content in a string (query from the DB), example:
$fulltext = "Thank you so much, {gallery}art-by-stephen{/gallery}. As you know I fell in love with it from the moment I saw it and I couldn’t wait to have it in my home!"
So I only want to extract what it is between the {gallery} tags, I'm doing the following but it does not work:
$regexPatternGallery= '{gallery}([^"]*){/gallery}';
preg_match($regexPatternGallery, $fulltext, $matchesGallery);
if (!empty($matchesGallery[1])) {
echo ('<p>matchesGallery: '.$matchesGallery[1].'</p>');
}
Any suggestions?
Try this:
$regexPatternGallery= '/\{gallery\}(.*)\{\/gallery\}/';
You need to escape / and { with a \ before it. And you where missing start and end / of the pattern.
http://www.phpliveregex.com/p/fn1
Similar to Andreas answer but differ in ([^"]*?)
$regexPatternGallery= '/\{gallery\}([^"]*?)\{\/gallery\}/';
Don't forget to put / at the beginning and the end of the Regex string. That's a must in PHP, different from other programming languages.
{,},/ are characters that can be confused as a Regex logic, so you have to escape it using \ like \{.
Use ? to make the string to non-greedy, thus saves memory. It avoids error when facing this kind of string "blabla {galery}you should only get this{/gallery} but you also got this instead.{/gallery} Rarely happens but be careful anyway".
Try this RegEx:
\{gallery\}(.*?)\{\/gallery\}
The problem with your RegEx was that you did not escape the / in the closing {gallery}. You also need to escape { and }.
You should use .*? for a lazy match, otherwise if there are 2 tags in one string, it will combine them. I.e. {gallery}by-joe{/gallery} and {gallery}by-tim{/gallery} would end up as:
by-joe{/gallery} and {gallery}by-tim
However, using a lazy match, you would get 2 results:
by-joe
by-tim
Live Demo on Regex101
I have the following code:
preg_match('/#([^# ]+)/', $image->caption->text, $matches)
and I wanted to basically detect mentions in a string. However the issue now is that it is confused with email address such that it detects email as a mention, so for example if I have aksdjasd#yahoo.com then this counts as a match. I guess what I want to say here is that before the # sign there should be a space. But how do I put that in to this regex?
EDIT:
I also wanted to detect #mentions at the beginning of the string as well
before the # sign there should be a space
You can use lookbehind (edited based on OP's comment below):
preg_match('/(?<= |^)#[^# ]+/', $image->caption->text, $matches);
Working Demo
My take:
preg_match('/(?<=\W|^)#(\w+)/', "#Easy? No.#anubhava try harder! #\t", $matches);
preg_match('/(?<=\W|^)#(\w+)/', "Easy? No.#anubhava try harder! #\t", $matches);
preg_match('/(?<=\W|^)#(\w+)/', "Easy? No.anubhava try harder! e#m #\t", $match);
Correctly recognizes #Easy , #anubhava and not the tab or email.
You can use look behinds to check behind your regex.
Try using: preg_match('/(?<![^\s])#([^#\s]+)/', $image->caption->text, $matches);
Important thing to note here, is that you also want to use \s in the class you check for AFTER the #. If not, you could end up matching #stuff<NEWLINE><nonmatch>. I did some quick testing and found the problems with just using space for a number of reasons. Here is a link to the tests.
This is also using a negative look behind, because if the mention is at the front of the string it would not match using a positive look behind. You have to account for blank in front of the positive matches.
I think just checking for a space alone could have risks. I think you might want to check for any whitespace character, just in case the mention is at the very beginning of the string.
I am stuck trying to create a regex that will allow for letters, numbers, and the following chars: _ - ! ? . ,
Here is what I have so far:
/^[-\'a-zA-Z0-9_!\?,.\s]+$/ //not escaping the ?
and this version too:
/^[-\'a-zA-Z0-9_!\?,.\s]+$/ //attempting to escape the ?
Neither of these seem to be able to match the following:
"Oh why, oh why is this regex not working! It's getting pretty frustrating? Frustrating - that is to say the least. Hey look, an underscore_ I wonder if it will match this time around?"
Can somebody point out what I am doing wrong? I must point out that my script takes the user input (the paragraph in quotes in this case) and strips all white space so actual input has no white space.
Thanks!
UPDATE:
Thanks to Lix's advice, this is what I have so far:
/^[-\'a-zA-Z0-9_!\?,\.\s]+$/
However, it's still not working??
UPDATE2
Ok, based on input this is what's happening.
User inputs string, then I run the string through following functions:
$comment = preg_replace('/\s+/', '',
htmlspecialchars(strip_tags(trim($user_comment_orig))));
So in the end, user input is just a long string of chars without any spaces. Then that string of chars is run using:
preg_match("#^[-_!?.,a-zA-Z0-9]+$#",$comment)
What could possibly be causing trouble here?
FINAL UPDATE:
Ended up using this regex:
"#[-'A-Z0-9_?!,.]+#i"
Thanks all! lol, ya'll are going to kill me once you find out where my mistake was!
Ok, so I had this piece of code:
if(!preg_match($pattern,$comment) || strlen($comment) < 2 || strlen($comment) > 60){
GEEZ!!! I never bothered to look at the strlen part of the code. Of course it was going to fail every time...I only allowed 60 chars!!!!
When in doubt, it's always safe to escape non alphanumeric characters in a class for matching, so the following is fine:
/^[\-\'a-zA-Z0-9\_\!\?\,\.\s]+$/
When run through a regular expression tester, this finds a match with your target just fine, so I would suggest you may have a problem elsewhere if that doesn't take care of everything.
I assume you're not including the quotes you used around the target when actually trying for a match? Since you didn't build double quote matching in...
