i have a wordpress inside Public html folder on server.
i want to dispaly images from the folder Public_html--->Trial-->Wordpress_site-->uploads
below is page.php code
<?php
$directory = dirname(__FILE__).'/uploads';
echo $directory;
try {
// Styling for images
foreach ( new DirectoryIterator("/" . $directory) as $item ) {
if ($item->isFile()) {
echo "<div class=\"expand_image\">";
$path = "/" . $directory . "/" . $item;
echo $path;
echo "<img src=/"". $path . "\" width=861 height=443 />";
echo "</div>";
}
}
}
catch(Exception $e) {
echo 'No images found for this player.<br />';
}
?>
The images arent getting displayed..
anyone knows about the same??
edit1
I think there is problem in this sentence
echo "<img src=/"". $path . "\" width=861 height=443 />";
is it?
edit2
//home/softwar2/public_html/Pradnnya_blog/wordpress_site/wp-content/themes/deep-red/our_results/4thpanelfinal.jpg
is the path that i get when echoed.
__FILE__ gives you the path of the current file on the filesystem; however, when you visit the webpage and you see a link in the tag, you'll try to access that as a URL instead of a file. For this, you might find $_SERVER['PHP_SELF'] useful, or another one of the $_SERVER elements. It might be better to have the URL in a configuration file though, because $_SERVER may sometimes not be set.
Good catch, there's a bit of a syntax error:
echo "<img src=\"". $path . "\" width=861 height=443 />";
You'll want to use the backslash to escape the double quote.
Related
i am coding a simple doc managing script and need to get the file size and file type /file or folder/ in a table. somehow it doesn't work into the mention directory. please help if possible:
<?php
$path = "./documents";
$dh = dir($path);
while( ($file=$dh->read()) )
{
if( $file=="." || $file=="..")continue;
echo "<tr><td><a href='download.php?f=$file' title='Click to Open/Download'>$file</a></td>";
echo "<td>";
echo (is_file($file))? "<img src='file.jpg'/> FILE" : "<img src='folder.jpg'/> FOLDER ";
echo "</td><td>" .filesize($file)."</td>";
echo "<td><input type='checkbox' name='delete[]'/></td></tr>";
}
?>
it does actually has 2 errors - one the file size doesn't work for the location, if i change it to path to "." - everything is ok, but if i try to change to the folder where i need it /documents ...all goes bad, and secondly - it doesn't take the right icon file as well, same type of problem.
thank you
Problem is, $file is only the filename without the directory prefix, so checking on it won't work. One way would be to have a variable with the absolute filename (say $realfile). You'd then have to alter your code and use this variable for the file checks:
<?php
$path = "./documents";
$dh = dir($path);
while(($file=$dh->read()) !== false) {
if( $file=="." || $file=="..") continue;
// have a new variable for the real filepath
$realfile = $path . "/" . $file;
echo "<tr><td><a href='download.php?f=$file' title='Click to Open/Download'>$file</a></td>";
echo "<td>";
echo (is_file($realfile))? "<img src='file.jpg'/> FILE" : "<img src='folder.jpg'/> FOLDER ";
echo "</td><td>" .filesize($realfile)."</td>";
echo "<td><input type='checkbox' name='delete[]'/></td></tr>";
}
?>
If anyone still encounters this error and the top answer didn't work for you. Then it must be because there is a special character in your filepath i.e. \r or \n
Try:
$f = str_replace(Array("\n", "\r", "\n\r"), '', $f);
This is a common problem for reading content on a file.
I am reading a folder with glob() function in php
foreach (glob("folder/*.*") as $filename) {
echo $filename."<br />"
}
My folder contains three kind of files pdf, image, videos. What I need here is to make a link for each file and open them on click.
How can I achieve this, any ideas?
