I have two tables in cakePHP.
competencies
------------
id
name
competenceRatings
-----------------
id
competence_id
user_id
rating
I need a way to write the following query in the cake way:
SELECT * FROM competencies WHERE id NOT IN (SELECT competence_id FROM competence_ratings WHERE employee_id = $userId)
Someone please help me!!
What i did before going to this subquery method:
I tried competencies->hasMany->competenceRatings, competenceRatings->belongsTo->competencies relations.
$competencies = $this->Competence->CompetenceRating->find('all',array('CompetenceRating.user_id' => $userId,'CompetenceRating.competence_id !=' => 'Competence.id'));
I want to be able to get the names of competencies for which a user have NOT made any ratings into competenceRatings table. i.e., I need list of names from competencies table for which there are no entries in comptenceRatings table(for given user_id).
EDIT
I tried table join also:
$options['joins'] = array(
array(
'table' => 'competence_ratings',
'alias' => 'CompetenceRating',
'type' => 'LEFT OUTER',
'conditions' => array(
'Competence.id = CompetenceRating.competence_id'
)
)
);
$options['conditions'] = array( 'CompetenceRating.employee_id' => $employee['Employee']['id'] );
$competencies = $this->Competence->find('all',$options);
you would probably have to use a subquery():
$subqueryOptions = array('fields' => array('competence_id'), 'conditions' => array('employee_id'=>$user_id));
$subquery = $this->Competence->CompetenceRating->subquery('all', $subqueryOptions);
$res = $this->Competence->CompetenceRating->find('all', array(
'conditions' => array('id NOT IN '. $subquery)
));
the source for subquery is here:
https://github.com/dereuromark/tools/blob/2.0/Lib/MyModel.php#L405
you need to put this in your AppModel.php
BUT I think the subquery is not necessary. You can probably make a single and easy query out of it:
$this->Competence->CompetenceRating->find('all', array(
'group' => 'competence_id',
'conditions' => array('NOT' => 'employee_id'=>$user_id)),
'contain' => array('Competence')
));
dont forget to include Competence via "contain" if you have recursive set to -1.
Related
can anyone tell me, how to retrieve joined result from multiple tables in cakePHP ( using cakePHP mvc architecture). For example, I have three tables to join (tbl_topics, tbl_items, tbl_votes. Their relationship is defined as following: a topic can have many items and an item can have many votes. Now I want to retrieve a list of topics with the count of all votes on all items for each topic. The SQL query for this is written below:
SELECT Topic.*, count(Vote.id) voteCount
FROM
tbl_topics AS Topic
LEFT OUTER JOIN tbl_items AS Item
ON (Topic.id = Item.topic_id)
LEFT OUTER JOIN tbl_votes AS Vote
ON (Item.id = Vote.item_id);
My problem is I can do it easily using $this-><Model Name>->query function, but this requires sql code to be written in the controller which I don't want. I'm trying to find out any other way to do this (like find()).
$markers = $this->Marker->find('all', array('joins' => array(
array(
'table' => 'markers_tags',
'alias' => 'MarkersTag',
'type' => 'inner',
'foreignKey' => false,
'conditions'=> array('MarkersTag.marker_id = Marker.id')
),
array(
'table' => 'tags',
'alias' => 'Tag',
'type' => 'inner',
'foreignKey' => false,
'conditions'=> array(
'Tag.id = MarkersTag.tag_id',
'Tag.tag' => explode(' ', $this->params['url']['q'])
)
)
)));
as referred to in nate abele's article: link text
I'll be honest here and say that you'll probably be a lot happier if you just create a function in your model, something like getTopicVotes() and calling query() there. Every other solution I can think of will only make it more complicated and therefore uglier.
Edit:
Depending on the size of your data, and assuming you've set up your model relations properly (Topic hasMany Items hasMany Votes), you could do a simple find('all') containing all the items and votes, and then do something like this:
foreach ($this->data as &$topic)
{
$votes = Set::extract('/Topic/Item/Vote', $topic);
$topic['Topic']['vote_count'] = count($votes);
}
Two things are important here:
If you have a lot of data, you should probably forget about this approach, it will be slow as hell.
I've written this from my memory and it might not look like this in real life and/or it may not work at all :-)
You can easily set the "recursive" property on a find() query.
$result = $this->Topic->find('all', array('recursive' => 2));
Alternatively, you can use the Containable behavior in your model. Then you can use:
$this->Topic->contain(array(
'Item',
'Item.Vote',
));
$result = $this->Topic->find('all');
or
$result = $this->Topic->find('all', array(
'contain' => array(
'Item',
'Item.Vote',
),
));
What you need is recursive associations support, which is not possible with stock CakePHP currently.
Although it could be achieved using some bindModel trickery
or an experimental RecursiveAssociationBehavior.
Both of these solutions will either require you to use extra code or rely on a behaviour in your application but if you resist the temptation to write pure SQL code, you'll be rewarded with being able to use Cake`s pagination, auto conditions, model magic etc..
