Jquery/ PHP Show database after got updated - php

I have this jQuery which updates the DB on blur. It works fine except I want the code to show the current DB value after it got updated. There is a value in the database the amount in the field will be added to that and it gets updated. The only way to see that now is to refresh the page each time something gets updated.
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.5.2/jquery.min.js"></script>
<script type="text/javascript">
// JQUERY: Plugin "autoSumbit"
(function($) {
$.fn.autoSubmit = function(options) {
return $.each(this, function() {
// VARIABLES: Input-specific
var input = $(this);
var column = input.attr('name');
// VARIABLES: Form-specific
var form = input.parents('form');
var method = form.attr('method');
var action = form.attr('action');
// VARIABLES: Where to update in database
var where_val = form.find('#where').val();
var where_col = form.find('#where').attr('name');
// ONBLUR: Dynamic value send through Ajax
input.bind('blur', function(event) {
// Get latest value
var value = input.val();
// AJAX: Send values
$.ajax({
url: action,
type: method,
data: {
val: value,
col: column,
w_col: where_col,
w_val: where_val
},
cache: false,
timeout: 10000,
success: function(data) {
// Alert if update failed
if (data) {
document.getElementById("notice").innerHTML="Error, NO UPDATE";
}
// Load output into a P
else {
$('#notice').text('Updated');
$('#notice').fadeOut().fadeIn();
}
}
});
// Prevent normal submission of form
return false;
})
});
}
})(jQuery);
// JQUERY: Run .autoSubmit() on all INPUT fields within form
$(function(){
$('#ajax-form INPUT').autoSubmit();
});
</script>
HTML stuff
<label>Total:</label>
<input name="company" value="<?php echo $row['total'] ?>" />
<label>Tax-in:</label>
<input name="lastname" value="<?php echo $row['taxin'] ?>" />

After your PHP file inserts the row into the database, have it SELECT the new value from the database and echo it back on the AJAX response to jQuery. Then use jQuery to populate that new value wherever you want it to go.

Related

How can I use localStorage in php with AJAX to update my database?

I need to use a localStorage value in a PHP file to update values in my database. I know that I need ajax to achieve this, I can't get it to work.
My localStorage item is named option and it exists (checked in browser and stored the value in a div)
$(document).ready(function(){
$.ajax({
type: "POST",
url: "activity.php",
data: { storageValue: localStorage.getItem('option') },
success: function(data){
alert('success');
}
});
});
PHP Example:
$option = $_POST['storageValue'];
mysql_query("...SET x = '".$option."'...");
echo 'Update complete';
I dont see any post data nor do I get a response.
Thank you!
Your page:
<form>
<input type="hidden" value="thedatayouwanttopost" id="option"/>
</form>
<script src="Your_Js_File.js"></script>
Your JS file:
document.getElementById('option').submit(); // This submits the form
var storageValue = $('#option').val(); // This gets the value of the form once it has been posted to the .php file
$(document).ready(function(){
$.ajax({
type: "POST",
url: "activity.php",
data: { storageValue:storageValue },
success: function(data){
alert('success');
}
});
return false; // This stops the page from refreshing
});
Your PHP file to callback the data to AJAX and display the alert (activity.php):
...
$option = $_POST['storageValue']; // This is the post value of your hidden input on your page
mysql_query("...SET x = '".$option."'...");
?><input type="hidden" id="option" value="<?php echo $option; ?>"><?
// The input above posts the value of 'option' on your page back to your Ajax and spits out the request.
...

