I am using codeigniter for my project. To get the uri segments I know I can use
$this->uri->segment();
but my case is a bit different
My url looks like
localhost/mediabox/home/box/21
but once I go to this url a popup form apears in which the user provide a key to access this page and I validate the key using ajax method which is inside my home controller validate_key function
when I echo the url it gives me localhost/home/validate_key
while calling valiate_key of the home controller how can I get the 21 from the url wrritten in the url bar?
Any ideas?
Thanks
The problem:
It's not a bug, it's a natural behavior.
Consider the following:
you request the validate_key function from the server by typing the URL in your address bar. current_url() returns localhost/blabla/validate_key. No AJAX involved.
requesting validate_key with AJAX. The same PHP code will be executed.
the current_url() will change to localhost/blabla/validate_key
even though your browser's address bar is showing localhost/blabla/box/21.
So, what does this means? It means the Codeigniter base_url() doesn't care about your address bar, it cares about the function it is in, whether it was called via ajax or normal request.
so as long this function is being executed, the URL is pointing to it.
The solution:
My favorite solution to such a case, is to simply create a hidden input.
Simply, when a user requests the box function. you're showing him a popup form. so add a hidden_input field, give it a name and a value of 21(depends).
For example(you should tailor this to your specific needs):
Add this to your form in the view that get displayed by the box function:
form_hidden("number", $this->uri->segment(3));;
Now these data will be sent to your validate_key function. How do we access it? It's simple!
function validate_key(){
$this->input->post("number");//returns 21 or whatever in the URL.
//OR if the form sends GET request
$this->input->get("number");//return 21 or whatever in the URL.
/*
*Or , you can do the following it's considered much safer when you're ONLY
*expecting numbers, since this function(intval) will get the integer value of
*the uri segment which might be a destructive string, so if it's a string
*this function will simply return 0.
*/
$number = intval($this->input->post("number"));//returns 21 or whatever in the URL.
//Or if it it GET request:
$number = intval($this->input->get("number"));//returns 21 or whatever in the URL.
}
It looks like you've used .htaccess to remove the index.php part of the url. So, when you navigate to localhost/mediabox/home/box/21 you're passing the value 21 to the function named box in the controller named home
If you want to keep that value within the validate_key function, just pass it through when calling it:
function box($param)
{
//$param = 21
$this->validate_key($param);
}
Its better and suggetsed to use hidden field and post the value when it is needed.
Related
I want pretty url. I access these records using url below. Last segment is index id to access data using it.
http://www.example.com/order/thank_you/344
How can I convert it into
http://www.example.com/order/thank_you
How to implement and also I want last segment in page to access the data using it.
routes.php
$route['order/thank_you/(:num)'] = 'thanks/thank_you/$1';
The left hand side is the URL accessed by the users. And the right hand side is where your request going to.
For example, the request example.com/order/thank_you/344 is going to the function thank_you() of the Controller thanks.
$1 is the argument. If have more than one, just /$1/$2/.
The Controller
public function friends_profile ($id = NULL) {
echo "This is the ID I want to thank to " .$id;
}
The function arguments can be passed directly by the route. $id is the argument passed by the URI.
By the way, check out the Codeigniter URI Routing Guide to get more information.
If you want the url not to contain the id portion you could keep it in a session var and retrieve it at the thank_you method.
For example, I have a page called profile_page.php. This page is only functional if data is written after the ?u= in the URL, for example, data for Alice's profile page can only be seen when the URL reads http://localhost/profile_page/alice.
Loading http://localhost/profile_page will give me undefined variable errors as most of my variable's are depending on the URL to have a value after the ?u=. For example, the variable $firstname can only be gathered when I get her username in the URL.
In such a case, when http://localhost/profile_page, I would rather have it redirect the user to their own profile_page, but I don't know how I can test the URL and parse it through an if statement.