I think this answer is already submitted, but I am posting here for someone who seeks still for this.
The joins can be done with find() method can be like below
$result = $this->ModelName1->find("all",array(
'fields' => array('ModelName1.field_name','Table2.field_names'), // retrieving fileds
'joins' => array( // join array
array(
'table' => 'table_name',
'alias' => 'Table2',
'type' => 'inner',
'foreignKey' => false,
'conditions'=> array('ModelName1.id = Table2.id') // joins conditions array
),
array(
'table' => 'table_name3',
'alias' => 'Table3',
'type' => 'inner',
'foreignKey' => false,
'conditions'=> array('Table3.id = Table2.id')
)
)));
You should study HaBTM (Has and Belongs to Many)
http://book.cakephp.org/2.0/en/models/associations-linking-models-together.html
I have the following problem with CakePHP:
Two tables are joined (filters and accounts). Then I am building conditions and only the second condition Account.active =>1 gets executed. If I print the result, there are still showing filters that are having another mode_id than 3.
$joins= array(
array('table' => 'filters',
'alias' => 'Filter',
'type' => 'right',
'conditions' => array(
'Filter.account_id = Account.id',
)
),
);
Then I execute the request including joins and conditions
$activeAccounts = $this->Account->find('all',array(
'conditions'=>array('AND'=>array('Filter.mode_id'=>3,'Account.active'=>1)),
'joins'=>$joins));
The models were checked and no problems identified. Filter belongs to Account. Account has many Filter.
Below the query that is generated. The results are still showing filters with Filter.mode_id other than 3
Here is the query that is generated. The results are still containing rows with Filter.mode_id other than 3 despite the fact that one condition is 'Filter.mode_id'=>3
SELECT `Account`.`id`, `Account`.`user_id`, `Account`.`name`,
`Account`.`api_key`, `Account`.`account_number`, `Account`.`remaining_balance`,
`Account`.`investment_size`, `Account`.`active`
FROM `baseline_db`.`accounts` AS `Account`
right JOIN `baseline_db`.`filters` AS `Filter`
ON (`Filter`.`account_id` = `Account`.`id`)
WHERE ((`Filter`.`mode_id` = 3) AND
(`Account`.`active` = '1'))
Like say Oldskool, use the Model associations
and for your condition, The "AND" is not necessary,
you cant put :
$activeAccounts = $this->Account->find('all',array(
'conditions' => array(
'Filter.mode_id'=>3,
'Account.active'=>1
)
));
the request you want to make with the type of relation you have, seem to me weird.
If i understand, perhaps with something like that :
$this->loadModel('Filter');
$filters =$this->Filter->find("list", array(
'conditions' => array('Filter.mode_id' => 3),
'fields' => array('Filter.account_id')
));
$activeAccounts = $this->Account->find('all',array(
'conditions' => array(
'Account.account_id'=>$filters,
'Account.active'=>1
)
));
I have two tables: users and posts. I'm trying to select any users that have at least one post.
I'm guessing this require either a join or a subselect. Is there something in CakePHP that makes this simple?
Use counter caching, see http://book.cakephp.org/2.0/en/models/associations-linking-models-together.html#belongsto
counterCache: If set to true the associated Model will automatically
increase or decrease the “[singular_model_name]_count” field in the
foreign table whenever you do a save() or delete(). If it’s a string
then it’s the field name to use. The value in the counter field
represents the number of related rows. You can also specify multiple
counter caches by using an array where the key is field name and value
is the conditions. E.g.:
array(
'recipes_count' => true,
'recipes_published' => array('Recipe.published' => 1) ) counterScope: Optional conditions array to use for updating counter
cache field.
No additional query needed in this case. It will automatically in- and decrease the count in the users table if you add/delete posts.
Example:
public $belongsTo = array(
'User' => array(
'foreignKey' => 'user_id',
'counterCache' => true,
'counterScope' => array(
'published' => 1)));
This should select all users that made 1 post or more
SELECT * FROM `users` as u
INNER JOIN `posts` as p ON p.user_id = u.id
In cake you should be able to do something like this:
$this->User->find('all', array('joins' =>
array(
'table' => 'posts',
'alias' => 'p',
'type' => 'inner',
'conditions' => array(
'User.id = p.user_id'
)
)
);
[EDIT]
Maybe you could add
'group' => 'User.id'
or
'fields' => 'DISTINCT User.id, ...'
To remove duplicates entries
I have a model template which hasmany themes.I want to show the list of templates with count of themes.I am using this
$this->Template->bindModel(
array(
'hasMany' => array(
'TemplateTheme' => array(
'className' => 'TemplateTheme',
'fields' => 'count(TemplateTheme.id) AS themes'
)
)
), false ...
it gives me 2 templates.But it gives me all the 3 themes count in the first template whereas 2 themes belongs to template 1 and the third theme belongs to template 2
in the query it is using id IN(template_id1,template_id2)
Any idea how to do this?
