I am merging the form with another form contains table based. Table contains the list with checkbox, after filling the form fields, checkboxes are selected and submitted.
When i write this code, Two forms with same id is generated how should i merge the two functions in one form.
function add_newHardware() {
$output = drupal_get_form('add_new_form');
return $output;
}
function add_new_form(&$form_state) {
$form['#attributes']['id'] = 'myform';
$form['device'] = array(
'#type' => 'fieldset',
'#collapsible' => FALSE,
'#collapsed' => FALSE,
);
$form['device']['type'] = array(
'#type' => 'select',
'#options' => listType(),
);
$form['device']['title'] = array(
'#type' => 'item',
'#value' => '<h4>2. Enter Information</h4>',
);
$form['table'] = array(
'#type' => 'item',
'#value' => drupal_get_form('selectList'),
);
}
function selectList() {
$form['#attributes']['id'] = 'myform';
......
$output .= theme('table', $header, $rows);
$output .= drupal_render($form);
return $output;
}
Related
I would like to be able to count the number of text inputs that have been filled and use the result to create a drop down with the options 0-[count returned]. I am using the
ajax_command_replace function in Drupal 7 but open to suggestions of any other method.
I have a test which does count the inputs filled and displays the result but I cannot figure out how to then use this to populate a select.
Any help much appreciated.
for the form elements.
$array = array_fill(0,5,'');
$form['test'] = array(
'#type'=> 'fieldset',
'#title' => 'TEST',
);
$form['test']['value']['#tree'] = TRUE;
foreach ($array as $key => $value) {
$form['test']['value'][$key] = array(
'#type' => 'textfield',
'#ajax' => array(
'callback' => 'test_callback',
),
);
}
$test = count(array_filter($array));
$form['test']['count'] = array(
'#suffix' => "<div id='testcount'>filled inputs = $test</div>",
);
and the ajax callback
function test_callback($form, $form_state){
$text = count(array_filter($form_state['input']['value']));
$commands = array();
$commands[] = ajax_command_replace("#testcount", "<div id='testcount'>filled inputs = $text</div>");
return array('#type' => 'ajax', '#commands' => $commands);
}
Thanks
This seems to be working for me now, same method but using the render() function to return an updated form element from within the callback. I hope it helps someone else.
$array = array_fill(0,5,'');
$form['test'] = array(
'#type'=> 'fieldset',
'#title' => 'TEST',
);
$form['test']['value']['#tree'] = TRUE;
foreach ($array as $key => $value) {
$form['test']['value'][$key] = array(
'#type' => 'textfield',
'#ajax' => array(
'callback' => 'test_callback',
),
);
}
$options = range(count(array_filter($array)),0,1);
$form['test']['count'] = array(
'#type'=> 'select',
'#options' => $options,
'#prefix' => '<div id="testcount">',
'#suffix' => "</div>",
);
Callback
function test_callback($form, $form_state){
$text = count(array_filter($form_state['input']['value']));
$default = $form_state['input']['count'];
$options = range($text,0,1);
$form['test']['count'] = array(
'#type'=> 'select',
'#options' => $options,
'#prefix' => '<div id="testcount">',
'#suffix' => "</div>",
'#default_value' => $default,
);
$commands = array();
$commands[] = ajax_command_replace("#testcount", render($form['test']['count']));
return array('#type' => 'ajax', '#commands' => $commands);
}
I have a query which I want shown as a Drupal tableselect with sorting and pagination and search term which is memorized in the $_SESSION. The problem is that the pagination is not working.