This should work for you:
(This creates you a list of all files which you can click on it and you get it opened in the new tab)
$files = glob("folder/*.*");
foreach($files as $file)
echo "<a href='" . $file . "' target='_blank'>" . $file . "</a><br />";
i have this code to display images, where each user has his own, i'll comment it to save your time
<?php
session_start();
$name=$_SESSION['valid_user']; //saved current username in variable
$loc="./uploads/"; //location of image directory
$path=$loc.$name; //current user's folder to save his images
echo $path."<br>"; //i used this to make sure the path is ok, only for testing
if(is_dir($path)) //if directory exists, show it exists,otherwise show it
{ //doesnt exists
echo "<br>exists";
}
else
{
echo "<br>not exists";
}
$files = glob($path."/");
for ($i=1; $i<count($files); $i++)
{
$num = $files[$i]; //picture number
print $num."<br />";
echo '<img src="'.$path.'" alt="random image" height="100" width="100"/>'."<br /><br />";
} //shows the picture till the last one
?>
the output that i get is this this
./uploads/user_name
exists
but it does not show the images, even though the folder is not empty (upload script works fine).
EDIT; solved it (low rep, cant answer my own question).
got it. For anyone who cares, this line here
echo '<img src="' . $path . '/' . $files[$i] . '" <!-- etc --> />';
wasn't working because i added $files, which already contained the path, and it was giving input to img src as
/uploads/username/uploads/username
so that was two times the same path.Upon removing $path, and using just
<img src="' . $files[$i] . '"
did the trick. Thank you all for your help.
I think you need to pass a wildcard path to glob: glob($path . '/*'). You are also not printing the filename in the image source attribute:
echo '<img src="' . $path . '/' . $files[$i] . '" <!-- etc --> />';
Also, your $num is actually the filename, not the picture number - that is $i. You could really simplify that loop using the foreach construct:
foreach($files as $filename) {
// etc
}
you need to add a pattern for using glob afaik
$files = glob($path."/*.*"); // all files
$files = glob($path."/*.jpg"); // all jpgs etc.pp
foreach($files as $idx => $file)
{
$num = $idx+1; //idx starts with 0 so we add one here
print $num."<br />";
echo '<img src="'.$path.'/'.$file'" alt="random image" height="100" width="100"/>'."<br /><br />";
}
Hi I am trying to get images to load into a page using the file names from an array,
This is what I have so far
<?php
$i=0;
$img=array("1.png","2.png","3.png","4.png");
while ($i<count($img))
{
echo "<img class='loadin' alt='imgg' src=" . "'http://www/images/" . $img[i] . "'" . "/" . ">" . "<br/>";
$i++;
}
?>
It seems to ignore the file name and just enters:
http://www/images/
as the source and ignores the file name from the array
Any Help would be great Thanks
Mikey
You forgot the dollar sign with your $i variable: $img[$i]
EDIT:
(btw. using a foreach-loop would be easier...)
foreach($img AS $filename) {
echo "<img class='loadin' alt='imgg' src='http://www/images/" . $filename . "'/><br/>";
}
I have the code below
<?php
$directory = 'images/slideshow';
try {
// Styling for images
echo '<div id="myslides">';
foreach ( new DirectoryIterator($directory) as $item ) {
if ($item->isFile()) {
$path = $directory . '/' . $item;
echo '<img src="' . $path . '"/>';
}
}
echo '</div>';
}
catch(Exception $e) {
echo 'No images found for this slideshow.<br />';
}
?>
copied from this topic:
Display Images From A Folder (slideshow)
I would like to know if its possible to load the images externally instead, or from a specific directory of a URL? Thanks in advance.
It is possible, but you would need to know the urls of each photo. Though that would be easy if you can make them follow a certain pattern I.e. www.example.com/dir/photo1, www.example.com/dir/photo2.
The external server you point must allow remote linking as well.
Then it's just a matter of making the links:
for ($i = 1; $i < NUMBER_OF_PHOTOS; ++$i) {
echo '<img src="http://www.example.com/dir/photo'.$i.'"/>';
}