PHP - How to format this output using given array? - php

Question

So right now i have an array named $socialMeta, containing:
Array (
[0] => Array (
[socialFacebook] => Array (
[0] => http://www.facebook.com/someUsername
)
)
[1] => Array (
[socialYoutube] => Array (
[0] => http://www.youtube.com/user/someUsername
)
)
[2] => Array (
[socialSoundcloud] => Array (
[0] => http://www.soundcloud.com/someUsername
)
)
)
From this array I need to create the following output:
<div class="social">
Add us on <span>Facebook</span>
Visit us on <span>Youtube</span>
Visit us on <span>Souncloud</span>
</div>
Please not that there are different anchor text for the first link.
For anchor classes i can use $socialMeta key to make whole process a bit easier.

Answer 1

<?php if (!empty($socialMeta)) { ?>
<div class="social">
<?php foreach ($socialMeta as $rows) {?>
<?php foreach ($rows as $key => $val) {?>
<?php
switch ($key) {
case "socialFacebook":
$title = "Facebook";
$class = "fb";
break;
case "socialYoutube":
$title = "Youtube";
$class = "yt";
break;
case "socialSoundcloud":
$title = "Souncloud";
$class = "sc";
break;
}
?>
Add us on <span><?php echo $title; ?></span>
<?php }?>
<?php }?>
</div>
<?php }?>

Answer 2

Start by identifying the network for each element in the array (I assume the name is $array in the following examples):
function add_network($array) {
static $networks = array('Facebook', 'Youtube', 'Soundcloud');
foreach($networks as $network)
if (isset($array['social' . $network])) {
$array['network'] = $network;
return $array;
}
//None found
$array['network'] = false;
return $array;
}
$array = array_map('add_network', $array);
Then transform the array (you should find a better name for this function):
function transform_array($a) {
static $classes = array('Youtube' => 'yt', 'Facebook' => 'fb', 'Soundcloud' => 'sc');
$network = $a['network'];
$class = $classes[$network];
$url = $a['social' . $network][0]
return array('network' => $network,
'url' => $url,
'class' => $class);
}
$array = array_map('transform_array', $array);
And now just loop over the elements of $array:
foreach($array as $row) {
$network = $row['network'];
$url = $row['url'];
$class = $row['class'];
if ($network === 'Facebook')
$link_text = 'Add us on <span>%s</span>';
else
$link_text = 'Visit us on <span>%s</span>'
$link_text = sprintf($link_text, $network);
printf('%s',
$url, $class, $link_text);
}

Answer 3

<?php
function flattenArray(array $input){
$nu = array();
foreach($input as $k => $v){
if(is_array($v) && count($v) == 1){
$nu[key($v)] = current($v);
if(is_array($nu[key($v)]) && count($v) == 1)
$nu[key($v)] = current($nu[key($v)]);
}
else
$nu[$k] = $v;
}
return $nu;
}
// here you can maintain the sortorder of the output and add more social networks with the corresponding URL-text...
$urlData = array(
'socialFacebook' => 'Add us on <span>Facebook></span>',
'socialYoutube' => 'Visit us on <span>Youtube</span>',
'socialSoundcloud' => 'Visit us on <span>Souncloud</span>',
);
$testArray = array(
array('socialFacebook' => array('http.asdfsadf')),
array('socialYoutube' => array('http.asdfsadf')),
array('socialSoundcloud' => array('http.asdfsadf'))
);
$output = flattenArray($testArray);
HERE WE GO
echo '<div class="social">';
foreach($urlData as $network => $linkText){
if(!empty($output[$network]))
echo sprintf('%s</span>', $output[$network], $linkText);
}
echo '</div>';