Now before we begin let me inform you all that this is just a school assignment and that I am not overly an expert in php and sql coding.
I have the problem, whenever I execute the script, I receive the following error:
Notice: Undefined variable: Team in
C:\xampp\htdocs\NFL\searchmatches.php on line 30.
From my understanding, there would be a spelling error in the link up between the script and the form file, but I can't seem to find the problem.
This is a file to search the database:
Script:
<?php
mysql_connect("localhost","root","0gd1d0wgpg") or die(mysql_error());
mysql_select_db("NFL") or die(mysql_error());
$query=mysql_query("SELECT * FROM Matches where Team ='$Team'") or die(mysql_error());
$numfields = mysql_num_fields($query);
print("<table border=\"1\">\n<tr>\n");
for ($i=0; $i<$numfields; $i++) {
printf("<th>%s</th>\n", mysql_field_name($query,$i));
}
print("</tr>\n");
while ($row = mysql_fetch_row($query)) {
print("<tr>\n");
for ($i=0; $i<sizeof($row); $i++) {
printf("<td>%s</td>\n", $row[$i]);
}
print("</tr>\n");
}
print("</table>\n");
?>
Form:
<form name="addmatch" method="post" action="searchmatches.php">
Search for the match history of a particular team here.<br>
<br>
Team Name: <input type="text" name="Team_Name" value="Team Name">
<br>
<br>
<input type="submit" value="Search">
</form>
Yes there is more coding in the actual files but I figured that, the PHP would be all you needed to help me.
So could somebody please tell me how rid of this error and make the search work.
PHP uses a special "super global" to give you access to submitted form values. The $_POST superglobal is an array with keys that match the name attribute of the form elements (when the form is submitted with the "post" method). Add this line:
$Team = mysql_real_escape_string($_POST['Team_Name']);
above the use of $Team in the query.
To recap, the 'Team_Name' identifier comes from your HTML:
<input type="text" name="Team_Name" value="Team Name">
and then when the form is submitted, whatever you put in that form control is available at $_POST['Team_Name']. I passed the value through the "escape" function so to protect your query from going bonkers (or worse) if that value happened to contain special characters.
Related
The newbie is back with another question. Any help would be much appreciated. Suppose we have got a form in which we have written down the name of a user and in front of which there is an input box in which we can allocate a grade to the mentioned user. Within this scenario, everything is clear. We have a form with the name of user (it's 'id' as the value) and another variable, that is the grade' which are posted to the php-action-page. Hence, in the php-action-page, I get two variables, one is the id of the user and the other allocated grade, through POST. Here, everything is clear and the process easy, since I have got just two defined variables. Now, suppose that we are inserting a list of users from our 'Users' table into the form dynamically. We fill our form with for example 10 users grabbed from the database. In front of them there are input boxes for the 'grade' to be inserted into. So far, everything is fine. The problem, though, lies in the next stage. The problem is I don't know how to ask php-action-page to do the insert, that is insert the grade in the database for specific users as long as there are posted variables of users. Here I have tens of users and tens of dynamic variables. And if the question is a little bit vague, please do excuse me; yet, do your best to get me free from this condition of bafflement. Many thanks.
Here comes some bits of the code to make the problem a little more clear.
I start with the following code:
<?php
require_once ('../inc/takein.php');
$pd = new dbase();
$students = $pd->run_a_query('SELECT * from `checking`');
Here I am including the database and other necessary files. Then I run a query to fetch a list of my students from the table. So far, everything is fine. The next line of action which makes me perplexed is the following code.
Before having a look at the code may you please look at the html design in the following picture:
Final Design
I totally have no idea about it being wrong or correct. You might help with this bit as well.
<form action="grades.php" method="post">
<table class="table table-bordered font-label" id="item_table">
<?php
foreach ($students as $student) {
echo '<tr>';
echo '<td>'.$student['name'].'</td>';
echo '<td><input type="text" name="grade[]" class="form-control omit-radius-input"></td>';
echo '<input type="hidden" name="id[]" value="'.$student['id'].'">';
echo '<tr>';
}
?>
</table>
<input type="submit" name="dispatched" class="btn btn-green">
</form>
Here, I am putting the information in a table within the form element. As you can see in the above picture, I am getting four students from the database. Now I want to send these students back to the database along with their newly set grades. What I want to be posted here is the student id and their grades.