You are doing a common mistake, you are counting everyrow each time since you are not using group by, you should do is group by Template.id when you do your search. Butttttttt.... has many wont do a join :( so you have to force it a littleor use something like linkable component
example
$join = array(
array('table' => 'templateThemes',
'alias' => 'TemplateTheme',
'type' => 'LEFT',
'conditions' => array(
'Template.id = TemplateTheme.Template_id',
)
)
);
$fields = array('Template.id','count(TemplateTheme.id) AS themes');
$this->Template->find('all', array('fields'=>$fields, 'joins'=>$join', $group =>array('Template.id')));
You may also do it in reverse since belongsTo does the join something like this
in your model (it is always recommended to put it static in your model unless is not a normal association)
var belongsTo = array(
'Template'=> array(
'classname' => 'Template',
'foreign_key' => 'template_id'
);
and in controller
$fields = array('Template.id','count(TemplateTheme.id) AS themes');
$this->Template->find('all', array('fields'=>$fields, $group =>array('Template.id')));
Hope this helps you, if not just comment
I'm using the Containable behavior to get a list of Comments (belongsTo Post, which belongs to Question; Question hasMany Post, and Post hasMany Comments; all of these belong to Users).
$data = $this->Question->find ( 'first',
array ('contain' =>
array ('User',
'Post' => array ('User', /* 'order' => 'User.created DESC'*/ )
)
)
);
It works, when I comment out the section in comments above. I suppose this is to be expected, but what I want is all of the Posts that are found, should be sorted in order of the 'created' field of the 'User' they belong to. How do I accomplish this deeper level sorting in CakePHP? I always get, "Warning (512): SQL Error: 1054: Unknown column 'User.created' in 'order clause'"
Thanks for your help!
Also, you might be trying to group on a related table from a find call that doesn't use joins.
Set your debug level to something greater than 1 so you can see the query log and make sure that Cake isn't doing two queries to fetch your data. If that is the case then the first query is not actually referencing the second table.
If you want to manually force a join in these situations you can use the Ad-Hoc joins method outlined by Nate at the following link.
http://bakery.cakephp.org/articles/view/quick-tip-doing-ad-hoc-joins-in-model-find
I have found two ways to get around this.
The first is to define the second level associacion directly in the model.
Now you will have access to this data everywhere.
It should look something like this.....
var $belongsTo = array(
'Foo' => array(
'className' => 'Foo', //unique name of 1st level join ( Model Name )
'foreignKey' => 'foo_id', //key to use for join
'conditions' => '',
'fields' => '',
'order' => ''
),
'Bar' => array(
'className' => 'Bar', //name of 2nd level join ( Model Name )
'foreignKey' => false,
'conditions' => array(
'Bar.id = Foo.bar_id' //id of 2nd lvl table = associated column in 1st level join
),
'fields' => '',
'order' => ''
)
);
The problem with this method is that it could make general queries more complex than they need be.
You can thus also add the second level queries directly into te find or paginate statement as follows: (Note: I found that for some reason you can't use the $belongsTo associations in the second level joins and will need to redefine them if they are already defined. eg if 'Foo' is already defined in $belongsTo, you need to create a duplicate 'Foo1' to make the association work, like the example below.)
$options['joins'] = array(
array('table' => 'foos',
'alias' => 'Foo1',
'type' => 'inner',
'conditions' => array(
'CurrentModel.foo_id = Foo1.id'
)
),
array('table' => 'bars',
'alias' => 'Bar',
'type' => 'inner',
'foreignKey' => false,
'conditions' => array(
'Bar.id = Foo1.bar_id'
)
)
);
$options['conditions'] = array('Bar.column' => "value");
$this->paginate = $options;
$[modelname] = $this->paginate();
$this->set(compact('[modelname]'));
I hope this is clear enough to understand and that it helps someone.
Check your recursive value. If it's too limiting, it will ignore the containable links, IIRC. I remember bumping into this a few times. I'd try containing multiple models, but my recursive option was set to 0 and nothing would get pulled. For your example, I'd think that a value of 1 (the default) would suffice, but maybe you've explicitly set it to 0 somewhere?
You can add before your call to find() the following:
$this->Question->order = 'Question.created DESC';
Yeah, I couldn't work out how to sort based on the related/associated model, so ended up using the Set::sort() method. Checkout this article for a good explanation.
// This finds all FAQ articles sorted by:
// Category.sortorder, then Category.id, then Faq.displaying_order
$faqs = $this->Faq->find('all', array('order' => 'displaying_order'));
$faqs = Set::sort($faqs, '{n}.Category.id', 'ASC');
$faqs = Set::sort($faqs, '{n}.Category.sortorder', 'ASC');
...And yes, it should probably be a Category->find() but unfortunately the original developer didn't code it that way, and I didn't wanna rework the views.