insert proccess whith looping in php - php

Question

firstly sorry my english is bad
then
i have problem
i try to make lopping insert into table but i have problem i can't make array for inputs
to can insert in table with looping from another table
maybe u can't understand me but look to the code and u will understand my problem
$select = mysql_query("SELECT * FROM table_name ");
?>
<form method="post" action="">
<?
while($row =mysql_fetch_array($select))
{
if($_POST['add'])
{
$updpol = mysql_query("insert into table_name2 (yes,no,maybe,g_id)
values
('".$_POST['yes']."','".$_POST['no']."','".$_POST['maybe']."','".$row['id']."')
")
}
else{
?>
<input type="checkbox" name="yes" value="1" />
<br />
<input type="checkbox" name="no" value="1" />
<br />
<input type="checkbox" name="maybe" value="1" />
<?
}
?>
<input type="submit" name="add_poll" value="submit" />
</form>

Answer 1

in your php code , your checking if:
if($_POST['add'])
While there's no input named add in your form.
I believe you meant:
if($_POST['add_poll'])
In order to have multiply instances of inputs , you can do something like:
<input type="checkbox" name="yes[]" value="1" />
<br />
<input type="checkbox" name="no[]" value="1" />
<br />
<input type="checkbox" name="maybe[]" value="1" />
So , now , when posted:
$_POST['yes'] is an array of all the checkboxes.
And as an array , it starts with $_POST['yes'][0] and continues $_POST['yes'][1] and so on.
Therefore:
$select = mysql_query("SELECT * FROM table_name ");
?>
<form method="post" action="">
<?
$i = 0;
while($row =mysql_fetch_array($select))
{
if($_POST['add_poll'])
{
$updpol = mysql_query("insert into table_name2 (yes,no,maybe,g_id)
values
('".$_POST['yes'][$i]."','".$_POST['no'][$i]."','".$_POST['maybe'][$i]."','".$row['id']."')
");
$i++;
}
else{
?>
<input type="checkbox" name="yes[]" value="1" />
<br />
<input type="checkbox" name="no[]" value="1" />
<br />
<input type="checkbox" name="maybe[]" value="1" />
<?
}
?>
<input type="submit" name="add_poll" value="submit" />
</form>