I am wondering if there is a way to select part of a column in mysql. For example, I want to select all statistics from my table that end in "_sep_2012". This would give me access to 1_sep_2012, 2_sep_2012, 3_sep_2012 etc...Is there a way to do this?
<?php
$query=mysql_query("SELECT %_sep_2012% FROM statistics WHERE id = '$id'");
$array = mysql_fetch_row($query);
$monthly_total = $array[0];
echo "$monthly_total";
?>
Any assistance would be greatly appreciated. Thanks!
According to your question it should be possible to do something like:
SELECT * FROM statistics WHERE datecolumn LIKE '%_sep_2012'
Not saying it's nice but it should get the data you need. You can add GROUP BY clauses to do a count or sum to get your total like:
SELECT datecolumn, SUM(amountcolumn) FROM statistics WHERE datecolumn LIKE '%_sep_2012' GROUP BY datecolumn
Write this in PHP:
for($i=1;$i<32;$i++)
printf("`%d_sep_2012`, ", $i);
Try this
SELECT * FROM statistics WHERE datecolumn LIKE '%_sep_2012' and id = '$id'
Related
SELECT * FROM (`poll`) WHERE `poll_id` IN ('6,10,5,9,1') AND `poll_status` = '1'
I tried this query. I expected It would give result as I gave. But It sorting the result automatically in ascending. I need result as I give. Kindly give me a solution. Thanks in advance.
You can use FIELD in mysql:
SELECT *
FROM (`poll`)
WHERE `poll_id` IN (6,10,5,9,1)
AND `poll_status` = 1
ORDER BY FIELD(`poll_id`,6,10,5,9,1)
You have to separate your ids like that:
SELECT * FROM (`poll`) WHERE `poll_id` IN (6,10,5,9,1) AND `poll_status` = '1'
I want to select record from table with key.My code is working but it's not select all record regarding Php and Mysql it select only PHP,Mysql record.
My code is
$skill=PHP,Mysql;
mysql_query("select * from tablename(skill) where fieldname(key) like '%$skill%'");
Try to do this
mysql_query("select * from skill where (key like '%PHP%' OR key like '%Mysql%')");
As you have comma separated values in $skill variable like operator will not work correctly, try using following query
select * from skill where FIND_IN_SET(keyn,'$skill')
Demo sql fiddle at http://sqlfiddle.com/#!2/181c74/5
$skill="PHP,Mysql";
mysql_query("select * from skill where key like '%$skill%'");
I am assuming you want to search for records that contain "PHP", "MySQL", or both. What you're doing is searching for the exact string of "PHP,MySQL".
A quick and dirty solution would be to turn $skill into an array that is split on the commas and then perform the search for each term using the OR keyword.
For example:
$skill = array("PHP", "MySQL");
$query = "select * from tablename(skill) where ";
foreach ($skil in $skill)
$query . "fieldname(key) like '%$skil%' OR ";
//code to remove the OR at the very end
Use in into your Query
select * from `skills` WHERE skillslist in ('Php','Javascript')
Run demo Fiddle
I can not find a proper answer to this question. I have a very simple code for making a query in mysql to select the row with the maximum value in a determined column (called popularity) from a table (called comments). Every row has a column named comment_id
here is the code:
$connect_error = 'Sorry, try again, there was a connection error';
$con = mysqli_connect('localhost','user_name','password') or die($connect_error);
mysqli_select_db($con, 'database') or die($connect_error);
$result = mysqli_query($con, "SELECT MAX(`popularity`) FROM `comments`");
while ($row = mysqli_fetch_assoc($result)) {
$most_popular = $row['comment_id'];
}
echo "most popular is: $most_popular";
mysqli_free_result($result);
mysqli_close($con);
the screen does not show a proper result. Can someone give me an advice in this regard?
Thank you
You are looking to display the comment_id field, but you don't have that in your SELECT query. You are only selecting the max popularity value, and nothing else.
Try this for your query:
SELECT comment_id FROM comments ORDER BY popularity DESC LIMIT 1
This is sorting your comments by popularity, and then just picking the top one.