Ajax autosave multiple fields

I have a page that has fields editable via contenteditable. I am autosaving the fields via ajax after the user edits the field. The problem is, I have multiple fields on the same page and when I try to autosave more than one field, either one field won't work or gets overwritten with the same content as the other field.
This is the code that I am using to update the database and it works exactly how I want it to for the "name" field.
$('.editname').keyup(function() {
delay(function(){
var name= $('.editname').text();
$.ajax({
type:"post",
url:"update.php",
data:"name="+name,
success:function(data){
console.log('success!');
}
});
}, 500 );
});
var delay = (function(){
var timer = 0;
return function(callback, ms){
clearTimeout (timer);
timer = setTimeout(callback, ms);
};
})();
However if I try to edit it like the following or duplicate it and give it a different name, it will not work properly to update another field along with the first field.
$('.editname').keyup(function() {
delay(function(){
var name= $('.editname').text();
$.ajax({
type:"post",
url:"update.php",
data:"name="+name,
success:function(data){
console.log('success!');
}
});
}, 500 );
});
$('.editsummary').keyup(function() {
delay(function(){
var summary= $('.editsummary').text();
$.ajax({
type:"post",
url:"update.php",
data:"summary="+summary,
success:function(data){
console.log('success!');
}
});
}, 500 );
});
var delay = (function(){
var timer = 0;
return function(callback, ms){
clearTimeout (timer);
timer = setTimeout(callback, ms);
};
})();
What am I doing wrong in the above block of code?
Looks like a usual error developers get into when they copy and paste code.
var name= $('.editsummary').text();
This should read:
var summary = $('.editsummary').text();
EDIT
This is how you do it properly. Have one generic auto-save handler and re-use it.
For example (html/js):
<script type="text/javascript" src="http://code.jquery.com/jquery-1.10.2.min.js"></script>
<script type="text/javascript">
// When Page Loads
$(document).ready(function()
{
// Handle Auto Save
$('.autosaveEdit').keyup(function() {
var fieldName = $(this).attr('name');
var fieldValue = $(this).val();
delay(function() {
$.ajax({
type: "post",
url: "update.php",
data: { fName: fieldName, fValue: fieldValue },
success: function(data) {
console.log('success!');
}
});
}, 500 );
});
});
var delay = (function() {
var timer = 0;
return function(callback, ms) {
clearTimeout (timer);
timer = setTimeout(callback, ms);
};
})();
</script>
Firstname: <input type="text" class="autosaveEdit" name="firstname" />
<br />
Lastname: <input type="text" class="autosaveEdit" name="lastname" />
Now, on your update.php
<?php
// Get the post data
$fieldName = isset($_POST['fName']) ? $_POST['fName'] : '';
$fieldValue = isset($_POST['fValue']) ? $_POST['fValue'] : '';
// Now save the $fieldValue against $fieldName in your db (if neither is empty)
So, in my example form, if I start editing the "firstname" input field, the auto-save will post the following to update.php:
print_r($_POST)
Array
(
[fName] => firstname
[fValue] => hello
)
I've tweaked your example a little to get it to work with JS Fiddle:
http://jsfiddle.net/eHz4t/
<div class="editname" contenteditable="true">my name</div>
<div class="editsummary"contenteditable>my summary</div>
It works properly. You can open the network console and see the traffic being sent.

Jquery/ajax/php load data into textfield after clicking checkbox

How do i load data into textfields after clicking a checkbox & after doing it, i need to disable that textbox, but again as i uncheck it, need to remove that data & make the textbox enable to manually enter data. I tried this code,i'm new to jquery/ajax, can't figure out how to solve this problem.
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js">
</script>
<script>
$(document).ready(function(){
$('#chk').click(function(){
if($(this).is(":checked"))
$("#txtaddress").removeAttr("disabled");
else
$("#txtaddress").attr("disabled" , "disabled");
// here, i don't know how do i assign $row['address'] to txtaddress by
// using php mysql
});
});
</script>
<!-this is my html code-->
<form>
<input type="checkbox" id="chk" name="chk">Same as home address?
<input id="txtaddress" name="txtaddress" disabled type="text">
</form>
Try the following,
<script>
$(document).ready(function(){
$('#chk').click(function(){
if($(this).is(":checked"))
$("#txtaddress").val(""); //reset the textbox
$("#txtaddress").removeAttr("disabled");
else {
$.ajax({
type: 'GET',
url: destinationUrl, // your url
success: function (data) { // your data ie $row['address'] from your php script
$("#txtaddress").val(data); //set the value
$("#txtaddress").attr("disabled", "disabled");
}
});
}
});
});
</script>
From your php script you can echo $row['address'], so the data in success function can be put into textbox in ajax
javascript code:
$(document).ready(function(){
$('#chk').click(function(){
var txt = $("#txtaddress");
($(this).is(":checked")) ? txt.attr("disabled" , true) : txt.attr("disabled" , false);
});
});
I hope this is what u meant.. Hope this might help... :)
$('#chk').click(function(){
if(! $(this).is(":checked")){
$("#txtaddress").removeAttr("disabled");
$("#txtaddress").val('');
}
else{
$.ajax( {
url: "get_row_details",
type: "POST", //or may be "GET" as you wish
data: 'username='+name, // Incase u want to send any data
success: function(data) {
$("#txtaddress").val(data); //Here the data will be present in the input field that is obtained from the php file
}
});
$("#txtaddress").attr("disabled" , "disabled");
}
});
From the php file echo the desired $row['address'].This value will be obtained at the success of the ajax function