I understand you can use $u=$_GET['u']; to obtain the current page URL? but I don't think doing this, is the best way to go about it:
$u=$_GET['u'];
if ($u == "http://localhost/profile_page/"){
// redirect to logged in users page code here
}
First, if you are using some parameter for your page to build, the url would looks like httlp://localhost/profile_page.php?firstname=alice&lastname=brown, with $_GET['firstname'] you will get alice in this case. If you want to test if the parameter is set first and redirect to another page if it is not set, you could use
if(!isset($_GET['firstname'])
{
header('Location:redirected_page.php');
}
I have a php code sending data to django.
I want django to redirect response to another php page instead of the previous one.
Here is my view which is called from PHP :
def search(request):
arg = { 'Score':clf.predict_proba(my_sample)}
response=redirect('redirected_url.php',arg)
return (HttpResponse(response)
query_arg is a value I want to pass to another php page and show it.
I have tried
return HttpResponseRedirect('redirected_url.php'.arg)
and it did not work either!
How should I proceed?
Best
You can't use redirect with arg as a second parameter in Django. That parameter determines whether it's a permanent redirect or not. Regardless, the *args option there is for extra data to pass to redirect, not for your variables.
If you're redirecting to another page, you need to pass your variables as a query string. For instance, you could pass a variable name when redirecting in Django this way:
return HttpResponseRedirect('redirected_url.php?name=alex')
And then access it from your PHP script via the superglobal $_GET['name'].
I have a listing with some filters which are applied on form submit, using GET as form method. So after submit, I get a url that looks like:
/listing?filter_1=a&filter_2=&filter_3=c
Notice that filter_2 is empty. How can I avoid showing it in the URL in this case? I would only need the URL to be like this:
/listing?filter_1=a&filter_3=c
I would not mess with $_GET and I wonder what is the right way to do it with Laravel 4.
Thank you
During making of url, you need to check the value of variables whether it has empty or null or have some value. Then add those varibale into the url, so that your url will be clean.
to achive this you will be required to use Laravel - pretty URls functionality and make some changes in Route::get function to remove empty parameters while construction url.
I an redirection (in some cases) from a controller to the error controller, action 'not-logged-in' using the redirector helper. My problem is the following: I want to pass an argument in the $_POST array (an URL from where the redirection happened) so the user will be able to return to that page after performing a login.
How can i place data in the $_POST array while using redirect helper?
Thank you ahead.
When you use the redirector with an internal redirect (ie. goToRoute) the paramters are passed along with it. Thus if you add your refferrer to the the request before you actually redirect:
// Assuming $request is a Zend_Controller_Request
$request->setParam('ref', $referrer);
// then use the redirector
then that variable will be passed along with the request upon redirect. So then you would need to check for/grab that variable from the request in the action youve redirected to and then set it as a hidden field in the form. Then when your form posts to your login action you can check again for a ref variable and on successful login redirect to that location.
Now if i were you i would not actually use the referral as the url but a serialized or json encoded array of the previous request's parameters. that way you can use goToRoute in this second instance as well.
Ofcourse if the redirection came form some sort of post action that contained sensitive data you wouldnt want to do this. In that case you would want to use the session as has been previously suggested.
Above all the best advice i can give is to look at the code of Zend_Controller_Router_Rewrite and Zend_Controller_Action_Helper_Redirector.
Not possible without some socket or Curl jiggery pokery.
Why not try using $_SESSION array in the same way?
Does it really matter if the user can see the redirection url in the address bar? i doubt they will care and i see it a few times on some top sites.
Passing control to the login page just feels more like a _forward than a _redirect, like it all belongs under the one action. Especially since you're coming right back.
_forward($action, $controller = null, $module = null, array $params = null)
Then, you can pass your originating location in $params as you'd like.
I'm pretty sure that you can't send POST when redirecting a person to another page. But maybe you can, and if so, I hope somebody proves me wrong here.
I'm not sure how you'd do what you want using Zend Framework, but I would suggest two ways how to do it in general. You can either send a GET variable, or use a session variable to store a back-URL.