Initialising an array of objects - php

Question

Program that tests the rand function is an example:
<?php
class number {
function number() {
$occurences=0;
}
public $occurences;
public $value;
}
$draws = 5000;
$numOfInts = 10;
//$integers = array();
$integers [] = new number();
//initialising loop
for($i=0;$i<=$numOfInts;$i++)
$integers[$i]->$value = $i; //debugger points here
for($i=0;$i<$draws;$i++) {
$integers[rand(0,numOfInts)]->$occurences++;
}
foreach($integers as $int)
printf("%5d %5d <br/>",$int->$value,$int->$occurences);
?>
Errors on the WAMP server:
Undefined variable: value in C:\path\index.php on line 31
Fatal error: Cannot access empty property in C:\path\index.php on line 31
What caused them and how to fix it? I suppose that the $integers is declared incorrectly.

Answer 1

You should access members of an object with this syntax:
$integers[$i]->value
$integers[$i]->occurences;
However you have to initialize your array first as well which means un-comment the initial line to
$integers = array();
As a matter of fact you are not using the better OOP style which would change your data structure like this:
class Number {
private $value;
private $occurences = 0;
public function __construct($value = 0) {
$this->value = $value;
}
public function getValue() {
return $this->number;
}
public function addOccurence() {
$this->occurences++;
}
public function getOccurences() {
return $this->occurences;
}
}
You would then access the members like this:
// init part
$integers = array();
for($i = 0; $i < $numOfInts; $i++) {
$integers[] = new Number($i);
}
// draws part
for($i=0; $i < $draws; $i++) {
$integers[rand(0,$numOfInts-1)]->addOccurence();
}
// print part
foreach($integers as $number) {
printf("%5d %5d<br />", $number->getValue(), $number->getOccurences());
}

Answer 2

Why?
//$integers = array();
$integers [] = new number();
Should just be
$integers = array();
for($i=0;$i<=$numOfInts;$i++) {
$integers[$i] = new number();
}
There are no typed arrays in PHP