How to fetch a table from MySQL in PHP - php

Question

I'm a newbie to PHP and I'm just trying the very basics of MVC. Everything is going good but I have a problem while fetching data from MySQL and populating a HTML table with it.
The problem is that my code is just returning one row of the table (there are three rows in that table).
I have tried many things and right now I'm using arrays for storing the data and passing to controller and then to the view.
Query class file having a function for getting data and name queryDB:
public function getdata(){
$connectObj=new dbConnection();
//its a connection class where mysql connection has been made
if(!$connectObj->connectDB()){
echo "Error in mysql: ".mysql_error();
return false;
}
else{
$query = "select * from tbl_cartypes";
$result = mysql_query($query) or die("Error: ".mysql_error());
$data = array();
while($row = mysql_fetch_assoc($result)){
$data[0] = $row['car_id'];
$data[1] = $row['car_name'];
$data[2] = $row['car_model'];
$data[3] = $row['car_type'];
$data[4] = $row['car_price'];
}
return $data;
}
$connectObj->closeDB();
}
The controller class where the controller of this query is name carController.php:
public function getAllData(){
$runQuery = new queryDB();
$array = array();
$array = $runQuery->getTickets($userid);
return $array;
}
And the final view where I'm just echoing my data:
include "$path/controllers/carController.php";
$ticket = new carController();
$array = array();
$array = $ticket->getdata();
for($i=0;$i<count($array);$i++){
echo $array[$i]."<br />";
}
Output of this code is without error, but the problem is that it's just fetching one row of the table whereas there are three rows.
So any one can help me with this?

Answer 1

It's fetching all rows, but you're saving all the data to the same place ($data[0] through $data[5]), so all but the last row is getting overwritten.
This might work better:
$data = array();
while($row = mysql_fetch_assoc($result)) {
$data[] = $row;
}

Answer 2

Using PDO and what other people have posted try using this
public function getdata(){
$connectObj=new dbConnection();
//its a connection class where mysql connection has been made
if(!$connectObj->connectDB()){
echo "Error in mysql: ".mysql_error();
return false;
}
else{
$query = 'select * from tbl_cartypes';
$result = $connectObj->query($query);
$data = array()
foreach ($result as $row){
array_push($data, $row)
}
return $data;
}
$connectObj->closeDB();
}

Answer 3

Your problem is that you're overwriting the values of the previous table:
while($row = mysql_fetch_assoc($result)){
$data[0] = $row['car_id'];
$data[1] = $row['car_name'];
$data[2] = $row['car_model'];
$data[3] = $row['car_type'];
$data[4] = $row['car_price'];
}
This will just re-write the last row of data over the key's in that table.
Try:
$data = array()
while($row = mysql_fetch_assoc($result)){
array_push($data, $row)
}

Answer 4

Your while loop is assigning just one row to array $data. in while loop instead try this
while($row = mysql_fetch_assoc($result)){
$data["car_id"][] = $row['car_id'];
$data["car_name"][] = $row['car_name'];
$data["car_model"][] = $row['car_model'];
$data["car_type"][] = $row['car_type'];
$data["car_price"][] = $row['car_price'];
}
return $data;
Now you can iterate through the array.