Jquery,AJAX & PHP, form submition not working - php

Question

Basically i am trying to create a validation for the form. I want it to check if it can connect to the DB and if true to proceed to another page and if false to return an error.
I am inputting the wrong details to make it just display the error but somehow it always returns "TRUE" on page load... and everytime i click the submit it doesnt do anything regardless of my entry...
thx
<script>
$(document).ready(function(){
var u = $('#username');
var s = $('#server');
var p = $('#password');
$('#iValForm').submit(
$.post("connect.php", {u: u.val(),p: p.val(),s: s.val()}, function(fd){
if (fd == "true"){
alert("Is: " + fd);
return false;
} // if1
if (fd == "false"){
alert("Is2: " + fd);
return false;
} // if2
} //post function
) //Post
) //submit
}) //document
</script>
<form class="iValForm" id="iValForm" method="post">
<fieldset>
<legend id="error"> </legend>
<p>
<label for="username">Username </label>
<input id="username" name="username" class="required" /> </input>
</p>
<p>
<label for="password">Password</label>
<input id="password" name="password" class="required"/> </input>
</p>
<p>
<label for="server">Server</label>
<input id="server" name="server" class="required"/> </input>
</p>
<p>
<input class="submit" type="submit" value="Submit"/>
</p>
</fieldset>
</form>
Connect.php
<?php
$user = $_POST['u'];
$password = $_POST['p'];
$server = $_POST['s'];
#$con = mysql_connect ($server, $user, $password);
if (!$con) {
$response = "false";
echo $response;
} else {
$response = "true";
echo $response;
}
?>

Answer 1

change your php script
if (!$con) {
$response = 'false';
echo $response;
} else {
$response = 'true';
echo $response;
}
and in javascript
if (data == 'false')