Here's my code:
$post = $_POST['test'];
$pattren='/((([http]{3,9}:(?:\/\/)?)(?:[-;:&=\+\$,\w]+#)?[A-Za-z0-9.-]+|(?:www.|[-;:&=\+\$,\w]+#)[A-Za-z0-9.-]+)((?:\/[\+~%\/.\w-_]*)?\??(?:[-\/+=&#?;%#,.\w_]*)#?(?:[\w]*)?))/';
preg_match_all( $pattren, $post, $matches);
foreach($matches[0] as $match) {
$images[]= "<a href=\"$match\" target=\"_blank\" >$match</a> ";
}
for ($i = 0, $c = count($images); $i < $c; $i++) {
$html_links = str_replace($pattren,$images[$i], $post);
}
echo $html_links;
I'm trying to get all urls from $post and convert them to links, but something is wrong.
There are many things wrong with this code, including:
Not sure where you've got your regular expression ($pattren) from, but it looks like complete gibberish to me - [http]{3,9}: means "any of the characters 'h', 't', or 'p', repeated between 3 and 9 times, followed by a colon" - so it would match "thppppppt:", which doesn't look much like the beginning of a URL to me.
str_replace has nothing to do with regular expressions, so str_replace($pattren, ... is looking for the text of that regular expression in the input.
In actual fact, I'm not sure what replacement you are expecting to happen in that loop, since you've already copied $match into the correct parts of the string.
You are over-writing the variable $html_links every time around your second loop. There is also no need for 2 loops, unless there is code not shown - you could simply build the string in the foreach loop and do away with the $images array altogether.
And, incidentally, you have spelled "pattern" wrong, and used an inconsistent convention for your curly-braces - some prefer the { on its own line, some on the line with the for/foreach, but you've managed one of each. [Neither of these will affect the code, though]
use preg_replace()
$post = $_POST['test'];
$pattren='%\b(([\w-]+://?|www[.])[^\s()<>]+(?:\([\w\d]+\)|([^[:punct:]\s]|/)))%s';
$html_links = preg_replace($pattren, '$1', $post);
echo $html_links;
Updated with a good pattern from here.
Related
I have the following title formation on my website:
It's no use going back to yesterday, because at that time I was... Lewis Carroll
Always is: The phrase… (author).
I want to delete everything after the ellipsis (…), leaving only the sentence as the title. I thought of creating a function in php that would take the parts of the titles, throw them in an array and then I would work each part, identifying the only pattern I have in the title, which is the ellipsis… and then delete everything. But when I do that, in the X space of my array, it returns the following:
was...
In position 8 of the array comes the word and the ellipsis and I don't know how to find a pattern to delete the author of the title, my pattern was the ellipsis. Any idea?
<?php
$a = get_the_title(155571);
$search = '... ';
if(preg_match("/{$search}/i", $a)) {
echo 'true';
}
?>
I tried with the code above and found the ellipsis, but I needed to bring it into an array to delete the part I need. I tried something like this:
<?php
define('WP_USE_THEMES', false);
require('./wp-blog-header.php');
global $wpdb;
$title_array = explode(' ', get_the_title(155571));
$search = '... ';
if (array_key_exists("/{$search}/i",$title_array)) {
echo "true";
}
?>
I started doing it this way, but it doesn't work, any ideas?
Thanks,
If you use regex you need to escape the string as preg_quote() would do, because a dot belongs to the pattern.
But in your simple case, I would not use a regex and just search for the three dots from the end of the string.
Note: When the elipsis come from the browser, there's no way to detect in PHP.
$title = 'The phrase... (author).';
echo getPlainTitle($title);
function getPlainTitle(string $title) {
$rpos = strrpos($title, '...');
return ($rpos === false) ? $title : substr($title, 0, $rpos);
}
will output
The phrase
First of all, since you're working with regular expressions, you need to remember that . has a special meaning there: it means "any character". So /... / just means "any three characters followed by a space", which isn't what you want. To match a literal . you need to escape it as \.
Secondly, rather than searching or splitting, you could achieve what you want by replacing part of the string. For instance, you could find everything after the ellipsis, and replace it with an empty string. To do that you want a pattern of "dot dot dot followed by anything", where "anything" is spelled .*, so \.\.\..*
$title = preg_replace('/\.\.\..*/', '', $title);
$text = "
<tag>
<html>
HTML
</html>
</tag>
";
I want to replace all the text present inside the tags with htmlspecialchars(). I tried this:
$regex = '/<tag>(.*?)<\/tag>/s';
$code = preg_replace($regex,htmlspecialchars($regex),$text);
But it doesn't work.
I am getting the output as htmlspecialchars of the regex pattern. I want to replace it with htmlspecialchars of the data matching with the regex pattern.
what should i do?
