http://www.example.com?id=05
or
http://www.example.com?id=05&name=johnny
This is a string. And I want to get the value of $id from it.
What is the correct pattern for it?
You don't need regex (and you shouldn't be jumping straight to regex in the future unless you have a good reason).
Use parse_url() with PHP_URL_QUERY, which retrieves the querystring. Then pair this with parse_str().
$querystring = parse_url('http://www.mysite.com?id=05&name=johnny', PHP_URL_QUERY);
parse_str($querystring, $vars);
echo $var['id'];
#PhpMyCoder's solution is perfect. But if you absolutely need to use preg_match (though completely unnecessary in this case)
$subject = "http://www.mysite.com?id=05&name=johnny";
$pattern = '/id=[0-9A-Za-z]*/'; //$pattern = '/id=[0-9]*/'; if it is only numeric.
preg_match($pattern, $subject, $matches);
print_r($matches);
Related
I have this string:
"application/controllers/backend"
I want get:
backend
of course the backend it's dynamic, so could be change, so I'm looking for a solution that allow me to get only the last part of the string. How I can do that?
You can take the advantage of basename() to get the last part
in your case, it will be
basename("application/controllers/backend");
Output:
backend
Some thing like this :
echo end(explode("/", $url));
If this thorws error then do :
$parts = explode("/", $url);
echo end($parts);
$arr = explode ("/", $string);
//$arr[2] is your third element in the string
http://php.net/manual/en/function.explode.php
Just use
basename("application/controllers/backend");
http://php.net/manual/en/function.basename.php
And, if you want to do it with a regex:
$result = (preg_match('%.*[/\\\\](.*?)$%', $url, $regs)) ? $regs[1] : '';
You did ask initially for a solution with regex, so, although the other answers haven't involved regex, here is one approach which does.
You can use preg_match and str_replace for this:
$string = '"application/controllers/backend"';
preg_match('/[^\/]+"/', $string, $matches);
$last_item = str_replace('"','',$matches[0]);
$last_item is now a string containing the word backend.
I want to replace a section of a string based that starts with one string and ends with another, and I want the section between also replaced. I think this is possible using regex but I cant' seem to find any decent examples showing this.
For Example:
I have "http://www.website.com" and I want to replace from "www" to "com" with "123xyz".
So"http://www.website.com/something" becomes "http://123xyz/something.
I am assuming I have to use preg_replace(), and I think the regex should start with "^www" and end with "com$", but I cant seem to get a grasp of the syntax of regex enough to create the desired effect.
please help
With reference to your example , you can try like this
$string = 'http://www.website.com/something';
$pattern = '/www(.*)com/';
$replacement = '123xyz';
echo preg_replace($pattern, $replacement, $string);
$phrase = "http://www.website.com";
$phraseWords = array("www", "com");
$replaceTo = array("123xyz", "something");
$result = str_replace($phraseWords, $replaceTo, $phrase);
echo $result;
Thanks so much to both #CodingAnt and #PHPWeblineindia for your great answers. Using #CodingAnt's answer (and some more research I did online) I wrote this function:
function replaceBetween(&$target, $from, $to, $with){
if(strpos($target, $from)===false)return false;
$regex = "'".$from."(.*?)".$to."'si";
preg_match_all($regex, $target, $match);
$match = $match[1];
foreach($match as $m) $target = str_replace($from.$m.$to, $with, $target);
return $target;
}
It seems to work pretty well. I hope someone finds this useful.
I have to extract the email from the following string:
$string = 'other_text_here to=<my.email#domain.fr> other_text_here <my.email#domain.fr> other_text_here';
The server send me logs and there i have this kind of format, how can i get the email into a variable without "to=<" and ">"?
Update: I've updated the question, seems like that email can be found many times in the string and the regular expresion won't work well with it.
You can try with a more restrictive Regex.
