php date validation - php

Question

Im trying to to set up a php date validation (MM/DD/YYYY) but I'm having issues. Here is a sample of what I got:
$date_regex = '%\A(0[1-9]|1[012])[- /.](0[1-9]|[12][0-9]|3[01])[- /.](19|20)\d\d\z%';
$test_date = '03/22/2010';
if (preg_match($date_regex, $test_date,$_POST['birthday']) ==true) {
$errors[] = 'user name most have no spaces';`

Answer 1

You could use checkdate. For example, something like this:
$test_date = '03/22/2010';
$test_arr = explode('/', $test_date);
if (checkdate($test_arr[0], $test_arr[1], $test_arr[2])) {
// valid date ...
}
A more paranoid approach, that doesn't blindly believe the input:
$test_date = '03/22/2010';
$test_arr = explode('/', $test_date);
if (count($test_arr) == 3) {
if (checkdate($test_arr[0], $test_arr[1], $test_arr[2])) {
// valid date ...
} else {
// problem with dates ...
}
} else {
// problem with input ...
}

Answer 2

You can use some methods of the DateTime class, which might be handy; namely, DateTime::createFromFormat() in conjunction with DateTime::getLastErrors().
$test_date = '03/22/2010';
$date = DateTime::createFromFormat('m/d/Y', $test_date);
$date_errors = DateTime::getLastErrors();
if ($date_errors['warning_count'] + $date_errors['error_count'] > 0) {
$errors[] = 'Some useful error message goes here.';
}
This even allows us to see what actually caused the date parsing warnings/errors (look at the warnings and errors arrays in $date_errors).

Answer 3

Though checkdate is good, this seems much concise function to validate and also you can give formats. [Source]
function validateDate($date, $format = 'Y-m-d H:i:s') {
$d = DateTime::createFromFormat($format, $date);
return $d && $d->format($format) == $date;
}
function was copied from this answer or php.net
The extra ->format() is needed for cases where the date is invalid but createFromFormat still manages to create a DateTime object. For example:
// Gives "2016-11-10 ..." because Thursday falls on Nov 10
DateTime::createFromFormat('D M j Y', 'Thu Nov 9 2016');
// false, Nov 9 is a Wednesday
validateDate('Thu Nov 9 2016', 'D M j Y');

Answer 4

Instead of the bulky DateTime object .. just use the core date() function
function isValidDate($date, $format= 'Y-m-d'){
return $date == date($format, strtotime($date));
}

Answer 5

Use it:
function validate_Date($mydate,$format = 'DD-MM-YYYY') {
if ($format == 'YYYY-MM-DD') list($year, $month, $day) = explode('-', $mydate);
if ($format == 'YYYY/MM/DD') list($year, $month, $day) = explode('/', $mydate);
if ($format == 'YYYY.MM.DD') list($year, $month, $day) = explode('.', $mydate);
if ($format == 'DD-MM-YYYY') list($day, $month, $year) = explode('-', $mydate);
if ($format == 'DD/MM/YYYY') list($day, $month, $year) = explode('/', $mydate);
if ($format == 'DD.MM.YYYY') list($day, $month, $year) = explode('.', $mydate);
if ($format == 'MM-DD-YYYY') list($month, $day, $year) = explode('-', $mydate);
if ($format == 'MM/DD/YYYY') list($month, $day, $year) = explode('/', $mydate);
if ($format == 'MM.DD.YYYY') list($month, $day, $year) = explode('.', $mydate);
if (is_numeric($year) && is_numeric($month) && is_numeric($day))
return checkdate($month,$day,$year);
return false;
}

Answer 6

REGEX should be a last resort. PHP has a few functions that will validate for you. In your case, checkdate is the best option. http://php.net/manual/en/function.checkdate.php

Answer 7

Nicolas solution is best. If you want in regex,
try this,
this will validate for, 01/01/1900 through 12/31/2099 Matches invalid dates such as February 31st Accepts dashes, spaces, forward slashes and dots as date separators
(0[1-9]|1[012])[- /.](0[1-9]|[12][0-9]|3[01])[- /.](19|20)[0-9]{2}

Answer 8

This function working well,
function validateDate($date, $format = 'm/d/Y'){
$d = DateTime::createFromFormat($format, $date);
return $d && $d->format($format) === $date;
}