You're replacing the match with the pattern itself, you're not using the back-references and the e-flag, but in this case, preg_replace_callback would be the way to go:
$code = preg_replace_callback($regex,'htmlspecialchars',$text);
This will pass the mathces groups to htmlspecialchars, and use its return value as replacement. The groups might be an array, in which case, you can try either:
function replaceCallback($matches)
{
if (is_array($matches))
{
$matches = implode ('', array_slice($matches, 1));//first element is full string
}
return htmlspecialchars($matches);
}
Or, if your PHP version permits it:
preg_replace_callback($expr, function($matches)
{
$return = '';
for ($i=1, $j = count($matches); $i<$j;$i++)
{//loop like this, skips first index, and allows for any number of groups
$return .= htmlspecialchars($matches[$i]);
}
return $return;
}, $text);
Try any of the above, until you find simething that works... incidentally, if all you want to remove is <tag> and </tag>, why not go for the much faster:
echo htmlspecialchars(str_replace(array('<tag>','</tag>'), '', $text));
That's just keeping it simple, and it'll almost certainly be faster, too.
See the quickest, easiest way in action here
If you want to isolate the actual contents as defined by your pattern, you could use preg_match($regex,$text,$hits);. This will give you an array of hits those bits that were between the paratheses in the pattern, starting at $hits[1], $hits[0] contains the whole matched string). You can then start manipulating these found matches, possibly using htmlspecialchars ... and combine them again into $code.
Hopefully, this is an easy one. I have an array with lines that contain output from a CSV file. What I need to do is simply remove any commas that appear between double-quotes.
I'm stumbling through regular expressions and having trouble. Here's my sad-looking code:
<?php
$csv_input = '"herp","derp","hey, get rid of these commas, man",1234';
$pattern = '(?<=\")/\,/(?=\")'; //this doesn't work
$revised_input = preg_replace ( $pattern , '' , $csv_input);
echo $revised_input;
//would like revised input to echo: "herp","derp,"hey get rid of these commas man",1234
?>
Thanks VERY much, everyone.
Original Answer
You can use str_getcsv() for this as it is purposely designed for process CSV strings:
$out = array();
$array = str_getcsv($csv_input);
foreach($array as $item) {
$out[] = str_replace(',', '', $item);
}
$out is now an array of elements without any commas in them, which you can then just implode as the quotes will no longer be required once the commas are removed:
$revised_input = implode(',', $out);
Update for comments
If the quotes are important to you then you can just add them back in like so:
$revised_input = '"' . implode('","', $out) . '"';
Another option is to use one of the str_putcsv() (not a standard PHP function) implementations floating about out there on the web such as this one.
This is a very naive approach that will work only if 'valid' commas are those that are between quotes with nothing else but maybe whitespace between.
<?php
$csv_input = '"herp","derp","hey, get rid of these commas, man",1234';
$pattern = '/([^"])\,([^"])/'; //this doesn't work
$revised_input = preg_replace ( $pattern , "$1$2" , $csv_input);
echo $revised_input;
//ouput for this is: "herp","derp","hey get rid of these commas man",1234
It should def be tested more but it works in this case.
Cases where it might not work is where you don't have quotes in the string.
one,two,three,four -> onetwothreefour
EDIT : Corrected the issues with deleting spaces and neighboring letters.
Well, I haven't been lazy and written a small function to do exactly what you need:
function clean_csv_commas($csv){
$len = strlen($csv);
$inside_block = FALSE;
$out='';
for($i=0;$i<$len;$i++){
if($csv[$i]=='"'){
if($inside_block){
$inside_block=FALSE;
}else{
$inside_block=TRUE;
}
}
if($csv[$i]==',' && $inside_block){
// do nothing
}else{
$out.=$csv[$i];
}
}
return $out;
}
You might be coming at this from the wrong angle.
Instead of removing the commas from the text (presumably so you can then split the string on the commas to get the separate elements), how about writing something that works on the quotes?
Once you've found an opening quote, you can check the rest of the string; anything before the next quote is part of this element. You can add some checking here to look for escaped quotes, too, so things like:
"this is a \"quote\""
will still be read properly.
Not exactly an answer you've been looking for - But I've used it for cleaning commas in numbers in CSV.
$csv = preg_replace('%\"([^\"]*)(,)([^\"]*)\"%i','$1$3',$csv);
"3,120", 123, 345, 567 ==> 3120, 123, 345, 567
We use custom bbcode in our news posts
[newsImage]imageName.jpg[/newsImage]
And i'd like to use preg_match to get the imageName.jpg from between those tags. The whole post is stored in a variable called $newsPost.
I'm new to regex and I just can't figure out the right expression to use in preg_match to get what I want.