My code looks kinda like this:
//build the header row (except the checkbox)
$header = array(
'status' => array('data' => t('Status')),
'name' => array('data' => t('Product name'), 'field' => 'p.name'),
'actions' => array('data' => t('Actions'))
);
//do the query for the data
$query = db_select('my_products', 'p');
$query->addField('p', 'pid');
$query->addField('p', 'name');
$query->addField('p', 'status');
//in case there is a search term then filter the table
if(isset($_SESSION['search_term_product'])) {
$query->condition('p.name', '%' . db_like($_SESSION['search_term_product']) . '%', 'LIKE');
}
//add a pager to the resulting data and a sorter
$query->extend('PagerDefault')
->limit(10);
->extend('TableSort')
->orderByHeader($header);
$result_set = $query->execute();
//structure the data accordingly
$rows = array();
$default_value = array();
foreach($result_set as $product) {
$default_value[$product->pid] = $product->status == 1 ? TRUE : FALSE; //ticked or not tiked
$rows[$product->pid] = array(//array key is needed for form submission
'status' => $product->status == 1 ? t('Active') : t('Not active'),
'name' => array(
'data' => array(
'#type' => 'link',
'#title' => $product->name,
'#href' => $base_url . '/' . $product->name . '/edit'
)
),
'actions' => array(
'data' => array(
'#type' => 'link',
'#title' => 'Delete',
'#href' => $base_url . '/' . $product->name . '/delete'
)
)
);
}
//configure the table
$form['products'] = array
(
'#type' => 'tableselect',
'#header' => $header,
'#options' => $rows,
'#empty' => t('No products found'),
'#multiple' => TRUE, //TRUE -> checkboxes FALSE-> radio buttons
'#default_value' => $default_value,
'#markup' => theme('pager')
);
$form['submit'] = array
(
'#type' => 'submit',
'#value' => t('Change status'),
);
return $form;
I tried lots of solutions and searched the web extensively but I don't know why the pagination isn't working. This code just shows all the result like my pagination code wasn't even there.
Any suggestions?
Edit: In my original code I have a few joins.
After many many tries I managed to solve it. I think there's a problem if you add the ->extend('PagerDefault') after a join. Anyway all you have to do is change
db_select('my_products', 'p');
to
db_select('my_products','p')->extend('PagerDefault')->extend('TableSort');
$query->extend('PagerDefault')
->limit(10);
->extend('TableSort')
->orderByHeader($header);
to
$query->limit(10)
->orderByHeader($header);
delete the line with '#markup' => theme('pager') and before return $form add
$form['pager'] = array(
'#markup' => theme('pager')
);
I have the form in drupal7.
What i need is: i have category and sub category . I have to list these in checkboxes like
I used the code as
$form['rate_the_room']['talent'] = array(
'#prefix'=>'<h1>category:</h1>',
'#type' => 'checkboxes',
'#options' => $sub_tal,
);
Here $sub_tal is an array. If it is the single dimensional array it works fine. Here how to pass an array(The category , sub categories are came from db). How to maintain this structure with this code.
Please help me thanks.
Is there any particular reason why these all need to be in one form element? If your data is set up properly, you can simply loop through them and create elements in a somewhat organized fashion.
function my_test_form($form_state) {
// Assuming you have your data in a format like this
$categories = array(
'cat1' => array(
'#title' => 'category 1',
'sub1' => 'Subcat1',
'sub2' => 'Subcat2',
),
'cat2' => array(
'#title' => 'category 2',
'sub21' => 'Subcat21',
'sub22' => 'Subcat22',
),
'cat3' => 'category 3',
);
$elements = array();
foreach ($categories as $cat => $data) {
// If multidimensional, create parent and loop through children
if (is_array($data)) {
$elements[] = array(
'#type' => 'checkbox',
'#title' => $data['#title'],
'#return_value' => $cat,
);
foreach (element_children($data) as $subcat) {
$elements[] = array(
'#type' => 'checkbox',
'#title' => $data[$subcat],
'#attributes' => array(
'style' => 'margin-left: 2em',
),
'#return_value' => $cat . '-' . $subcat,
);
}
}
// Else, just create top level
else {
$elements[] = array(
'#type' => 'checkbox',
'#title' => $data,
'#return_value' => $cat,
);
}
}
// Group all of these elements together. They'll be submitted into the same array.
$form['categories'] = $elements;
$form['categories']['#tree'] = TRUE;
$form['categories']['#prefix'] = '<div style="font-weight:bold" class="label">' . t('Checkboxes title') . ':</div>';
$form['submit'] = array(
'#value' => t('Submit me'),
'#type' => 'submit',
);
return $form;
}
function my_test_form_submit($form, &$form_state) {
$submitted_values = array_filter($form_state['values']['categories']);
}
Renders as:
And when the form is submitted, assuming some checkboxes were checked, $submitted_values looks like this:
array('cat2', 'cat2-sub21', 'cat2-sub22')
You can change the values of the checkboxes submitted to the submit handler by changing the #return_value attribute that I set on each checkbox above.
The submitted values are grouped together not only because they are all within the $form['categories'] section, but also because #tree is set to TRUE.
