class A
{
static function get_name_derived_class()
{
//This function must return the name of the real class
//Is it possible without insert a methon in B class?
{
}
class B extends A
{
}
B::test()
I'd like to have a static methon in base class which returns the name of real (derived) class, without insert a specific method in it. is it possible?
thanx
<?php
class A
{
static function test()
{
return get_called_class();
}
}
class B extends A
{
}
echo B::test();
Requires PHP >= 5.3.0. See PHP's manual entry on Late Static Bindings
Related
I have two classes: Action and MyAction. The latter is declared as:
class MyAction extends Action {/* some methods here */}
All I need is method in the Action class (only in it, because there will be a lot of inherited classes, and I don’t want to implement this method in all of them), which will return classname from a static call. Here is what I’m talking about:
Class Action {
function n(){/* something */}
}
And when I call it:
MyAction::n(); // it should return "MyAction"
But each declaration in the parent class has access only to the parent class __CLASS__ variable, which has the value “Action”.
Is there any possible way to do this?
__CLASS__ always returns the name of the class in which it was used, so it's not much help with a static method. If the method wasn't static you could simply use get_class($this). e.g.
class Action {
public function n(){
echo get_class($this);
}
}
class MyAction extends Action {
}
$foo=new MyAction;
$foo->n(); //displays 'MyAction'
Late static bindings, available in PHP 5.3+
Now that PHP 5.3 is released, you can use late static bindings, which let you resolve the target class for a static method call at runtime rather than when it is defined.
While the feature does not introduce a new magic constant to tell you the classname you were called through, it does provide a new function, get_called_class() which can tell you the name of the class a static method was called in. Here's an example:
Class Action {
public static function n() {
return get_called_class();
}
}
class MyAction extends Action {
}
echo MyAction::n(); //displays MyAction
Since 5.5 you can use class keyword for the class name resolution, which would be a lot faster than making function calls. Also works with interfaces.
// C extends B extends A
static::class // MyNamespace\ClassC when run in A
self::class // MyNamespace\ClassA when run in A
parent::class // MyNamespace\ClassB when run in C
MyClass::class // MyNamespace\MyClass
It's not the ideal solution, but it works on PHP < 5.3.0.
The code was copied from septuro.com
if(!function_exists('get_called_class')) {
class class_tools {
static $i = 0;
static $fl = null;
static function get_called_class() {
$bt = debug_backtrace();
if (self::$fl == $bt[2]['file'].$bt[2]['line']) {
self::$i++;
} else {
self::$i = 0;
self::$fl = $bt[2]['file'].$bt[2]['line'];
}
$lines = file($bt[2]['file']);
preg_match_all('/([a-zA-Z0-9\_]+)::'.$bt[2]['function'].'/',
$lines[$bt[2]['line']-1],
$matches);
return $matches[1][self::$i];
}
}
function get_called_class() {
return class_tools::get_called_class();
}
}
Now (when 5.3 has arrived) it's pretty simple:
http://php.net/manual/en/function.get-called-class.php
class MainSingleton {
private static $instances = array();
private static function get_called_class() {
$t = debug_backtrace();
return $t[count($t)-1]["class"];
}
public static function getInstance() {
$class = self::get_called_class();
if(!isset(self::$instances[$class]) ) {
self::$instances[$class] = new $class;
}
return self::$instances[$class];
}
}
class Singleton extends MainSingleton {
public static function getInstance()
{
return parent::getInstance();
}
protected function __construct() {
echo "A". PHP_EOL;
}
protected function __clone() {}
public function test() {
echo " * test called * ";
}
}
Singleton::getInstance()->test();
Singleton::getInstance()->test();
(PHP 5 >= 5.3.0, PHP 7)
get_called_class — The "Late Static Binding" class name
<?php
class Model
{
public static function find()
{
return get_called_class();
}
}
class User extends Model
{
}
echo User::find();
this link might be helpfull
There is no way, in the available PHP versions, to do what you want. Paul Dixon's solution is the only one. I mean, the code example, as the late static bindings feature he's talking about is available as of PHP 5.3, which is in beta.
we have one class
class A
{
// I am using class B here
public function whatever()
{
$class_b = new B;
$class_b->show_caller();
}
}
and other
class B
{
public function show_caller()
{
// show me the caller class (should output "A")
}
}
I need to get the caller class name.
P.S. Inheritance is not an option!
Pass class A as a parameter to B::show_caller() and output it's class name using get_class():
class A
{
// I am using class B here
public function whatever()
{
$class_b = new B;
$class_b->show_caller($this);
}
}
class B
{
public function show_caller($class)
{
echo get_class($class);
}
}
We can't provide the knowledge about of where your method is executing to method's class without parameters. Late static binding will work only with inheritance, so it's not your case. The only approach, I can give you, is to use your IDE ability to find method usage in your project (ctrl+mouse1 in PhpStorm). If you're not using any IDE - it's a time to start.
Using PHP 5.3+ and having something equal to the following I get the output of 'C' instead of 'B':
class A
{
public static function doSomething()
{
echo get_called_class();
}
}
class B extends A
{
public static function doMore()
{
self::doSomething();
}
}
class C extends B {}
C::doMore();
If I had used static::doSomething() that would be the expected result, but when using self::doSomething() I expect this method to get called in the scope of B because it's where the 'self' is defined and not the late static binding.
