How do I get jQuery/AJAX result into table cell - php

Question

I have this script here that outputs a result from a sql db query but I can not figure out how to get it to put the result in the table cell specified.
Here is query:
<script type="text/javascript">
$(document).ready(function(){
$('.typeval').change(function(){
var movement = $(this).val();
var client_id = $(this).parent().siblings().find('.clientval').val();
var class_id = <? echo $class_id; ?>;
$.ajax({
type: "POST",
url: "movement_count.php",
data: {movement:movement, client_id:client_id, class_id:class_id},
dataType: "json",
success:(function(output) {
$.each(output, function(index, value){
alert(value);
$(".count").append(output[value]);
}) // each
}) // success
}); // ajax
}); // .typeval
}); // document
</script>
I want to put the result of this (value):
alert(value);
into here:
<td><label class="count"></label></td>
The <td> I am targeting on the same row as the <select> menu that is triggering the result. There will also be multiple table rows with this exact same cell <td>. So I need to target the <td> on this row only somehow. Can someone help me with this? Im not sure if I need the $.each but my php query is a mysql_fetch_row array even though the value returned will always be just one number.
Here is the HTML markup for the table cell I need the value in:
<td><label class="count"></label></td>
JS source code for class=count:
$(".count").append(output[index]);
ITS WORKING!!!! here is the code below
$(document).ready(function(){
$('.typeval').change(function(){
var movement = $(this).val();
var client_id = $(this).parent().siblings().find('.clientval').val();
var class_id = <? echo $class_id; ?>;
$count = $(this).parents('tr').find('label.count');
$.ajax({
type: "POST",
url: "movement_count.php",
data: {movement:movement, client_id:client_id, class_id:class_id},
dataType: "json",
success:(function(output) {
$.each(output, function(index, value){
//alert(value);
$count.append(output[index]);
}) // each
}) // success
}); // ajax
}); // .typeval
}); // document

Answer 1

Replace this
$("label.count<?php echo $client_id; ?>").append(output[value]);
With
$("label.count<?php echo $client_id; ?>").append(value);
Or alternately with this
$("label.count<?php echo $client_id; ?>").append(output[index]);
Hope this will help !!

Answer 2

Working code:
$(document).ready(function(){
$('.typeval').change(function(){
var movement = $(this).val();
var client_id = $(this).parent().siblings().find('.clientval').val();
var class_id = <? echo $class_id; ?>;
$count = $(this).parents('tr').find('label.count');
$.ajax({
type: "POST",
url: "movement_count.php",
data: {movement:movement, client_id:client_id, class_id:class_id},
dataType: "json",
success:(function(output) {
$.each(output, function(index, value){
//alert(value);
$count.append(output[index]);
}) // each
}) // success
}); // ajax
}); // .typeval
}); // document