Is it possible to add additional form elements in the validate or submit functions in drupal 7 module? The following code works and image is displayed on the form:
function test1_form($form, &$form_state)
{
$form['image']=array(
'#markup'=>'<img src="sites/all/modules/create_ad/th.jpeg"><br/>', //replace with your own image path
);
$form['submit'] = array(
'#type' => 'submit',
'#value' => 'Submit',
);
}
but when I try to display image after submission in submit function like following, it doesn't work:
function test1_form($form, &$form_state)
{
$form['submit'] = array(
'#type' => 'submit',
'#value' => 'Submit',
);
}
function test1_form_submit($form,&$form_state)
{
$form['image']=array(
'#markup'=>'<img src="sites/all/modules/create_ad/th.jpeg"><br/>', //replace with your own image path
);
}
Any positive help is welcome. Thanks.
You could follow the multi-step form methodology to add additional fields to your form after submission.
Here is a blog post that talks about one approach for multi-step and can give you some insight.
Basically, on your submit function you store your values and set the form to be rebuilt. Then in your form function you check for those stored values and add the new fields if present.
Example:
<?php
function test1_form($form, &$form_state)
{
if (isset($form_state['storage']['show-image'])){
$form['image']=array(
'#markup'=>'<img src="sites/all/modules/create_ad/th.jpeg"><br/>', //replace with your own image path
);
}
$form['submit'] = array(
'#type' => 'submit',
'#value' => 'Submit',
);
}
function test1_form_submit($form,&$form_state)
{
$form_state['rebuild'] = TRUE;
$form_state['storage']['show-image'] = true;
}
Here is another way of doing this with Ajax. This way you will not get any page reload since only the image will be loaded in to the div with wrapper id.
Here is the code:
function test_menu()
{
$items = array();
$items['test'] = array(
'title' => 'test',
'page callback' => 'drupal_get_form',
'page arguments' => array('test1_form'),
'access callback' => array(TRUE),
'type' => MENU_CALLBACK,
);
return $items;
}
function test1_form($form, &$form_state)
{
$form['submit'] = array(
'#type' => 'button',
'#value' => t('Submit'),
'#name' => 'add',
'#ajax' => array(
'callback' => 'ajax_load_picture_callback',
'wrapper' => 'wrapper',
'method' => 'replace',
'effect' => 'fade',
),
);
$form['image'] = array(
'#markup' => '',
'#prefix' => '<div id="wrapper">',
'#suffix' => '</div>',
);
if (array_key_exists('triggering_element', $form_state) &&
array_key_exists('#name', $form_state['triggering_element']) &&
$form_state['triggering_element']['#name'] == 'add')
{
$form['image']['#markup'] ='<img src="themes/bartik/logo.png"><br/>'; //replace with your own image path
}
return $form;
}
function ajax_load_picture_callback($form, $form_state)
{
return $form['image'];
}
function test1_form_submit($form, &$form_state)
{
}
I am struggling in my attempts to programmatically display a form to display in my node-page view area. I have the following code in my "simplemodule".
function simplemodule_newcomer_form($form_state){
$form = array();
$form['simplemodule_newcomer']['name'] = array(
'#type' => 'textfield',
'#title' => t('name'),
'#description' => t(''),
'#weight' => -1,
);
$form['simplemodule_newcomer']['email'] = array(
'#title' => t('email'),
'#type' => 'textfield',
'#description' => t(''),
'#weight' => 0,
);
$form['simplemodule_newcomer']['phone'] = array(
'#title' => t('telephone No.'),
'#type' => 'textfield',
'#description' => t(''),
'#weight' => 0,
);
$form['submit_button'] = array(
'#type' => 'submit',
'#value' => 'enter',
);
return $form;
}
function simplemodule_newcomer_form_submit($form_id, &$form_state){
//dealing with submitted data
}
This code works but only from a defined link in my administration menu.
What I want to do is get the form to display and submit on a specific node in view mode. So it creates the effect that there is a form to fill when visiting the node.
You can implement hook_nodeapi() and attach your form using drupal_get_form():
function simplemodule_nodeapi(&$node, $op, $a3 = NULL, $a4 = NULL) {
if ($node->nid == $the_nid && $op == 'view') {
$node->content['my_additional_field'] = array(
'#value' => drupal_get_form('simplemodule_newcomer_form'),
'#weight' => 10,
);
}
}
You can use the #weight key to specify where in relation to the other content on the page your form will appear. Also you'll need to clear Drupal's caches when you implement this hook to make sure it's picked up.
Surely you can use
hook_form_alter(&$form, &$form_state, $form_id) and
hook_nodeapi(&$node, $op, $teaser = NULL, $page = NULL)
http://api.drupal.org/api/drupal/modules--system--system.api.php/function/hook_form_alter/7
http://drupal.org/node/1011692