Print JSON string in dropdown menu - php

Question

I am getting a problem in generating values of a JSON string into a dropdown menu.I have a JSON API
http://service.proventustechnologies.com/api/json?username=demo&token=4ce26206-025d-11dc-8314-0800200c9a66&method=getattributevalues&dimensionId=10
When you click it you will see many values like this.
{
"response": {
"id": 10,
"values": [
{
"id": 258,
"value": "Cameras"
},
{
"id": 2581,
"value": "GPS Navigation"
},
{
"id": 259,
"value": "MP3 Players"
},
{
"id": 260,
"value": "Cell Phone/PDA"
},
{
"id": 6377,
"value": "Digital Photo Frame"
},
{
"id": 110,
"value": "Motherboard"
},
{
"id": 108,
"value": "Desktop/Server"
},
{
"id": 109,
"value": "Notebook"
},
{
"id": 10738,
"value": "E-Book Reader"
}
],
"name": "System Type"
},
"status": "ok"
}
I want to print all the values such as Cameras,GPS Navigation in a dropdown menu.Thank you for any kind of help.

Answer 1

Use json_decode to convert json encoded string into PHP variable:
<?php
$json = file_get_contents($your_url);
$obj = json_decode($json);
echo $obj->response->id; // prints 10 (based on your sample code)
?>

Answer 2

I can't really get a feel for what your level of knowledge is, but you should load your data in a html select element for example like this:
<?php
echo '<select>';
$jsonData = file_get_contents($url);
$jsonDataObject = json_decode($jsonData);
foreach($jsonDataObject->response->values as $option){
echo '<option value=' . $option->id . '>' . $option->value . '</option>';
}
echo '</select>';
?>

Answer 3

hridaynehu,
Its very easy to populate the select box using your json array values. Follow below line of code.
<?php
$url = 'http://service.proventustechnologies.com/api/json?username=demo&token=4ce26206-025d-11dc-8314-0800200c9a66&method=getattributevalues&dimensionId=10';
$content = file_get_contents($url);
$jsonArray = json_decode($content, true);?>
<select name="json_populate"><?php
foreach($jsonArray->response->values as $jsonValue) { ?>
<option value="<?php echo $jsonValue->id; ?>"><?php echo $jsonValue->value; ?></option>
<?php } ?>
</select>
Please mark it answer if it helps you. Because it may help others too.
With Thanks & Regards,
Sanjoy Dey