add an if echo statement to my search engine - php

Question

I have a search engine and because of the paralympics, I want people to be able to see a h1 countdown I have placed at the top of my site. Underneath will be the looped results from my database. Any ideas where I go wrong? because in this if, it won't echo the h1 tag at all. I would like to above my results.
$query = " SELECT * FROM scan WHERE ";
$terms = array_map('mysql_real_escape_string', $terms);
$i = 0;
foreach ($terms as $each) {
if ($i++ !== 0) {
$query .= " OR ";
}
$query .= "keywords LIKE '%{$each}%'";
}
// Don't append the ORDER BY until after the loop
$query .= "ORDER BY rank";
$query = mysql_query($query) or die('MySQL Query Error: ' . mysql_error($connect));
$numrows = mysql_num_rows($query);
if ($numrows > 0) {
while ($row = mysql_fetch_assoc($query)) {
$id = $row['id'];
$title = $row['title'];
$description = $row['description'];
$keywords = $row['keywords'];
$link = $row['link'];
$rank = $row['rank'];
echo '<h2><a class="ok" href="' . $link . '">' . $title . '</a></h2>' . PHP_EOL;
echo '<p maxlength="10" class="kk">' . $description . '</p>' . PHP_EOL;
echo '<p><a class="okay" href="' . $link . '">' . $link . '<br><br><span class="keywords"></p>' . PHP_EOL;
}
} else {
echo "No results found for \"<b>{$k}</b>\"";
}
if ($k = "Paralympics 2012") {
echo "<h1> Countdown to Paralympics: 7 Days </h1>";
}

Answer 1

if ($k = "Paralympics 2012") {
echo "<h1> Countdown to Paralympics: 7 Days </h1>";
}
Will always print the <h1>. You're doing assignment rather than comparison. Try:
if ($k == "Paralympics 2012")
Also, verify that $k is what you expect it to be when debugging.

Answer 2

One equals (=) assigns, and two/three (==/===) compares. The line
if ($k = "Paralympics 2012") {
Assigns $k to a string, which always returns true, because any string other than an empty one ("") is truthy. Try this:
if ($k === "Paralympics 2012") {

Answer 3

First things first, the <h1> is always displaying, opposite of what you're question states. It's always displaying due to the fact that you're doing an assignment of a non-false value with:
if ($k = "Paralympics 2012") {
Update that to use a comparison to fix that logic issue.
if ($k == "Paralympics 2012") {
Next, to get it to display above your results, you need to actually move that if-statement above the loop that echos the results. Try placing it in the if ($numrows > 0) { block, like this:
if ($numrows > 0) {
if ($k == "Paralympics 2012") {
echo "<h1> Countdown to Paralympics: 7 Days </h1>";
}
while ($row = mysql_fetch_assoc($query)) {
...