Of course you can easily change that to select more columns or even a SELECT * if you want to be able to display other values in this record.
To select the row with max 'popularity' column use this query;
$result = mysqli_query($con, "SELECT * FROM `comments` ORDER BY `popularity` DESC LIMIT 1");
In case you want all sorted by popularity remove the LIMIT 1...
You need
SELECT MAX(`popularity`) AS comment_id FROM `comments`
This will give the column the correct name for the associated array.
You are trying to read the result from a column named comment_id when the result from your query will be named MAX(popularity)
Run this query in mysql "SELECT MAX(popularity) FROM comments" first.The output of this gives you the index to use with $row[index] ie first row which in this case the index will be popularity else just change $row[content_id] to $row[popularity]
I am very new to using PHP so I am asking for some help. I have this code which works fine (I got it online from somewhere).
$data = mysql_query("SELECT * FROM products")
or die(mysql_error());
print "<table border cellpadding=3>";
while($info = mysql_fetch_array( $data ))
{
print "<tr>";
print "<th>title:</th> <td>".$info['title'] . "</td> ";
print "<th>info:</th> <td>".$info['information'] . " </td></tr>";
}
print "</table>";
But what PHP would I use to pull just one cell? For example, I have 9 items in my db with productIDs how could I call just the name or price or description for that particular product?
Thanks in advance.
It sounds like you want a particular row, in which, case you would just changes your query to filter for some specific value that identifies the row. THis might look something like this:
SELECT * FROM products WHERE product_id = ?
Where ? is the known product_id value that you want to receive the full record for.
Also, since you are just learning, I should point out that you should not learn to use mysql_* functions. They are deprecated. Learn mysqli or PDO for interacting with MySQL.
To obtain just one cell try the following:
SELECT CellName FROM TableName Where productId = x
So to get the price you would do:
SELECT price FROM products WHERE productid=x
Where productid equals the specific product you talked about.
if you want to understand a bit more mysql I advise you to go to PhpMyAdmin and try those and think about the result:
SELECT * FROM products;
SELECT title, information AS lol FROM products;
SELECT title, count(*) AS count FROM products;
SELECT * FROM products WHERE title = 'XXXX';
SELECT *, count(*), CHAR_LENGTH(title) FROM products;
SELECT title AS lol FROM products;
you will understand better the query language i thinks.
please read this chapter http://dev.mysql.com/doc/refman/5.0/en/examples.html. it'll really help you.
I just want to say, you can retrieve any columns(s) in any condition column
SELECT column_name(s) FROM products WHERE colmnm_name = ?
I'm trying to add a single column in a db query result. I've read about the SUM(col_name) as TOTAL, GROUP BY (col_name2).
But is there a way i can only SUM the column without any GROUPing? I a case whereby all col_name2 are all unique.
For example... I have a result with the following col headers:
course_code
course_title
course_unit
score
grade
Assuming this have 12 rows returned into an HTML table. Now i want to perform SUM() on all the values (12 rows) for the column course_unit, in other to implement a GPA school grading system.
How can i achieve this.
Thanks.
SELECT SUM(col_name) as 'total' FROM <table>
GROUP BY is required only if you want to sum subsets of the rows in the table.
You can find sum or any aggregate db functions (such as count, avg, etc) for most cases without using group clause. Your sql query may look something like this:
SELECT SUM(course_unit) as "Total" FROM <table_name>;
As comments below have already pointed out: SELECT SUM(course_unit) AS total FROM your_table;. Note that this is a separate query to the one with which you retrieve the table data.
This does it in php. I'm not sure how to do it with pure sql
$query = "SELECT * FROM table";
$result = mysql_query($query);
$sum = 0;
while($row = mysql_fetch_assoc($result))
{
$sum+= intval($row['course_unit']);
}
echo $sum;
SELECT
course_code,
course_title,
course_unit,
score, grade,
(select sum(course_unit) from TableA) total
from TableA;