Then, the following is the last part of the code which is left incomplete because I couldn't make any senses how to do it.
if (isset($_POST['dispatched'])) {
$id[] = $_POST['id'];
$grade[] = $_POST['grade'];
// what to do now???!!!
foreach(...HOW TO DO THE 'FOREACH') {
...
}
}
May you please help me insert my student grades. Many thanks in advance.
Simply name your variables as arrays - if your form looks like this
<form method="POST">
<input type="text" name="grade[12]">
<br>
<input type="text" name="grade[15]">
<br>
<input type="text" name="grade[7]">
<br>
<input type="text" name="grade[21]">
<!-- continue here -->
</form>
then in your PHP code you will access the grades like this
if(is_array($_POST['grade'])) foreach($_POST['grade'] as $id => $value)
{
// REPLACE INTO user_grades(user_id, grade) VALUES($id, $value)
}
UPDATE
You should also put the ID of your students in the name of the INPUT field - otherwise you won't know for which student is the given grade.
<?php
foreach ($students as $student) {
echo '<tr>';
echo '<td>'.$student['name'].'</td>';
echo '<td><input type="text" name="grade['.$student['id'].']" class="form-control omit-radius-input" value="'.$student['current_grade'].'"></td>';
echo '<tr>';
}
?>
The foreach is shown above in my original answer.
i have 5 textboxes with the name of textbox1,textbox2 ... textbox5. now what i want is that instead of putting each of their value in a variable individually I want to do it in a loop, i have my code here but after i enter submit errors like
Array to string conversion in ...
and
Undefined index: textboxArray in...
.please see what's wrong with my code.
if(isset($_POST['submit'])){
for($i=0; $i<5; $i++){
$sasa = $_POST["textbox".[$i].""];
$sql="INSERT into sasa (sasa) values('$sasa')";
$q=$conn->query($sql);
}
}
This is incorrect:
$sasa = $_POST["textbox".[$i].""];
^^^^
[$i] defines a new array with a single integer in it, which you then concatenate into a string. Arrays used in a string context simply become the literal word Array, which means you're effectively running this:
$sasa = $_POST["textboxArray"];
which doesn't exist in your form.
You want
$sasa = $_POST["textbox{$i}"];
instead. Note the {}.
And note that your code is vulnerable to sql injection attacks.
The problem is this line: $sasa = $_POST["textbox".[$i].""];
You should do it as follows:
if(isset($_POST['submit'])){
if(is_array($_POST["textbox"])){
foreach($_POST["textbox"] as $sasa){
//This is unsafe, use prepared statements instead
$sql="INSERT into sasa (sasa) values('$sasa')";
$q=$conn->query($sql);
}
}
}
This allows you to write your form like:
<form method="post" ... >
<input type="text" name="textbox[]"/>
<input type="text" name="textbox[]"/>
<input type="text" name="textbox[]"/>
<button type="submit">Submit</button>
</form>
In answer to your comment, this is how you could add/remove inputs dinamically using jQuery:
var control = $('<div class="controls"></div>');
control.append("<input class='form-control' type='text' name='textbox[]' placeholder='textbox'/><a href='#' class='remove_this btn btn-danger'>remove</a>");
control.appendTo('form');
control.find('.remove_this').click(function(){
control.remove();
});
I am doing a project in which as per number getting by GET method, I display dynamic number of HTML Textbox for storing Multiple values. I am giving each textbox unique name+id in ascending manner starting from 1(Like textbox1,textbox2). Now I want that when I click on submit button, it should fire an insert statement which insert all textbox values at once. I know I can do by array, but my question is that how to get all textbox's value in an array and How to perform insert statement?