Any help is appreciated. Also, do any of you know a good resource for learning what each of the characters in regex do?
preg_match_all('/\[newsImage\]([^\[]+)\[\/newsImage\]/i', $newsPost, $images);
The variable $images should then contain your list of matches.
http://www.php.net/manual/en/regexp.introduction.php
To answer your second question: A very good regex tutorial is regular-expressions.info.
Among other things, it also contains a regular expression syntax reference.
Since different regex flavors use a different syntax, you'll also want to look at the regex flavor comparison page.
As Rob said but escaping last ]
preg_match('/\[newsImage\]([^\[]+)\[newsImage\]/i', $newsPost, $images);
$images[1] will contain the name of image file.
This is not exactly what you asked for, but you can replace your [newsImage] tags with tags using the following code, its not perfect as it will fall down if you have an empty tag e.g. [newsImage][/newsImage]
function process_image_code($text) {
//regex looks for [newsImage]sometext[/newsImage]
$urlReg ="/((?:\[newsImage]{1}){1}.{1,}?(?:\[\/newsImage]){1})/i";
$pregResults = preg_split ($urlReg , $text, -1, PREG_SPLIT_DELIM_CAPTURE);
$output = "";
//loop array to build the output string
for($i = 0; $i < sizeof($pregResults); $i++) {
//if the array item has a regex match process the result
if(preg_match($urlReg, $pregResults[$i]) ) {
$pregResults[$i] = preg_replace ("/(?:\[\/newsImage]){1}/i","\" alt=\"Image\" border=\"0\" />",$pregResults[$i] ,1);
// find if it has a http:// at the start of the image url
if(preg_match("/(?:\[newsImage]http:\/\/?){1}/i",$pregResults[$i])) {
$pregResults[$i] = preg_replace ("/(?:\[newsImage]?){1}/i","<img src=\"",$pregResults[$i] ,1);
}else {
$pregResults[$i] = preg_replace ("/(?:\[newsImage]?){1}/i","<img src=\"http://",$pregResults[$i] ,1);
}
$output .= $pregResults[$i];
}else {
$output .= $pregResults[$i];
}
}
return $output;
}
I have fooled around with regex but can't seem to get it to work. I have a file called includes/header.php I am converting the file into one big string so that I can pull out a certain portion of the code to paste in the html of my document.
$str = file_get_contents('includes/header.php');
From here I am trying to get return only the string that starts with <ul class="home"> and ends with </ul>
try as I may to figure out an expression I am still confused.
Once I trim down the string I can just print that on my page but I can't figure out the trimming part
If you need something really hardcore, http://www.php.net/manual/en/book.xmlreader.php.
If you just want to rip out the text that fits that pattern try something like this.
$string = "stuff<ul class=\"home\">alsdkjflaskdvlsakmdf<another></another></ul>stuff";
if( preg_match( '/<ul class="home">(.*)<\/ul>/', $string, $match ) ) {
//do stuff with $match[0]
}
I'm assuming that the difficulty you're having has to do with escaping the regex special characters in the string(s) you're using as a delimiter. If so, try using the preg_quote() function:
$start = preg_quote('<ul class="home">');
$end = preg_quote('</ul>', '/');
preg_match("/" . $start. '.*' . $end . "/", $str, $matching_html_snippets);
The html you want should be in $matching_html_snippets[0]
You probably want an XML parser such as the built in one. Here is an example you might want to take a look at.
http://www.php.net/manual/en/function.xml-parse.php#90733
If you want to use regex then something along the lines of
$str = file_get_contents('includes/header.php');
$matchedstr = preg_match("<place your pattern here>", $str, $matches);
You probably want the pattern
'/<ul class="home">.*?<\/ul>/s'
Where $matches will contain an array of the matches it found so you can grab whatever element you want from the array with
$matchedstr[0];
which will return the first element. And then output that.
But I'd be a bit wary, regular expressions do tend to match to surprising edge cases and you need to feed them actual data to get reliable results as to when they are failing. However if you are just passing templates it should be ok, just do some tests and see if it all works. If not I'd still recommend using the PHP XML Parser.
Hope that helps.
If you feel like not using regexes you could use string finding, which I think the PHP manual implies is quicker:
function substrstr($orig, $startText, $endText) {
//get first occurrence of the start string
$start = strpos($orig, $startText);
//get last occurrence of the end string
$end = strrpos($orig, $endText);
if($start === FALSE || $end === FALSE)
return $orig;
$start++;
$length = $end - $start;
return substr($orig, $start, $length);
}
$substr = substrstr($string, '<ul class="home">', '</ul>');
You'll need to make some adjustments if you want to include the terminating strings in the output, but that should get you started!
Here's a novel way to do it; I make no guarantees about this technique's robustness or performance, other than it does work for the example given:
$prefix = '<ul class="home">';
$suffix = '</ul>';
$result = $prefix . array_shift(explode($suffix, array_pop(explode($prefix, $str)))) . $suffix;