I have a strange problem . I am trying to insert some values to database with respective date . In HTML form, the date format is mm/dd/yyyy format. I converted this format to mysql yyyy-mm-dd format using the following PHP (from stackoverflow answer):
echo $date1 = str_replace("/","-",$_POST['date']);
echo $date = date('Y-m-d', strtotime($date1));
But the above echo , when I run the code it shows like this:
07-30-2012 1970-01-01
Dates in the m/d/y or d-m-y formats are disambiguated by looking at the separator between the various components: if the separator is a slash (/), then the American m/d/y is assumed; whereas if the separator is a dash (-) or a dot (.), then the European d-m-y format is assumed. See http://php.net/manual/en/function.strtotime.php for details.
So even you are passing '07-30-2012' as an input, it is considering 07 as date, 30 as month hence you are getting incorrect results.
Following should work
echo $date = date('Y-m-d', strtotime($_POST['date']));
echo $date = preg_replace('/^(\d\d)\/(\d\d)\/(\d{4})$/', '$3-$1-$2', $_POST['date']);
I think this code should work fine, but of course you must do all necessary checks before insert it into database.
echo $date1 = str_replace("/","-","$_POST['date']");
echo $date = date('Y-m-d', strtotime($date1));
put double quotes in date then you get perfect result
I've just tried :
$date = "30/07/2012";
echo $date1 = str_replace("/","-",$date);
echo '<br />';
echo $date = date('Y-m-d', strtotime($date1));
And it's actually returning :
30-07-2012
2012-07-30
You should check your $_POST['date'] format.
echo $date = date('Y-m-d', strtotime($_POST['date']));
Your first line is incorrect, which returns false, which (converted to an integer) is 0, 0 is the beginning of time on a linux machine! (hence 1970-01-01)
Your input is in mm/dd/yyyy format, that means you should use slashes / You would need to change to dashes if you were using dd-mm-yyyy format, as is shown in the answer you link to. So in your case you should not replace the /.
Related
I m trying to add 28 days to the given date and echo, however it is taking the given date and considering it as month and adding the days given
Help me fix the format.
my code goes as:
$start = "04/03/2019";
$nextpay1 = date('d/m/Y',strtotime($start . "+28 days"));
echo $nextpay1;
as result it is echoing "01/05/2019", which is not right..
I'll start my answer by quoting the strtotime docs:
Note:
Dates in the m/d/y or d-m-y formats are disambiguated by looking at
the separator between the various components: if the separator is a
slash (/), then the American m/d/y is assumed; whereas if the
separator is a dash (-) or a dot (.), then the European d-m-y format
is assumed. If, however, the year is given in a two digit format and
the separator is a dash (-), the date string is parsed as y-m-d.
To avoid potential ambiguity, it's best to use ISO 8601 (YYYY-MM-DD)
dates or DateTime::createFromFormat() when possible.
So, in your case:
$date = DateTime::createFromFormat('d/m/Y', '04/03/2019');
$date->modify('+28 days');
echo $date->format('d/m/Y');
The problem is that $start is being parsed in the default mm/dd/yyyy format. You should use a function to parse it as the format you intend, and then add to that.
$parsed = date_parse_from_format('d/m/Y', $start);
$startdate = mktime(
$parsed['hour'],
$parsed['minute'],
$parsed['second'],
$parsed['month'],
$parsed['day'],
$parsed['year']
);
$nextpay1 = date('d/m/Y', strtotime('+28 days', $startdate));
$date=Date('y:m:d', strtotime("+3 days"));
This will save the date after 3 days
Im submitting a form that has a date range picker in it.
I have the code to get the value of the picker from the form, which is in this format:
01/03/2017 - 01/03/2017
I also have it so that it splits the date range into two variables.
$one = 20/01/2017
$two = 13/03/2017
Im now trying to format the date of these variables into the one that MYSQL uses.
My problem is that the end date will fail and be displayed as 1970-01-01 all the time.
// Get the range from the form
$daterange = $_POST["daterange"];
// Split the range into a start and end date
list($one, $two) = explode("-", "$daterange", 2);
// Test the split worked
echo $one;
echo $two;
// Format the start date into MySQL style
$StartDate = date("Y-m-d", strtotime($one));
// Test date
echo $StartDate;
// Format the end date into MySQL style
$EndDate = date("Y-m-d", strtotime($two));
//Test date
echo $EndDate;
Personnaly, I prefer the date_create_from_format that does not presume anything.
One-liner :
$StartDate = date_create_from_format( "d/m/Y" , $one )->format("Y-m-d");
Try this:
$one = '20/01/2017';
$one = str_replace('/', '-', $one);
echo date('Y-m-d', strtotime($one));
// Output: 2017-01-20
Working Code
For the reason, see The PHP Manual for strtotime() Specifically this note
Note:
Dates in the m/d/y or d-m-y formats are disambiguated by looking at the separator between the various components: if the separator is a slash (/), then the American m/d/y is assumed; whereas if the separator is a dash (-) or a dot (.), then the European d-m-y format is assumed. If, however, the year is given in a two digit format and the separator is a dash (-, the date string is parsed as y-m-d.
