display partial results from a mysql query - php

Question

I have a sql query that pulls all types of data from 3 different tables that I now want to display in an array. I can get it to output all the data from the sql query, but I only want to display part of the array at a time based on if the value of the column in table is the same. Will try to demonstrate below.
My sql result looks like this:
Client | Order | Exc1 | Exc2 | Rest | Reps |
-------------------------------------------------------
Steve | 1A | this | That | This | that |
-------------------------------------------------------
Mike | 1A | this | That | This | that |
-------------------------------------------------------
Jax | 1A | this | That | This | that |
-------------------------------------------------------
Steve | 1B | this | That | This | that |
-------------------------------------------------------
Mike | 1B | this | That | This | that |
-------------------------------------------------------
Jax | 1B | this | That | This | that |
I want my array to output this on a page1
Steve | 1A | this | That | This | that |
-------------------------------------------------------
Mike | 1A | this | That | This | that |
-------------------------------------------------------
Jax | 1A | this | That | This | that |
And this on page 2 and so on. Each page will contain a list of all clients and only one order value per page. The order column value will vary for each user as they will be able to input there own text for the order field. Is this possible and if so how is the best way possible?
#Gordon Linoff here is my current query. I dont really understand what you wrote or more of how it would relate to my query. below id my current query. I did not finish outputting into array. I just have this as I was testing until I got the results I wanted.
function get_workout_class(){
$workout_class = array();
$workout_query = mysql_query("
SELECT *
FROM `movements`
LEFT JOIN `classes`
ON `movements`.`class_id` = `classes`.`class_id`
LEFT JOIN `clients`
ON `movements`.`class_id` = `clients`.`class_id`
WHERE `classes`.`class_id` = '$class_id' AND `user_id` = ".$_session['user_id']."
ORDER BY `movements`.`order`, `clients`.`first_name`
");
}
Here is a screen shot of my query result so you can see how I want them grouped. Pages to be split by different "order" values. The number of clients will vary from class to class.
http://custommovement.com/help/query.png
Here is my new query. The first part works just fine but the subquery is giving my problems. Its not pulling any results. #GordonLinoff
function get_workout_class($class_id){
$class_id = (int)$class_id;
$workout_class = array();
$workout_query = mysql_query("
WITH `workouts` as (
SELECT
`movements`.`movement_id`,
`movements`.`order`,
`movements`.`mv_00`,
`movements`.`mv_01`,
`movements`.`mv_02`,
`movements`.`mv_03`,
`movements`.`mv_04`,
`movements`.`rep_set_sec`,
`movements`.`rest`,
`classes`.`class_name`,
`clients`.`client_id`,
`clients`.`first_name`,
`clients`.`last_name`,
`clients`.`nickname`
FROM `movements`
LEFT JOIN `classes` ON `movements`.`class_id` = `classes`.`class_id`
LEFT JOIN `clients` ON `movements`.`class_id` = `clients`.`class_id`
WHERE `classes`.`class_id` = '$class_id'
)
SELECT `wo`.*
(SELECT COUNT(DISTINCT `order`) FROM `workouts` `wo2` WHERE `wo2`.`order` <= `wo`.`order`) as `pagenum`
FROM `workouts` `wo`
ORDER BY `pagenum`
");
echo mysql_num_rows($workout_query);
}

Answer 1

I think you can solve your problem by adding a page number to your query. Unfortunately, this is moderately painful in mysql, because you have to use a self join or correlated subquery.
Here is an example of how to do it with a correlated subquery:
select t.*,
(select count(distinct order) from t t2 where t2.order <= t.order) as pagenum
from t
order by pagenum
Based on your original query (but without putting it into a string):
with workouts as (
SELECT *
FROM `movements` LEFT JOIN
`classes`
ON `movements`.`class_id` = `classes`.`class_id` LEFT JOIN
`clients`
ON `movements`.`class_id` = `clients`.`class_id`
WHERE `classes`.`class_id` = '$class_id' AND `user_id` = ".$_session['user_id']."
)
select wo.*,
(select count(distinct order) from workouts wo2 where wo2.order <= wo.order) as pagenum
from workouts wo
order by pagenum
This will almost work . . . just one caveat. You can put the "SELECT *" into the with clause because you have multiple columns with the same name. Put in the columns you need.
I forget that mysql does not support the "with" statement. My apologies for the bad syntax. One work around is to use a view or temporary table. Otherwise, the query is a bit more complicated because the logic has to be repeated twice:
select wo.*,
(select count(distinct order)
from (SELECT *
FROM `movements` LEFT JOIN
`classes`
ON `movements`.`class_id` = `classes`.`class_id` LEFT JOIN
`clients`
ON `movements`.`class_id` = `clients`.`class_id`
WHERE `classes`.`class_id` = '$class_id' AND `user_id` = ".$_session['user_id']."
) wo2
where wo2.order <= wo.order
) as pagenum
from (SELECT *
FROM `movements` LEFT JOIN
`classes`
ON `movements`.`class_id` = `classes`.`class_id` LEFT JOIN
`clients`
ON `movements`.`class_id` = `clients`.`class_id`
WHERE `classes`.`class_id` = '$class_id' AND `user_id` = ".$_session['user_id']."
) wo
order by pagenum

Answer 2

try this. It uses subquery for the max value of the order.
SELECT a.*
FROM myTable a INNER JOIN
(
SELECT Client,
Max(`Order`) as MaxOrder
FROM myTable
GROUP BY Client
) c
ON a.Client = c.Client AND
a.`Order` = c.MaxOrder
or the simpliest if i'm not mistaken
SELECT *
FROM myTable
WHERE `Order` = '1B'