$string = 'other_text_here to=<my.email#domain.fr> other_text_here';
preg_match('/to=<([A-Z0-9._%+-]+#[A-Z0-9.-]+\.[A-Z]{2,4})>/i', $string, $matches);
echo $matches[1];
Simple regular expression should be able to do it:
$string = 'other_text_here to=<my.email#domain.fr> other_text_here';
preg_match( "/\<(.*)\>/", $string, $r );
$email = $r[1];
When you echo $email, you get "my.email#domain.fr"
Try this:
<?php
$str = "The day is <tag> beautiful </tag> isn't it? ";
preg_match("'<tag>(.*?)</tag>'si", $str, $match);
$output = array_pop($match);
echo $output;
?>
output:
beautiful
Regular expression would be easy if you are certain the < and > aren't used anywhere else in the string:
if (preg_match_all('/<(.*?)>/', $string, $emails)) {
array_shift($emails); // Take the first match (the whole string) off the array
}
// $emails is now an array of emails if any exist in the string
The parentheses tell it to capture for the $matches array. The .* picks up any characters and the ? tells it to not be greedy, so the > isn't picked up with it.
I'm Stuck try to get domain using preg_replace,
i have some list url
download.adwarebot.com/setup.exe
athena.vistapages.com/suspended.page/
prosearchs.com/se/tds/in.cgi?4&group=5¶meter=mail
freeserials.spb.ru/key/68703.htm
what i want is
adwarebot.com
vistapages.com
prosearchs.com
spb.ru
any body can help me with preg_replace ?
i'm using this http://gskinner.com/RegExr/ for testing :)
using preg_replace, if the number of TLDs is limited:
$urls = array( 'download.adwarebot.com/setup.exe',
'athena.vistapages.com/suspended.page/',
'prosearchs.com/se/tds/in.cgi?4&group=5¶meter=mail',
'freeserials.spb.ru/key/68703.htm' );
$domains = preg_replace('|([^.]*\.(?:com|ru))/', '$1', $urls);
matches everything that comes before .com or .ru which is not a period. (to not match subdomains)
You could however use PHPs builtin parse_url function to get the host (including subdomain) – use another regex, substr or array manipulation to get rid of it:
$host = parse_url('http://download.adwarebot.com/setup.exe', PHP_URL_HOST);
if(count($parts = explode('.', $host)) > 2)
$host = implode('.', array_slice($parts, -2));
Following code assumes that every entry is exactly at the beginning of the string:
preg_match_all('#^([\w]*\.)?([\w]*\.[\w]*)/#', $list, $m);
// var_dump($m[2]);
P.S. But the correct answer is still parse_url.
Why use a regular expression? Of course it is possible, but using this:
foreach($url in $url_list){
$url_parts = explode('/', $url);
$domains[] = preg_replace('~(^[^\.]+\.)~i','',$url_parts[0]);
}
$domains = array_unique($domains);
will do just fine;
maybe a more generic solution:
tested by grep, I don't have php environment, sorry:
kent$ echo "download.adwarebot.com/setup.exe
dquote> athena.vistapages.com/suspended.page/
dquote> prosearchs.com/se/tds/in.cgi?4&group=5¶meter=mail
dquote> freeserials.spb.ru/key/68703.htm"|grep -Po '(?<!/)([^\./]+\.[^\./]+)(?=/.+)'
output:
adwarebot.com
vistapages.com
prosearchs.com
spb.ru
I need to get the ID part of a pastebin link,
which is setup like http://pastebin.com/{id}, i have tired alot of different regex i am also using preg_match in php
preg_match("~http://pastebin.com/([0-9a-zA-Z]+)~", $url, $match);
print_r($match);
or
$url = "http://pastebin.com/a65d46";
$parsed = parse_url($url);
echo trim($parsed['path'])." is ID you needed";
Instead of regex, try using parse_url to extract the path
regex would be overkill for this.
$url = "http://pastebin.com/Ugj1eqCN"
$pos = strpos($url,"pastebin.com/");
echo substr($url,$pos+13);