I have done following code:
Here is PHP Code for submit button:
$schedules = array();
if(isset($_POST['submit']))
{
for($d=1; $d<=$_GET['totalDay'] ;$d++)
{
array_push($schedules,$_POST['txtSchedule'.'$d']);
}
print_r($schedules);
}
Here is the html code:
<form method="post">
<table>
<tr>
<td>Day</td>
<td>Schedule</td>
</tr>
<?php
if(isset($_GET['tour_code']) and ($_GET['totalDay']!=1))
{
$tour_code = $_GET['tour_code'];
$total = $_GET['totalDay'];
$i=0;
do
{
$i=$i+1;
?>
<tr>
<td><?php echo $i;?></td>
<td>
<input name="txtSchedule<?php echo $i;?>" type="text" size="30"/>
</td>
</tr>
<?php
$start = date('Y-m-j',strtotime($start.'+1 days'));
}while($i!=$total);
}
?>
</table>
<input type="submit" name="submit" value="Add Tour Details" />
But I am getting an empty array.
Note: $total is coming through URLString's $GET method.
Below is the output of HTML:
Simplest thing first. You have an error, you can't use
array_push($schedules,$_POST['txtSchedule'.'$d']);
You must use DOUBLE QUOTES on the $d (single quotes won't evaluate d, it will literally read "txtSchedule$d" with a dollar sign, and not actually 0, 1,..., n)
array_push($schedules,$_POST['txtSchedule'."$d"]);
//or no quotes at all
array_push($schedules,$_POST['txtSchedule'.$d]);
(that may sovlve your problems)
But now let's get to how to make an array available to the $_POST object in the processing page via form naming conventions
You're not using array syntax, but you are oh-so close. In PHP, whatever is submitted needs to be of an expected format, and iterating txtSchedule0, txtSchedule1, ...txtScheduleN is not an Array(), but $_POST[] is an array that contains each (given what you've named your input fields, which is missing 1 small thing - square brackets).
What you need to do is be naming your inputs as an array is the array name followed by square brackets (arrayName[]), here is how you create an input array of the name txtSchedule (that way when you print_r($_POST['txtSchedule']) you get an Array())
<input name="txtSchedule[<?php echo $i;?>]" type="text" size="30"/>
I had the same issue when I started in PHP, you were forgetting the square brackets around [<?php echo $i;?>]
Just make sure that if you want to do an iteration over an array of inputs:
for($i=0; $i < count($_POST['txtSchedule']); $i++){
echo "They entered " . $_POST['txtSchedule'][$i] . " in the $i" . "th position";
}
... you have used the <input name="arrayName[$i]"> sytax, or even more simply <input name="arrayName[]"> for it to auto-magically generate an array on submit in the order the inputs were in the HTML page. The naming convention is so important, and since you have it wrong (you used arrayName0, arrayName1, ... arrayNameN instead of arrayName[0], arrayName[1], ... arrayName[n]), it will never be available to you as an array.
if i understand your question correctly you are trying to retrive user input from each textbox and save it in an array?
if so I would use jquery to select all textboxes and loop through them and retrive the value
If you are looking purely at the SQL syntax, then you can just append extra records to insert at the end of your query by providing more value sets:
INSERT INTO myTable (fieldName1, fieldName2) values ("Value1A", "Value1B"), ("Value2A", "Value2B")
If you looking at the PHP logic, then my first suggestion is to use the http POST method instead of GET. Then start with processing the $_POST fields:
$data= array();
foreach($_POST as $key => $value) {
if (preg_match('/^TextBox\d+$/', $key)) {
$data[] = $mysqli->real_escape_string($value);
}
}
The construct the SQL query based on the available data
if (count($data) > 0) {
$sql = 'INSERT INTO `myTable` VALUES("' . implode('"),("', $data).'")';
// log query
// execute query
// process query results
// redirect user to a thankyou page
header('Location: thankyou.php');
}
Note that the code assumes that you have a mysqli connection instance available at $mysqli
Not sure if this is what you are looking for but should give you at least a start..
String []ar=request.getParameterValues("name");
String cmd=request.getParameter("cmd");
if(cmd==null) cmd="";
if(cmd.equals("Submit")){
for(int i=0;i<ar.length;i++) {
insert logic;
<form method="post" action="page3.jsp">
<br/><input type="text" name="name"/>
<br/><input type="text" name="name"/>
<br/><input type="text" name="name"/>
<br/> <input type="submit" value="Submit" name="cmd"/>
</form>
Orignal post http://www.daniweb.com/web-development/jsp/threads/197777/insert-dynamic-textbox-value-in-database
This is more of a technique question rather than maybe code. I am having a php form with many fields (items to select). Naturally some of the items might be selected and some not. How do I know which ones are selected when i post the data from page 1 to page 2? I thought of testing each one if empty or not, but there are just too many fields and it doesn't feel at all efficient to use or code.