Answer 9

I know this is an older post, but I've developed the following function for validating a date:
function IsDateTime($aDateTime) {
try {
$fTime = new DateTime($aDateTime);
$fTime->format('m/d/Y H:i:s');
return true;
}
catch (Exception $e) {
return false;
}
}

Answer 10

Try This
/^(19[0-9]{2}|2[0-9]{3})\-(0[1-9]|1[0-2])\-(0[1-9]|1[0-9]|2[0-9]|3[0-1])((T|\s)(0[0-9]{1}|1[0-9]{1}|2[0-3]{1})\:(0[0-9]{1}|1[0-9]{1}|2[0-9]{1}|3[0-9]{1}|4[0-9]{1}|5[0-9]{1})\:(0[0-9]{1}|1[0-9]{1}|2[0-9]{1}|3[0-9]{1}|4[0-9]{1}|5[0-9]{1})((\+|\.)[\d+]{4,8})?)?$/
this regular expression valid for :
2017-01-01T00:00:00+0000
2017-01-01 00:00:00+00:00
2017-01-01T00:00:00+00:00
2017-01-01 00:00:00+0000
2017-01-01
Remember that this will be cover all case of date and date time with (-) character

Answer 11

Not sure if this answer the question or going to help....
$dt = '6/26/1970' ; // or // '6.26.1970' ;
$dt = preg_replace("([.]+)", "/", $dt);
$test_arr = explode('/', $dt);
if (checkdate($test_arr[0], $test_arr[1], $test_arr[2]) && preg_match("/[0-9]{1,2}\/[0-9]{1,2}\/[0-9]{4}/", $dt))
{ echo(date('Y-m-d', strtotime("$dt")) . "<br>"); }
else
{ echo "no good...format must be in mm/dd/yyyy"; }

Answer 12

We can use simple "date" input type, like below:
Birth date: <input type="date" name="userBirthDate" /><br />
Then we can link DateTime interface with built-in function 'explode':
public function validateDate()
{
$validateFlag = true;
$convertBirthDate = DateTime::createFromFormat('Y-m-d', $this->birthDate);
$birthDateErrors = DateTime::getLastErrors();
if ($birthDateErrors['warning_count'] + $birthDateErrors['error_count'] > 0)
{
$_SESSION['wrongDateFormat'] = "The date format is wrong.";
}
else
{
$testBirthDate = explode('-', $this->birthDate);
if ($testBirthDate[0] < 1900)
{
$validateFlag = false;
$_SESSION['wrongDateYear'] = "We suspect that you did not born before XX century.";
}
}
return $validateFlag;
}
I tested it on Google Chrome and IE, everything works correctly. Furthemore, Chrome display simple additional interface. If you don't write anything in input or write it in bad format (correctly is following: '1919-12-23'), you will get the first statement. If you write everything in good format, but you type wrong date (I assumed that nobody could born before XX century), your controller will send the second statement.

Answer 13

I think it will help somebody.
function isValidDate($thedate) {
$data = [
'separators' => array("/", "-", "."),
'date_array' => '',
'day_index' => '',
'year' => '',
'month' => '',
'day' => '',
'status' => false
];
// loop through to break down the date
foreach ($data['separators'] as $separator) {
$data['date_array'] = explode($separator, $thedate);
if (count($data['date_array']) == 3) {
$data['status'] = true;
break;
}
}
// err, if more than 4 character or not int
if ($data['status']) {
foreach ($data['date_array'] as $value) {
if (strlen($value) > 4 || !is_numeric($value)) {
$data['status'] = false;
break;
}
}
}
// get the year
if ($data['status']) {
if (strlen($data['date_array'][0]) == 4) {
$data['year'] = $data['date_array'][0];
$data['day_index'] = 2;
}elseif (strlen($data['date_array'][2]) == 4) {
$data['year'] = $data['date_array'][2];
$data['day_index'] = 0;
}else {
$data['status'] = false;
}
}
// get the month
if ($data['status']) {
if (strlen($data['date_array'][1]) == 2) {
$data['month'] = $data['date_array'][1];
}else {
$data['status'] = false;
}
}
// get the day
if ($data['status']) {
if (strlen($data['date_array'][$data['day_index']]) == 2) {
$data['day'] = $data['date_array'][$data['day_index']];
}else {
$data['status'] = false;
}
}
// finally validate date
if ($data['status']) {
return checkdate($data['month'] , $data['day'], $data['year']);
}
return false;
}