This question already has an answer here:
Closed 10 years ago.
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Finetune Regex to skip tags
Currently my function looks like this. It converts plain text URLs into HTML links.
function UrlsToLinks($text){
return preg_replace('#(https?://([-\w\.]+)+(:\d+)?(/([\w/_\.-]*(\?\S+)?)?)?)#', '$1', $text);
}
But there are some problems. What I'm trying to do is skip existing links, the src attribute in <img> tags, etc.. Can't figure out what I need to modify in this function.
This would work, assuming that the URLs we want to replace are not already inside a tag.
function UrlsToLinks($text){
$matches = array();
$strippedText = strip_tags($text);
preg_match_all('#(https?://([-\w\.]+)+(:\d+)?(/([\w/_\.-]*(\?\S+)?)?)?)#', $strippedText, $matches);
foreach ($matches[0] as $match) {
if (filter_var($match, FILTER_VALIDATE_URL)) {
$text = str_replace($match, ''.$match.'', $text);
}
}
return $text;
}
Related
This question already has answers here:
How to remove the querystring and get only the URL?
(16 answers)
Closed 2 years ago.
I would like to remove anything that follows after a specific set of characters (i.e. filetypes / extensions). I have tried numerous scripts I found online, but none really manage to do what I need, they either remove the file extension as well, or keep parts of the arguments that follow.
$urls = array(
'http://www.example.com/images/image1.jpg',
'http://www.example.com/images/image2.png?arg=value',
'http://www.example.com/images/image3.jpg?foo=bar',
'http://www.example.com/images/image4.gif?v=1',
'http://www.example.com/images/image5.bmp?x=y',
'http://www.example.com/images/image6.tiff?werdfs=234234'
);
Desired outcome:
http://www.example.com/images/image1.jpg
http://www.example.com/images/image2.png
http://www.example.com/images/image3.jpg
http://www.example.com/images/image4.gif
http://www.example.com/images/image5.bmp
http://www.example.com/images/image6.tiff
Maybe this one help you.
$re = '/^.*(?:\.)[a-zA-Z]+/m';
$urls = array(
'http://www.example.com/images/image1.jpg',
'http://www.example.com/images/image2.png?arg=value',
'http://www.example.com/images/image3.jpg?foo=bar',
'http://www.example.com/images/image4.gif?v=1',
'http://www.example.com/images/image5.bmp?x=y',
'http://www.example.com/images/image6.tiff?werdfs=234234',
'asdasd'
);
foreach ($urls as $url) {
preg_match($re, $url, $matches);
if ($matches) {
echo $matches[0];
echo "\n";
}
}
Output
http://www.example.com/images/image1.jpg
http://www.example.com/images/image2.png
http://www.example.com/images/image3.jpg
http://www.example.com/images/image4.gif
http://www.example.com/images/image5.bmp
http://www.example.com/images/image6.tiff
How about PHP's parse_url() and basename?
$inName = $urls[0]; // for example
$newName = parse_url($inName,PHP_URL_SCHEME)
. parse_url($inName,PHP_URL_HOST)
. parse_url($inName,PHP_URL_PATH)
. basename($inName);
This question already has answers here:
Extracting all values between curly braces regex php
(3 answers)
Closed 3 years ago.
so I have this email template that consist of something of a template strings
<p>My name is {name}</p>
that later on, when I trigger email function, I can just do file_get_contents and use str_replace to replace that part with the correct value
$temp = file_get_contents(__DIR__.'/template/advertise.html');
$temp = str_replace('{img}','mysite.com/assets/img/face.jpg',$temp);
Now what wanted this time is to get those word inside {} and append to an array $words = [];
What I've tried is using explode technique e.g.
$word = 'Hello {img}, age {age}, I live in {address}';
$word = explode('}',$word);
$words = [];
foreach( $word as $w ){
$words[] = explode('{',$w)[1];
}
print_r($words);
but is there other better way to do this? any ideas, help?
Try the following:
$word = 'Hello {img}, age {age}, I live in {address}';
if (preg_match_all('/\{([^\}]+)\}/', $word, $matches, PREG_PATTERN_ORDER)) {
var_dump($matches[1]);
}
It should return all the variable names inside the curly braces.
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Closed 3 years ago.
Improve this question
[i][b][i][b](This is a paragraph with BBcode.)[/b][/i][/b][/i]
Some of my BB code has double tags, whats the best way to remove this?
I've tried a few things mostly regex, but I'm honestly a novice when it comes to regex.
This is absolutely horrible, but it works.
<?php
$bb = '[i][b][i][b](This is a paragraph with BBcode.)[/b][/i][/b][/i]';
// regex with start, paragraph, and end capture groups
$regex = '#(?<start>(\[[a-z]*\])*+)(?<paragraph>.*)(?<end>(\[\/[a-z]*\])*+)#U';
// put matches into $matches array
preg_match_all($regex, $bb, $matches);
// get the stuff we need
$start = $matches['start'][0]; // string(12) "[i][b][i][b]"
$paragraph = implode('', $matches['paragraph']);
// now we will grab each tag
$regex = '#\[(?<tag>[a-z])\]#';
preg_match_all($regex, $start, $matches);
$tags = array_unique($matches['tag']);
// and build up the new string
$newString = '';
foreach($tags as $tag) {
$newString .= '[' . $tag . ']';
}
// create the end tags
$end = str_replace('[', '[/', $newString);
// put it all together
$newString .= $paragraph . $end;
echo $newString; // [i][b](This is a paragraph with BBcode.)[/i][/b]
Which gives you [i][b](This is a paragraph with BBcode.)[/i][/b]
Check it here https://3v4l.org/O8UHO
You can try to extract all the tags with a regexp (maybe like /\[.*\]/U) and then iterate throught them, removing all the duplicates
Quick example :
$bb = '[i][b][i][b](This is a paragraph with BBcode.)[/b][/i][/b][/i]';
preg_match_all('/(\[.*\])/gU', $bb, $tags);
$metTags = [];
foreach($tags[0] as $tag) {
// tag has not been met, save it
if (in_array($tag, $metTags) === false) {
$metTags[] = $tag;
// tag have been met already
} else {
// remove it ONCE
$bb = preg_replace('#'.preg_quote($tag).'#', '', $bb, 1);
}
}
echo $bb;
That is probably not the best solution due to preg_replace() use, but still doing the job great.
