display only 3 foreach result per row - php

Question

i have script as follows
$output="<table class='products'><tr>";
while($info = mysql_fetch_array( $data )) {
//Outputs the image and other data
$output.= "<td>
<img src=http://localhost/zack/sqlphotostore/images/" .$info['photo'] ." width=323px ></img>
<b>Name:</b> ".$info['name'] . "
<b>Email:</b> ".$info['email'] . "
<b>Phone:</b> ".$info['phone'] . "</td> ";
}
$output.="<tr></table>";
print $output;
?>
it shows all results in long horizontal line how do i break the results so that they show
in new row after 3 count.

Answer 1

Keep a counter, and output a new table row every 3 images
$output="<table class='products'>";
$counter = 0;
while($info = mysql_fetch_array( $data ))
{
if( $counter % 3 == 0 )
$output .= '<tr>';
$output .= "<td>";
$output .= "<img src=http://localhost/zack/sqlphotostore/images/".$info['photo'] ." width=323px ></img>";
$output .= "<b>Name:</b> ".$info['name'];
$output .= "<b>Email:</b> ".$info['email'];
$output .= "<b>Phone:</b> ".$info['phone']."</td> ";
if( $counter % 3 == 0)
$output .= "</tr>";
$counter++;
}
$output.="</table>";
print $output;
?>

Answer 2

Add a counter and start a new row every time it reaches a multiple of 3.
$counter = 0;
while($info = mysql_fetch_array($data)) {
if ($counter++ % 3 == 0) {
if ($counter > 0) {
$output .= "</tr>";
}
$output .= "<tr>";
}
// stuff
}
if ($counter > 0) {
$output .= "</tr>";
}
$output .= "</table>";
Please note: It may not help answer your question, but you should stop using mysql_* functions. They're being deprecated. Instead use PDO (supported as of PHP 5.1) or mysqli (supported as of PHP 4.1). If you're not sure which one to use, read this article.