MYSQL to JSON for Autocomplete jQueryUI - php

Question

My code below show what I'm doing. Basically the aim is to retrieve data from a database and convert it to a JSON format for jQueryUI. With the method below and a method that didn't use the array_to_json function I was able to get JSON data returned. Eg.:
[ { "name": "Kurt Schneider" }, { "name": "Sam Tsui" }, { "name": "Christina Grimmie" } ]
But the issue is that it still doesn't function with the autocomplete. I replaced the below code with the search.php that was provided with the example, so it's obviously an issue with this code.
I began with only this code:
<?php
include 'connect.php';
mysql_select_db("database", $con);
$search = mysql_query("SELECT name FROM artist");
$rows = array();
while($row = mysql_fetch_assoc($search)) {
$result[] = $row;
}
print json_encode($result);
?>
Which achieved affectively the same results as the below code (besides some differences in spacing):
(The array_to_json function was copied direct from the example).
<?php
include 'connect.php';
mysql_select_db("database", $con);
$search = mysql_query("SELECT name FROM artist");
$rows = array();
while($row = mysql_fetch_assoc($search)) {
$result[] = $row;
}
function array_to_json( $array ){
if( !is_array( $array ) ){
return false;
}
$associative = count( array_diff( array_keys($array), array_keys( array_keys( $array )) ));
if( $associative ){
$construct = array();
foreach( $array as $key => $value ){
// We first copy each key/value pair into a staging array,
// formatting each key and value properly as we go.
// Format the key:
if( is_numeric($key) ){
$key = "key_$key";
}
$key = "\"".addslashes($key)."\"";
// Format the value:
if( is_array( $value )){
$value = array_to_json( $value );
} else if( !is_numeric( $value ) || is_string( $value ) ){
$value = "\"".addslashes($value)."\"";
}
// Add to staging array:
$construct[] = "$key: $value";
}
// Then we collapse the staging array into the JSON form:
$result = "{ " . implode( ", ", $construct ) . " }";
} else { // If the array is a vector (not associative):
$construct = array();
foreach( $array as $value ){
// Format the value:
if( is_array( $value )){
$value = array_to_json( $value );
} else if( !is_numeric( $value ) || is_string( $value ) ){
$value = "'".addslashes($value)."'";
}
// Add to staging array:
$construct[] = $value;
}
// Then we collapse the staging array into the JSON form:
$result = "[ " . implode( ", ", $construct ) . " ]";
}
return $result;
}
echo array_to_json($result);
?>

Answer 1

<?php
include 'connect.php';
mysql_select_db("database", $con);
$search = mysql_query("SELECT name FROM artist");
$rows = array();
while($row = mysql_fetch_assoc($search)) {
//don't add the array, just the name.
$result[] = $row["name"];
}
print json_encode($result);
?>
The code above should return the JSON
["Kurt Schneider", "Sam Tsui", "Christina Grimmie"]