php link from mysql - php

Question

I am revisiting php and mySQL from a long time off.
mysql_select_db($database_conn, $conn);
$query = sprintf("SELECT DISTINCT Username FROM Entries ");
$result = mysql_query($query);
$row_results = mysql_fetch_assoc($result);
<?php do {
//$name = $row_results['Username'];
//echo $name, "<br/>";
echo '<a href=\"$row_results['Username'],.php\">';
echo '$row_results['Username'],'s overview </a><br/>';
}
while ($row_results = mysql_fetch_assoc($result)); ?>
What I am trying to do is echo out the link from the results the link is in the form username.php the username is stored in the database.
I have used single quotes and double quotes with escaped /" in but get different errors I know its going to be something as simple as a ; or " .
If you could be as kind to explane what is wrong abd if there is a better way to do this?
The query is correct and the commented out code also works on its own.
Thanks

Answer 1

You cannot parse variables through single quotes:
echo '<a href=\"$row_results['Username'],.php\">';
use
echo '<a href="'.$row_results['Username'].'">';

Answer 2

mysql_select_db($database_conn, $conn);
$query = sprintf("SELECT DISTINCT Username FROM Entries ");
$result = mysql_query($query);
$row_results = mysql_fetch_assoc($result);
<?php do {
//$name = $row_results['Username'];
//echo $name, "<br/>";
echo '<a href="'.$row_results['Username'].'php">';
echo $row_results['Username'].'\'s overview </a><br/>';
}
while ($row_results = mysql_fetch_assoc($result)); ?>

Answer 3

Looks to me like the concatenation of your html string and the username is incorrect.
Currently, your string that you are writing to the page is
<a href=\"$row_results['Username'],.php\">
What you need to be doing is joining the html with the value coming out from the database.
This can be done like so:
echo '<a href=\"'.$row_results['Username'].'.php\">';
echo $row_results['Username'].'\'s overview </a><br/>';
Notice the '.' to concatenate two potions of the string, and the escapement of the apostrophe in the 's

Answer 4

Here are your errors :
Even though you are using DISTINCT in your SQL Query, there might be multiple entries, so you must use a while loop.
You had a comma in there (probably by typo).
You need to escaping the php variable.
So after doing the above, this is what it should be.
while ($row_results = mysql_fetch_assoc($result)) {
echo '<a href="' .$row_results["Username"]. '.php">';
}

Answer 5

try:
echo '<a href="'.$row_results['Username'].'.php">';
echo $row_results['Username'].'\'s overview </a><br/>';

Answer 6

Seems like you got pretty mixed up with the " and ' there. You should really avoid using anything other than ' - it will only bite you on the long run.
Also: You concatenate with ., not with ,.
mysql_select_db($database_conn, $conn);
$query = sprintf('SELECT DISTINCT Username FROM Entries ');
$result = mysql_query($query);
$row_results = mysql_fetch_assoc($result);
do {
$name = $row_results['Username'];
echo $name.'<br/>';
echo '<a href="'.$name.'.php">';
echo $name.'\'s overview </a><br/>';
} while ($row_results = mysql_fetch_assoc($result)); ?>