Thanks,
UPDATE EDIT:
I've tried the following and maybe it will get me somewhere before I carry on testing the repliers solutions...
<html>
<body>
<form name="test" id="name" action="testprocess.php" method="POST">
<input type="text" name="choices[shirt]">
<input type="text" name="choices[pants]">
<input type="text" name="choices[tie]">
<input type="text" name="choices[socks]">
<input type="submit" value="submit data" />
</form>
</body>
</html>
and then second page:
<?php
$names = $_POST['choices'];
echo "Names are: <br>";
print_r($names);
?>
This gives out the following:
Names are: Array ( [shirt] => sdjalskdjlk [pants] => lkjlkjlk [tie]
=> jlk [socks] => lkjlkjl )
Now what I am going to try to do is iterate over the array, and since the values in my case are numbers, I will just check which of the fields are > 0 given the default is 0. I hope this works...if not then I will let you know :)
I think what you're looking for is this:
<form action="submit.php" method="POST">
<input type="checkbox" name="checkboxes[]" value="this" /> This
<input type="checkbox" name="checkboxes[]" value="might" /> might
<input type="checkbox" name="checkboxes[]" value="work" /> work
<input type="submit" />
</form>
And then in submit.php, you simply write:
<?php
foreach($_POST['checkboxes'] as $value) {
echo "{$value} was checked!";
}
?>
The square brackets in the name of the checkbox elements tell PHP to put all elements with this name into the same array, in this case $_POST['checkboxes'], though you could call the checkboxes anything you like, of course.
You should post your code so we would better understand what you want to do.
But from what I understood you are making a form with check boxes. If you want to see if the check boxes are selected, you can go like this:
if(!$_POST['checkbox1'] && !$_POST['checkbox2'] && !$_POST['checkbox3'])
This looks if all the three check boxes are empty.
Just an idea:
Create a hidden input field within your form with no value. Whenever any of the forms fields is filled/selected, you add the name attribute of that field in this hidden field (Field names are saved with a comma separator).
On doing a POST, you can read this variable and only those fields present in this have been selected/filled in the form.
Hope this helps.
Try this.....
<?php
function checkvalue($val) {
if($val != "") return true;
else return false;
}
if(isset($_POST['submit'])) {
$values = array_filter(($_POST), "checkvalue");
$set_values = array_keys($values);
}
?>
In this manner you can get all the values that has been set in an array..
I'm not exactly sure to understand your intention. I assume that you have multiple form fields you'd like to part into different Web pages (e.g. a typical survey form).
If this is the case use sessions to store the different data of your forms until the "final submit button" (e.g. on the last page) has been pressed.
How do I know which ones are selected when i post the data from page 1 to page 2?
is a different question from how to avoid a large POST to PHP.
Assuming this is a table of data...
Just update everything regardless (if you've got the primary / unique keys set correctly)
Use Ajax to update individual rows as they are changed at the front end
Use Javascript to set a flag within each row when the data in that row is modified
Or store a representation of the existing data for each row as a hidden field for the row, on submission e.g.
print "<form....><table>\n";
foreach ($row as $id=>$r) {
print "<tr><td><input type='hidden' name='prev[$id]' value='"
. md5(serialize($r)) . "'>...
}
...at the receiving end...
foreach ($_POST['prev'] as $id=>$prev) {
$sent_back=array( /* the field values in the row */ );
if (md5(serialize($sent_back)) != $prev) {
// data has changed
update_record($id, $sent_back);
}
}
I am going back though a web-based document numbering system from few weeks ago. To sum it up, the user types in the project,class,base, and dash number (PPP-CCC-BBBB-DDD) then it is added to a mysql database. Now most doc numbers go in order according to revisions. IE: A document 1465-630-0001-000 becomes, after revision, 1465-630-0002-000.
