passing an array through the function - php

Question

My website is featuring online classified advertisements, programmed by PHP and MySQL. The following code let the administrator delete multiple records using the checkbox tool.
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" >
<table>
<td><? echo $rows['CountryName']; ?></td>
<td><input name="delete_items[]" type="checkbox" value="<?php echo $rows['id']; ?>" /></td>
</table>
<input type="submit" name="deleteSelected" value="Submit" >
</form>
<?php
if(isset($_POST['deleteSelected'])) {
$delete_items = join(', ', $_POST["delete_items"]);
$query = "DELETE FROM $table_name WHERE id IN ($deleted_items)";
$result = mysql_query($query);
header("Location: admin.php"); }
?>
When I press the submit button without checking boxes (all boxes are unchecked), I receive the following error message (p.s. the script is working well without any error message, if any Checkbox being checked):
Warning: join() [function.join]: Invalid arguments passed in C:\xampp\htdocs\admin_listing.php on line 87
I’ve tried the implode function instead of using join, but still I'm getting an error message.
Maybe I do not passing an array through the function correctly, but I cannot find a solution for the above.
Any advise would be appreciated.

Answer 1

It looks like you are displaying all the records from your database into a single input in the form.
The code will probably work well with the implode() as you tried, but you will need to use a loop in the displaying of the form to generate it properly with the options.
Something like this:
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" >
<table>
<?php
while($row=$databaseResult) //however you are getting the data out of the database.
{
echo "<tr><td>".$rows['CountryName']."</td><td><input name='delete_items[]' type='checkbox' value=".$rows['id']."/></td></tr>";
}
?>
</table>
<input type="submit" name="deleteSelected" value="Submit" >
</form>

Answer 2

Thank you all for trying to help, I found a simple solution by adding one code line, as follows:
<?php
if(isset($_POST['deleteSelected'])) {
if(isset($_POST["delete_items"][0])) {
$delete_items = join(', ', $_POST["delete_items"]);
$query = "DELETE FROM $table_name WHERE id IN ($delete_items)";
$result = mysql_query($query);
header("Location: admin.php");
}
}
?>
Hope it can help someone else...