How is that explained and how do I get 'B' in the doSomething() method?
Thanks in advance, JS
The issue here is late static binding. The get_called_class() function will use late static binding to return the class name, __CLASS__ will use late static binding if called using static::, but not when used with $this-> or self::. I don't know of a way to get it to return B short of having the echo within B instead of A. It sounds like this would be an ideal use of traits if you were using PHP 5.4.
Example:
class A
{
public static function doSomething()
{
echo __CLASS__;
}
}
class B extends A
{
public static function doMore()
{
self::doSomething();
}
}
class C extends B {}
C::doMore();
This returns A instead of C.
Override the method doSomething, to get B
class C extends B
{
public static function doMore()
{
B::doMore();
}
}
Tested
My Class is independant from another Class.
Inside my Class, a function is doing the same but refined job as a function in another Class. Can I use parent:: function_in_another_class() and get my function join that parent funciton's job flow?
No.
In PHP you can only extend from none or one class. As you write both classes are independent to each other, there is no information where to find the one or the other class.
But what you're looking for is probably this:
class A
{
function myFunction() {}
}
class B
{
private $a;
public function __construct(A $a)
{
$this->a = $a;
}
public function myFunction()
{
$this->a->myFunction();
}
}
If any class method already doing the same thing why would you bother call join it?
You can not do it. If you want the same job flow best way to do is to instantiate the other class and invoke that very same method. Thats why we use OOP.
See the example,
interface Fable()
{
public function f();
}
class OtherClass implements Fable
{
public function f()
{
// job flow
}
}
class MyClass
{
private $fable;
public function __construct(Fable $f)
{
$this->fable = $f;
}
public function method1($args){
return $this->fable->f($args);
}
}
If the current class is a child of another class, yes, you can. parent references to the parent class.
From php.net:
<?php
class A {
function example() {
echo "I am A::example() and provide basic functionality.<br />\n";
}
}
class B extends A {
function example() {
echo "I am B::example() and provide additional functionality.<br />\n";
parent::example();
}
}
$b = new B;
// This will call B::example(), which will in turn call A::example().
$b->example();
?>
The best you can do here is to extend Class B from Class A
Class B extends Class A
But, you can also:
class ClassA {
function do_something($args) {
// Do something
}
}
class ClassB {
function do_something_inclassA($args) {
classA::do_something($args);
}
}
Important: calling classa::do_something(); is a static call, in other words with error reporting E_STRICT you will get a static notice warning because function do_something() is not static function do_something()
Also, calling this function statically (i.e. classa::do_something()) means that class a's function cannot refer to $this within it
How do I call child function from parent static function ?
In php5.3 there is a built in method called get_called_class() to call child method from parent class. But my server is running with php 5.1.
Is there any way can do this ?
I want to call it from a static function . So that I can not use "$this"
So i should use "self" keyword.
Below example my parent class is "Test123" , from the parent class static function "myfunc" am trying to call child class function like this "self::test();"
abstract class Test123
{
function __construct()
{
// some code here
}
public static function myfunc()
{
self::test();
}
abstract function test();
}
class Test123456 extends Test123
{
function __construct()
{
parent::__construct();
}
function test()
{
echo "So you managed to call me !!";
}
}
$fish = new Test123456();
$fish->test();
$fish->myfunc();
Edit: What you try to achieve is not possible with PHP 5.1. There is no late static bindings PHP Manual in PHP 5.1, you need to explicitly name the child class to call the child function: Test123456::test(), self will be Test123 in a static function of the class Test123 (always) and the static keyword is not available to call a static function in PHP 5.1.
Related: new self vs new static; PHP 5.2 Equivalent to Late Static Binding (new static)?
If you are referring to a static parent function, then you need to explicitly name the parent (or child) for the function call in php 5.1:
parentClass::func();
Test123456::test();
In PHP 5.3 you can do this instead with the static keyword PHP Manual to resolve the called class' name:
static::func();
static::test();
If those are non-static, just use $this PHP Manual:
$this->parentFunc();
$this->childFunc();
Or if it has the same name, use parent PHP Manual:
parent::parentFunc();
(which is not exactly what you asked for, just putting it here for completeness).
Get_called_class() has been introduced for very specific cases like to late static bindings PHP Manual.
See Object Inheritance PHP Manual
I suspect you are a bit confused abuot parent / child, class / object and function / method.
Ionuț G. Stan has provided the explanation of how to invoke a method which is not declared in a parent class (which as he says should be abstract or implement the __call() method).
However if you mean how do invoke a method which has been overridden in a child class from the parent, then it is not possible - nor should it be. Consider:
Class shape {
...
}
Class circle extends shape {
function area() {
}
}
Class square extends shape {
function area() {
}
}
If it is your intent to call the area method on an instance of 'shape' (which does not have an area method) then which child should it use? Both the child methods would depend on properties which are not common / not implemented by the shape class.
try this:
<?php
class A {
public static function newInstance() {
$rv = new static();
return $rv;
}
public function __construct() { echo " A::__construct\n"; }
}
class B extends A {
public function __construct() { echo " B::__construct\n"; }
}
class C extends B {
public function __construct() { echo " C::__construct\n"; }
}
?>