Show/hide div with jQuery and AJAX not working properly

I'm trying to show a specific div depending on the result of a SQL query.
My issue is that I can't get the divs to switch asynchronously.
Right now the page needs to be refreshed for the div to get updated.
<?php
//SQL query
if (foo) {
?>
<div id="add<?php echo $uid ?>">
<h2>Add to list!</h2>
</div>
<?php
} else {
?>
<div id="remove<?php echo $uid ?>">
<h2>Delete!</h2>
</div>
<?php
}
<?
<script type="text/javascript">
//add to list
$(function() {
$(".plus").click(function(){
var element = $(this);
var I = element.attr("id");
var info = 'id=' + I;
$.ajax({
type: "POST",
url: "ajax_add.php",
data: info,
success: function(data){
$('#add'+I).hide();
$('#remove'+I).show();
}
});
return false;
});
});
</script>
<script type="text/javascript">
//remove
$(function() {
$(".minus").click(function(){
var element = $(this);
var I = element.attr("id");
var info = 'id=' + I;
$.ajax({
type: "POST",
url: "ajax_remove.php",
data: info,
success: function(data){
$('#remove'+I).hide();
$('#add'+I).show();
}
});
return false;
});
});
</script>
ajax_add.php and ajax_remove.php only contain some SQL queries.
What is missing for the div #follow and #remove to switch without having to refresh the page?
"I'm trying to show a specific div depending on the result of a SQL query"
Your code doesn't seem to do anything with the results of the SQL query. Which div you hide or show in your Ajax success callbacks depends only on which link was clicked, not on the results of the query.
Anyway, your click handler is trying to retrieve the id attribute from an element that doesn't have one. You have:
$(".plus").click(function(){
var element = $(this);
var I = element.attr("id");
...where .plus is the anchor element which doesn't have an id. It is the anchor's containing div that has an id defined. You could use element.closest("div").attr("id") to get the id from the div, but I think you intended to define an id on the anchor, because you currently have an incomplete bit of PHP in your html:
<a href="#" class="plus" ?>">
^-- was this supposed to be the id?
Try this:
<a href="#" class="plus" data-id="<?php echo $uid ?>">
And then:
var I = element.attr("data-id");
Note also that you don't need two separate script elements and two document ready handlers, you can bind both click handlers from within the same document ready. And in your case since your two click functions do almost the same thing you can combine them into a single handler:
<script type="text/javascript">
$(function() {
$(".plus,.minus").click(function(){
var element = $(this);
var I = element.attr("data-id");
var isPlus = element.hasClass("plus");
$.ajax({
type: "POST",
url: isPlus ? "ajax_add.php" : "ajax_remove.php",
data: 'id=' + I,
success: function(data){
$('#add'+I).toggle(!isPlus);
$('#remove'+I).toggle(isPlus);
}
});
return false;
});
});
</script>
The way i like to do Ajax Reloading is by using 2 files.
The first: the main file where you have all your data posted.
The second: the ajax file where the tasks with the db are made.
Than it works like this:
in the Main file the user lets say clicks on a button.
and the button is activating a jQuery ajax function.
than the ajax file gets the request and post out (with "echo" or equivalent).
at this point the Main file gets a success and than a response that contains the results.
and than i use the response to change the entire HTML content of the certain div.
for example:
The jQuery ajax function:
$.ajax({
type: 'POST', // Type of request (can be POST or GET).
url: 'ajax.php', // The link to the Ajax file.
data: {
'action':'eliran_update_demo', // action name, used when one ajax file handles many functions of ajax.
'userId':uId, // Simple variable "uId" is a JS var.
'postId':pId // Simple variable "pId" is a JS var.
},
success:function(data) {
$("#div_name").html(data); // Update the contents of the div
},
error: function(errorThrown){
console.log(errorThrown); // If there was an error it can be seen through the console log.
}
});
The PHP ajax function:
if (isset($_POST['action']) ) {
$userId = $_POST['userId']; // Simple php variable
$postId = $_POST['postId']; // Simple php variable
$action = $_POST['action']; // Simple php variable
switch ($action) // switch: in case you have more than one function to handle with ajax.
{
case "eliran_update_demo":
if($userId == 2){
echo 'yes';
}
else{
echo 'no';
}
break;
}
}
in that php function you can do whatever you just might want to !
Just NEVER forget that you can do anything on this base.
Hope this helped you :)
if you have any questions just ask ! :)

Get value from jQuery AJAX to PHP

Working on a project where I want to be able to delete a dynamic record using jQuery and PHP. I already have the option for users to add a record dynamically it is just getting the delete option to work. While I am trying to develop this function I have set the Delete to INSERT. Where I am having trouble is getting the value from the hidden field to delete-class.php (the bottom script). Below I have posted the code:
<form id="frmDelete" method="post" action="delete-class.php">
<input id="btnSubmit" type="submit"/>
<ul id="class">
<?php
//this is being loaded from a different page and is here just to reference the fields
while ($row = mysql_fetch_array($result)) {
echo '<li id="liClass" class="ui-widget"><img src="trash-can-icon.png" id='.$row["id_distance_class"].' class="delete"/>' . $row["class_section"] . '<input type="hidden" name="hdid" id="hdid" value="'.$row["id_distance_class"].'"/></li>';
?>
</ul>
</form>
<script>
$(function() {
$(".delete").click(function() {
$('#load').fadeIn();
var commentContainer = $(this).parent();
var id = $(this).attr("id");
var string = id ;
// console.log(id);
$.ajax({
type: "POST",
url: "delete-class.php",
data: $(this).serialize(),
cache: false,
success: function(){
commentContainer.slideUp('slow', function() {$(this).remove();});
$('#load').fadeOut();
}
});
return false;
});
});
</script>
//this is the delete-class.php
$results = mysql_query("INSERT INTO distance_class (class_section) VALUES ( '".$_POST['hdid']."' ) ");
The problem is you're not passing this information in your AJAX request. You're passing
data: $(this).serialize()
...presumably thinking this points to the form. It doesn't; it points to the deletion button clicked, since this code is running in the button's event handler callback.
Change the above to target the form.

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