how to convert zval to vector for php extension? - php

Question

i'm writing a php extension for my c++ library which is defined something like this:
bool getPids(map<string,string> pidsMap, vector<string> ids);
now, i'm writing a php wrapper for above function like this.
ZEND_METHOD(myFInfo, get_pids)
{
zval *idsArray;
if (zend_parse_parameters( ZEND_NUM_ARGS() TSRMLS_CC, "a",
&idsArray ) == FAILURE )
{
RETURN_NULL();
}
}
now i want to call getPids(), but i don't know the proper way to pass idsArray as vector into the c++ function.
after some search on web, i found an example where zval array is iterated to read each values, and i thought maybe i can use this to create a vector.
PHP_FUNCTION(hello_array_strings)
{
zval *arr, **data;
HashTable *arr_hash;
HashPosition pointer;
int array_count;
if (zend_parse_parameters(ZEND_NUM_ARGS() TSRMLS_CC, "a", &arr) == FAILURE) {
RETURN_NULL();
}
arr_hash = Z_ARRVAL_P(arr);
array_count = zend_hash_num_elements(arr_hash);
php_printf("The array passed contains %d elements", array_count);
for(zend_hash_internal_pointer_reset_ex(arr_hash, &pointer); zend_hash_get_current_data_ex(arr_hash, (void**) &data, &pointer) == SUCCESS;
zend_hash_move_forward_ex(arr_hash, &pointer)) {
if (Z_TYPE_PP(data) == IS_STRING) {
PHPWRITE(Z_STRVAL_PP(data), Z_STRLEN_PP(data));
php_printf("
");
}
}
RETURN_TRUE;
}
but is this the best approach? or is there a better way to do this?
thanks!

Answer 1

To populate a std::vector<std::string> from a PHP array, here's how I'd do it (the short version):
std::vector<std::string> vec;
HashTable *arr_hash = Z_ARRVAL_P(arr);
zval **arr_value;
for(zend_hash_internal_pointer_reset(arr_hash);
zend_hash_get_current_data(arr_hash, (void **)&arr_value) == SUCCESS;
zend_hash_move_forward(arr_hash))
{
vec.push_back(Z_STRVAL_PP(arr_value));
}
...where arr is your input zval *, and vec is your output vector.