How to pass xml image in php page? - php

Question

I'm new in php. I recently go through one login example in php (http://net.tutsplus.com/articles/news/build-a-login-and-registration-system-with-xml/) and implemented login page for my test site in local host.
But now i want to assing each user one image let say i have 3 user and i have 3 user xml under user folder and each xml should look something like this
<?xml version="1.0"?>
<user>
<password>some password will come here</password>
<email>user#user.com</email>
<img>images/mynewimage.jpg</img>
</user>
i added <img> node in xml but i don't know how to call that on php page. Here the biggest challenge is for me is to find out the current user on each page since i have 3-4 basic pages after login and i'm maintain his login on each page so i want his image also on all the page i given below code on each page to maintain session
<?php
session_start();
if(!file_exists('users/' . $_SESSION['username'] . '.xml')){
header('Location: login.php');
die;
}
?>
when i check with username <?php echo ucfirst($_SESSION['username']); ?> it shows me current user name but in same way i'm unable to call image next to username.

Answer 1

use simplexml_load_file()
$xml = simplexml_load_file('users/' . $_SESSION['username'] . '.xml');
echo $xml->img;

Answer 2

the first thing you have to do is parse your xml file.php have a function for this:
$xmls = simple_xml_load_file(your_file's_exact_path);
$image = $xml->img;
if you have many img elements in your xml file you have to use foreach loop for that like:
foreach($xmls as $xml)
{
$xml->img;
$image = implode(',',$$xml->img;);
}
this code parse you xml file and save all images to the variable $image. now you can use it as you want.make sure about the img element's path. just try with this. it will help you.
happy coding!