PHP if statement errmsg - php

Question

I have this if statment
if(!empty($URL) && ($safe===true)){
//lots of code
}
Is it possible to show different error messages depending on what condition failed?
For example if $URL is empty echo "URL empty";
and if $safe===false echo "GTFO";

Answer 1

Just add this to your code
else if(empty($URL)
{
echo "url empty";
}
else if($safe===false)
echo "Get Out"; // be polite ;)

Answer 2

if (empty($url))
{
echo "URL empty";
}
elseif ($safe === false)
{
echo "GTFO";
}
else
{
//lots of code
}

Answer 3

} else {
if($safe === false){
die("GTFO");
}
if (empty($url)){
echo "URL Empty.";
}
}

Answer 4

Yes; you could make use of an else if statement.
if (!empty($URL) && ($safe===true)) {
//lots of code
} else if (empty($URL)) {
// report that url is empty
} else if ($safe === false) {
// report that safe is false
}
Alternatively, you could just use an else statement to report that the if condition was false.

Answer 5

I propose the following solution. It will allow you to show multiple errors and set each condition only once (instead of having so many conditions and anti-conditions as other solutions proposed).
$errors = array();
if(empty($URL) {
$errors[] = 'URL empty';
}
if($safe !== true) {
$errors[] = 'GTFO';
}
if(empty($errors)) {
//lots of code
} else {
echo '<ul>';
foreach($errors as $error_message) {
echo '<li>' . $error_message . '</li>';
}
echo '</ul>';
}