The boss wants the system to automatically fill the input text box for the base number if it detects that the user is entering a revised doc. So if a user types in 1465 into the project field and 630 into the class field the system should autofill the base field with the next available number. In the previous example this would be 0002.
It needs to be able to search the database for the first two fields so that it can find the next available one. Is there anyway to do this using javascript or something? SO was really helpful with my last javascript question pertaining to this system.
heres an bit of my code if it helps:
` ?>
<div id='preview'></div>
<form id='item' action="submit.php?item=1" method="post">
Enter Title:<input type="text" name="title" size="20"><BR>
Choose Project Code:
<SELECT NAME="project">
<OPTION VALUE="">Project...
<?
$query = "SELECT * FROM project ORDER BY project asc";
$result = mysql_query($query);
while($row = mysql_fetch_assoc($result))
{
$num = ($row['project']);
$name = ($row['description']);
?>
<OPTION VALUE="<?=$num?>" ><? echo"{$num}" . " | " . "{$name}";?>
<?
}
?>
</SELECT><BR>
Choose Class Code:
<SELECT NAME="class">
<OPTION VALUE="">Class...
<?
$query = "SELECT * FROM class ORDER BY class asc";
$result = mysql_query($query);
while($row = mysql_fetch_assoc($result))
{
$num = ($row['class']);
$name = ($row['description']);
?>
<OPTION VALUE="<?=$num?>" ><? echo"{$num}" . " | " . "{$name}";?>
<?
}
?>
</SELECT><BR>
Assigned Base Number:<input type="text" name="base" size="20"><BR>
Enter Dash Number:<input type="text" name="dash" size="20"><BR>
Enter Comments:<input type="text" name="comment" size="40"><BR>
<input type="hidden" name="item" value="1"/> `
Just a simple html/php input form with the project and class code list generated from a database pertaining to each.
Thanks for any help-Thomas
Update:
So, you're going to need to make an AJAX call (see example in my comment below) to some PHP script that will retrieve the base value you want and then returns that to the AJAX request. Once the request gets a response, you can use that data to fill in the value the way I originally said...
On a side note, since the example I gave you is a jQuery AJAX function, you should probably check out how to use jQuery to select elements on the page, instead of using straight JS.
E.g. for getting by ID and replacing value:
$("#base").attr('value', valueFromAjaxCall);
How to change value with JS:
If you use PHP to get the base value you want to fill into the field, then you can fill the value in with:
var baseField = document.getElementsByName("base")[0];
baseField.value = <?=$baseValue?>;
The getElementsByName() call returns an array, which is why you have to index into the field you want. I would suggest giving your <input> an id so that you can use document.getElementById() instead. You would do something like:
<input type="text" id="base" size="20">
and the JS to get the input element would be:
var baseField = document.getElementById("base");
...therefore, no need to index, in case you named any fields with the same name.
**Not sure about the PHP syntax.
An ajax call on focus of the 3rd field firing back to the server the values of the first two fields?
first, you'll probably want to use jQuery since it has great support is easy to use and will feel familiar to someone used to PHP.
so include your jQuery javascript code that you can get from :
http://jquery.com/
then, assume a form that looks like:
{form}
<input type=text id='major' name='major' value=''>
{Or a select, your choice}
<input type=text id='minor' name='minor'>
{or a select again}
<input type=text id='sequence' name='sequence' onFocus='getNextSequence()'>
...
{/form}
in your head, have your javascript:
function getNextSequence(){
var major=$('#major').val();
var minor=$('#minor').val();
if(!major){
alert('Select a major version#');
$('#major').focus();
return(false);
}
if(!minor){
alert('Select a minor version#');
$('#minor').focus();
return(false);
}
$.getJSON('http://url.to.getnextNumber.php',
{major:major,minor:minor},
function(data){
if(!data.error){
$('sequence').val(data.nextSequence);
}else{
alert(data.error);
}
}
});
}
the jQuery getJSON call will make a call back to your URL with two $_POST variables, major and minor. do your query, save the result as $result=array('nextSequence'=>$x,'error'=>'false');
and convert it to JSON with echo json_encode($result);
don't include ANY headers or any other content in the output of that file, and jQuery will pull the correct value and insert it where it's supposed to bed