Edit : add code
So i wrote a long winded method in php only. It basically loops through all the characters, then i when i find an "[" i check the rest for accepted tags. I end up with an array of all the styles and just text allowing me to remove the duplicate styles. Would show code but dont want to get laughed at :D
This question already has answers here:
how to extract links and titles from a .html page?
(6 answers)
Closed 3 years ago.
Hi know there's already a lot of question about this so far. But I've tried a lot of them and can't get it quite where I need it.
I need a regex that will extract a youtube url from a string that contains an iframe.
Sample text:
<p>
</p><p>Garbage text</p><p><iframe width="560" height="315" src="//www.youtube.com/embed/PZlJFGgFTfA" frameborder="0" allowfullscreen=""></iframe></p>
Here's the regex I come up with :
(\bhttps?:)?\/\/[^,\s()<>]+(?:\([\w\d]+\)|(?:[^,[:punct:]\s]|\/))
Regex101 test
I'm using it on a function and it returned an empty array. Do someone have an idea what's wrong with my function ?
function extractEmbedYT($str) {
preg_match('/(\bhttps?:)?\/\/[^,\s()<>]+(?:\([\w\d]+\)|(?:[^,[:punct:]\s]|\/))/', $str, $matches, PREG_OFFSET_CAPTURE, 0);
return $matches;
}
EDIT 1 : Changed capture group in my regex so it don't capture last the last char
EDIT 2 : Added some PHP Code to put in context, since it's working in Regex101 but not on my script.
You need to convert the capturing group to a non-capturing one:
/(\bhttps?:)?\/\/[^,\s()<>]+(?:\(\w+\)|(?:[^,[:punct:]\s]|\/))/s
^^^
Also, in the code, you need to pass $string to the function, not $str:
function stripEmptyTags ($result)
{
$regexps = array (
'~<(\w+)\b[^\>]*>([\s]| )*</\\1>~',
'~<\w+\s*/>~',
);
do
{
$string = $result;
$result = preg_replace ($regexps, '', $string);
}
while ($result != $string);
return $result;
}
function extractEmbedYT($str) {
// Find all URLS in $str
preg_match_all('/(\bhttps?:)?\/\/[^,\s()<>]+(?:\(\w+\)|(?:[^,[:punct:]\s]|\/))/s', $str, $matches);
// Remove all iframes from $str
$str = preg_replace('/<iframe.*?<\/iframe>/i','', $str);
$str = stripEmptyTags($str);
return [$str, $matches[0]];
}
$string = '<p>
</p><p>UDA Stagiaire</p><p><iframe width="560" height="315" src="//www.youtube.com/embed/PZlJFGgFTfA" frameborder="0" allowfullscreen=""></iframe></p>';
$results = extractEmbedYT($string);
print_r($results);
See the online PHP demo.
This question already has answers here:
calling function inside preg_replace thats inside a function
(2 answers)
Closed 8 years ago.
I'm trying to come up with a way to find all RegEx matches in a string, then run all of those matches through a function that I've written, but I'm having no luck.
Specifically, I'm trying to find all email addresses in a string and then use a function to convert those addresses into useful mailto links that hide the addresses from spam bots.
So I start with plain old RegEx to turn the addresses into mailto links, just so I know that the matches are working.
$pattern = '#([0-9a-z]([-_.]?[0-9a-z])*#[0-9a-z]([-.]?[0-9a-z])*\\.[a-wyz][a-z](fo|g|l|m|mes|o|op|pa|ro|seum|t|u|v|z)?)#i';
$replacement = "<a href='mailto:\\1'>\\1</a>";
$description = preg_replace($pattern, $replacement, $description);
Works great. So far, so good. But when I try to use my function to manipulate the address string, email addresses are no longer matched.
$pattern = '#([0-9a-z]([-_.]?[0-9a-z])*#[0-9a-z]([-.]?[0-9a-z])*\\.[a-wyz][a-z](fo|g|l|m|mes|o|op|pa|ro|seum|t|u|v|z)?)#i';
$replacement = myFunction('\\1');
$description = preg_replace($pattern, $replacement, $description);
What am I doing wrong?
$description = preg_replace_callback($pattern, 'myFunction', $description);
Check preg_replace_callback() on manual to understand how it works.
Your myFunction() function should be coded like that:
function myFunction($matches)
{
return sprintf('%s', $matches[1], $matches[1]);
}
Using preg_replace_callback() with a closure (PHP 5.3+):
$description = preg_replace_callback($pattern, function ($matches) {
return myFunction($matches[1]);
}, $description);