To avoid potential ambiguity, it's best to use ISO 8601 (YYYY-MM-DD) dates or DateTime::createFromFormat() when possible.
Use this to format your date:
$StartDate = date_format(date_create_from_format('d/m/Y', $one), 'Y-m-d');
To reverse:
$reverse = date('d/m/Y', strtotime($StartDate));
I find a problem related to the date function in php
i want to convert a date '04-08-2016'(mm-dd-yyyy) into a different format '2016-04-08'(yyyy-mm-dd). But it produces the result as '2016-08-04'(yyyy-dd-mm) instead of '2016-04-08'(yyyy-mm-dd).
my code is
$date = '04-08-2016';
echo date('Y-m-d',strtotime($date));
If i place '/' in place of '-' then it is working fine.
Can anyone tell me why this is happening?
You can use the DateTime object:
$date = '04-08-2016';
$d = DateTime::createFromFormat("m-d-Y", $date);
echo $d->format("Y-m-d");
The reason you need to do this is date conventions.
As specified in http://php.net/manual/en/function.strtotime.php
Dates in the m/d/y or d-m-y formats are disambiguated by looking at the separator between the various components: if the separator is a slash (/), then the American m/d/y is assumed; whereas if the separator is a dash (-) or a dot (.), then the European d-m-y format is assumed. If, however, the year is given in a two digit format and the separator is a dash (-, the date string is parsed as y-m-d.
Try this:
$date = '04-08-2016';
$timeArray = strptime($date, '%m-%d-%Y');
$timestamp = mktime(0, 0, 0, $timeArray['tm_mon']+1, $timeArray['tm_mday'], $timeArray['tm_year']+1900);
echo date('Y-m-d', $timestamp);
This allows you to specify the format yourself.
I am writing below code to convert the data to Date.
$date = strtotime($request->input('DueDate'));
$Job->DueDate = date('Y-m-d', $date);
$Job->save();
But this saves the data as 0000-00-00
Try this maybe: (createFromFormat's first argument should be the format which is being received by the user)
$dt = \DateTime::createFromFormat('m/d/Y', strtotime($request->input('DueDate')));
$Job->DueDate = $dt->format('Y-m-d');
$Job->save();
Cheers,,
Let say your DueDate is correctly return the data. Try this:
$date = Carbon::parse($request->input('DueDate'))->format('Y-m-d');
$Job->DueDate = $date;
$Job->save();
Use carbon instance. For more docs Carbon
From the PHP manual for strtotime()
Dates in the m/d/y or d-m-y formats are disambiguated by looking at the separator between the various components: if the separator is a slash (/), then the American m/d/y is assumed; whereas if the separator is a dash (-) or a dot (.), then the European d-m-y format is assumed. If, however, the year is given in a two digit format and the separator is a dash (-, the date string is parsed as y-m-d.
To avoid potential ambiguity, it's best to use ISO 8601 (YYYY-MM-DD) dates or DateTime::createFromFormat() when possible.
So the simplest mod for your situation would be to just convert the slashes to hyphens like this
$fixDate = str_replace('/', '-', $request->input('DueDate'));
$date = strtotime($fixDate);
$Job->DueDate = date('Y-m-d', $date);
$Job->save();
I have a problem with strtotime function in php, i'm trying to convert mm-dd-yyyy to yyyy-mm-dd. The date is entered on the text box and on submit it should save the date to the database. the problem is it returns a wrong date(1970-01-01) each time,which means my code isn't taking the variable i use to store the date, My code is:
//dateconvert
$submitdate = date($_POST['date']);
$date = date("Y-m-d", strtotime($submitdate));
//storeindb
$query ="INSERT INTO ticket SET date = '$date'";
$result = mysql_query($query);
I'm a newbie,please help.
Dates in the m/d/y or d-m-y formats are disambiguated by looking at the separator between the various components: if the separator is a slash (/), then the American m/d/y is assumed; whereas if the separator is a dash (-) or a dot (.), then the European d-m-y format is assumed.
http://php.net/manual/en/function.strtotime.php
You need to use the forward slash separator for mm/dd/yyyy formats.
Use the code as:
$submitdate = $_POST['date'];
$date = date("Y-m-d", strtotime($submitdate));
Hope this hepls.
date format in $submitdate is incorrect Because the format yyyy/mm/dd should be yyyy-mm-dd so you will need to replace your / characters.
Try this:
$submitdate = str_replace("/","-",$_POST['date']);
echo date('Y-m-d', strtotime($submitdate));