Can somebody point out what I am doing wrong? I must point out that my script takes the user input (the paragraph in quotes in this case) and strips all white space so actual input has no white space.
in which case you don't need the \s if it's working correctly.
I got the following code to work as expected to (running php5):
<?php
$pattern = "#[-'A-Z0-9_?!,.\s]+#i";
$string = "Oh why, oh why is this regex not working! It's getting pretty frustrating? Frustrating - that is to say the least. Hey look, an underscore_ I wonder if it will match this time around?";
$results = array();
preg_match($pattern, $string, $results);
echo '<pre>';
print_r($results);
echo '</pre>';
?>
The output from print_r($results) was as following:
Array
(
[0] => Oh why, oh why is this regex not working! It's getting pretty frustrating? Frustrating - that is to say the least. Hey look, an underscore_ I wonder if it will match this time around?
)
Tested on http://writecodeonline.com/php/.
It's not necessary to escape most characters inside []. However, \s will not do what you want inside the expression. You have two options: either manually expand (/^[-\'a-zA-Z0-9_!?,. \t\n\r]+$/) or use alternation (/^(?:[-\'a-zA-Z0-9_!?,.]|\s)+$/).
Note that I left the \ before the ' because I'm assuming you're putting this in a PHP string and I wouldn't want to suggest a syntax error.
The only characters with a special meaning within a character class are:
the dash (since it can be used as a delimiter for ranges), except if it is used at the beginning (since in this case it is no part of any range),
the closing bracket,
the backslash.
In "pure regex parlance", your character class can be written as:
[-_!?.,a-zA-Z0-9\s]
Now, you need to escape whatever needs to be escaped according to your language and how strings are written. Given that this is PHP, you can take the above sample as is. Note that \s is interpreted in character classes as well, so this will match anything which is matched by \s outside of a character class.
While some manuals recommend using escapes for safety, knowing the general regex rules for character classes and applying them leads to shorter and easier to read results ;)
I'm having this issue with a regular expression in PHP that I can't seem to crack. I've spent hours searching to find out how to get it to work, but nothing seems to have the desired effect.
I have a file that contains lines similar to the one below:
Total','"127','004"','"118','116"','"129','754"','"126','184"','"129','778"','"128','341"','"127','477"','0','0','0','0','0','0
These lines are inserted into INSERT queries. The problem is that values like "127','004" are actually supposed to be 127,004, or without any formatting: 127004. The latter is the actual value I need to insert into the database table, so I figured I'd use preg_replace() to detect values like "127','004" and replace them with 127004.
I played around with a Regular Expression designer and found that I could use the following to get my desired results:
Regular Expression
"(\d+)','(\d{3})"
Replace Expression
$1$2
The line on the top of this post would end up like this: (which is what I am after)
Total','127004','118116','129754','126184','129778','128341','127477','0','0','0','0','0','0
This, however, does not work in PHP. Nothing is being replaced at all.
The code I am using is:
$line = preg_replace("\"(\d+)','(\d{3})\"", '$1$2', $line);
Any help would be greatly appreciated!
There are no delimiters in your regex. Delimiters are required in order for PHP to know what is the pattern to match and what is a pattern modifier (e.g. i - case-insensitive, U - ungreedy, ...). Use a character that doesn't occur in your pattern, typically you'll see a slash '/' used.
Try this:
$line = preg_replace("/\"(\d+)','(\d{3})\"/", '$1$2', $line);
You forgot to wrap your regular expression in front-slashes. Try this instead:
"/\"(\d+)','(\d{3})\"/"
use preg_replace("#\"(\d+)','(\d+)\"#", '$1$2', $s); instead of yours
Hi Guys I'm very new to regex, can you help me with this.
I have a string like this "<input attribute='value' >" where attribute='value' could be anything and I want to get do a preg_replace to get just <input />
How do I specify a wildcard to replace any number of any characters in a srting?
like this? preg_replace("/<input.*>/",$replacement,$string);
Many thanks
What you have:
.*
will match "any character, and as many as possible.
what you mean is
[^>]+
which translates to "any character, thats not a ">", and there must be at least one
or altertaively,
.*?
which means
"any character, but only enough to make this rule work"
BUT DONT
Parsing HTML with regexps is Bad
use any of the existing html parsers, DOM librarys, anything, Just NOT NAïVE REGEX
For example:
<foo attr=">">
Will get grabbed wrongly by regex as
'<foo attr=" ' with following text of '">'
Which will lead you to this regex:
`<[a-zA-Z]+( [a-zA-Z]+=['"][^"']['"])*)> etc etc
at which point you'll discover this lovely gem:
<foo attr="'>\'\"">
and your head will explode.
( the syntax highlighter verifies my point, and incorrectly matches thinking i've ended the tag. )
Some people were close... but not 100%:
This:
preg_replace("<input[^>]*>", $replacement, $string);
should be this:
preg_replace("<input[^>]*?>", $replacement, $string);
You don't want that to be a greedy match.
preg_replace("<input[^>]*>", $replacement, $string);
// [^>] means "any character except the greater than symbol / right tag bracket"
This is really basic stuff, you should catch up with some reading. :-)
If I understand the question correctly, you have the code:
preg_replace("/<input.*>/",$replacement,$string);
and you want us to tell you what you should use for $replacement to delete what was matched by .*
You have to go about this the other way around. Use capturing groups to capture what you want to keep, and reinsert that into the replacement. E.g.:
preg_replace("/(<input).*(>)/","$1$2",$string);
Of course, you don't really need capturing groups here, as you're only reinserting literal text. Bet the above shows the technique, in case you want to do this in a situation where the tag can vary. This is a better solution:
preg_replace("/<input [^>]*>/","<input />",$string);
The negated character class is more specific than the dot. This regex will work if there are two HTML tags in the string. Your original regex won't.