How to inject a repository into a service in Symfony? - php

Question

I need to inject two objects into ImageService. One of them is an instance of Repository/ImageRepository, which I get like this:
$image_repository = $container->get('doctrine.odm.mongodb')
->getRepository('MycompanyMainBundle:Image');
So how do I declare that in my services.yml? Here is the service:
namespace Mycompany\MainBundle\Service\Image;
use Doctrine\ODM\MongoDB\DocumentRepository;
class ImageManager {
private $manipulator;
private $repository;
public function __construct(ImageManipulatorInterface $manipulator, DocumentRepository $repository) {
$this->manipulator = $manipulator;
$this->repository = $repository;
}
public function findAll() {
return $this->repository->findAll();
}
public function createThumbnail(ImageInterface $image) {
return $this->manipulator->resize($image->source(), 300, 200);
}
}

Answer 1

Here is a cleaned up solution for those coming from Google like me:
Update: here is the Symfony 2.6 (and up) solution:
services:
myrepository:
class: Doctrine\ORM\EntityRepository
factory: ["#doctrine.orm.entity_manager", getRepository]
arguments:
- MyBundle\Entity\MyClass
myservice:
class: MyBundle\Service\MyService
arguments:
- "#myrepository"
Deprecated solution (Symfony 2.5 and less):
services:
myrepository:
class: Doctrine\ORM\EntityRepository
factory_service: doctrine.orm.entity_manager
factory_method: getRepository
arguments:
- MyBundle\Entity\MyClass
myservice:
class: MyBundle\Service\MyService
arguments:
- "#myrepository"

Answer 2

I found this link and this worked for me:
parameters:
image_repository.class: Mycompany\MainBundle\Repository\ImageRepository
image_repository.factory_argument: 'MycompanyMainBundle:Image'
image_manager.class: Mycompany\MainBundle\Service\Image\ImageManager
image_manipulator.class: Mycompany\MainBundle\Service\Image\ImageManipulator
services:
image_manager:
class: %image_manager.class%
arguments:
- #image_manipulator
- #image_repository
image_repository:
class: %image_repository.class%
factory_service: doctrine.odm.mongodb
factory_method: getRepository
arguments:
- %image_repository.factory_argument%
image_manipulator:
class: %image_manipulator.class%

Answer 3

In case if do not want to define each repository as a service, starting from version 2.4 you can do following, (default is a name of the entity manager):
#=service('doctrine.orm.default_entity_manager').getRepository('MycompanyMainBundle:Image')

Answer 4

Symfony 3.3, 4 and 5 makes this much simpler.
Check my post How to use Repository with Doctrine as Service in Symfony for more general description.
To your code, all you need to do is use composition over inheritance - one of SOLID patterns.
1. Create own repository without direct dependency on Doctrine
<?php
namespace MycompanyMainBundle\Repository;
use Doctrine\ORM\EntityManagerInterface;
use MycompanyMainBundle\Entity\Image;
class ImageRepository
{
private $repository;
public function __construct(EntityManagerInterface $entityManager)
{
$this->repository = $entityManager->getRepository(Image::class);
}
// add desired methods here
public function findAll()
{
return $this->repository->findAll();
}
}
2. Add config registration with PSR-4 based autoregistration
# app/config/services.yml
services:
_defaults:
autowire: true
MycompanyMainBundle\:
resource: ../../src/MycompanyMainBundle
3. Now you can add any dependency anywhere via constructor injection
use MycompanyMainBundle\Repository\ImageRepository;
class ImageService
{
public function __construct(ImageRepository $imageRepository)
{
$this->imageRepository = $imageRepository;
}
}

Answer 5

In my case bases upon #Tomáš Votruba answer and this question I propose the following approaches:
Adapter Approach
Without Inheritance
Create a generic Adapter Class:
namespace AppBundle\Services;
use Doctrine\ORM\EntityManagerInterface;
class RepositoryServiceAdapter
{
private $repository=null;
/**
* #param EntityManagerInterface the Doctrine entity Manager
* #param String $entityName The name of the entity that we will retrieve the repository
*/
public function __construct(EntityManagerInterface $entityManager,$entityName)
{
$this->repository=$entityManager->getRepository($entityName)
}
public function __call($name,$arguments)
{
if(empty($arrguments)){ //No arguments has been passed
$this->repository->$name();
} else {
//#todo: figure out how to pass the parameters
$this->repository->$name(...$argument);
}
}
}
Then foreach entity Define a service, for examplein my case to define a (I use php to define symfony services):
$container->register('ellakcy.db.contact_email',AppBundle\Services\Adapters\RepositoryServiceAdapter::class)
->serArguments([new Reference('doctrine'),AppBundle\Entity\ContactEmail::class]);
With Inheritance
Same step 1 mentioned above
Extend the RepositoryServiceAdapter class for example:
namespace AppBundle\Service\Adapters;
use Doctrine\ORM\EntityManagerInterface;
use AppBundle\Entity\ContactEmail;
class ContactEmailRepositoryServiceAdapter extends RepositoryServiceAdapter
{
public function __construct(EntityManagerInterface $entityManager)
{
parent::__construct($entityManager,ContactEmail::class);
}
}
Register service:
$container->register('ellakcy.db.contact_email',AppBundle\Services\Adapters\RepositoryServiceAdapter::class)
->serArguments([new Reference('doctrine')]);
Either the case you have a good testable way to function tests your database beavior also it aids you on mocking in case you want to unit test your service without the need to worry too much on how to do that. For example, let us suppose we have the following service:
//Namespace definitions etc etc
class MyDummyService
{
public function __construct(RepositoryServiceAdapter $adapter)
{
//Do stuff
}
}
And the RepositoryServiceAdapter adapts the following repository:
//Namespace definitions etc etc
class SomeRepository extends \Doctrine\ORM\EntityRepository
{
public function search($params)
{
//Search Logic
}
}
Testing
So you can easily mock/hardcode/emulate the behavior of the method search defined in SomeRepository by mocking aither the RepositoryServiceAdapter in non-inheritance approach or the ContactEmailRepositoryServiceAdapter in the inheritance one.
The Factory Approach
Alternatively you can define the following factory:
namespace AppBundle\ServiceFactories;
use Doctrine\ORM\EntityManagerInterface;
class RepositoryFactory
{
/**
* #param EntityManagerInterface $entityManager The doctrine entity Manager
* #param String $entityName The name of the entity
* #return Class
*/
public static function repositoryAsAService(EntityManagerInterface $entityManager,$entityName)
{
return $entityManager->getRepository($entityName);
}
}
And then Switch to php service annotation by doing the following:
Place this into a file ./app/config/services.php (for symfony v3.4, . is assumed your ptoject's root)
use Symfony\Component\DependencyInjection\Definition;
use Symfony\Component\DependencyInjection\Reference;
$definition = new Definition();
$definition->setAutowired(true)->setAutoconfigured(true)->setPublic(false);
// $this is a reference to the current loader
$this->registerClasses($definition, 'AppBundle\\', '../../src/AppBundle/*', '../../src/AppBundle/{Entity,Repository,Tests,Interfaces,Services/Adapters/RepositoryServiceAdapter.php}');
$definition->addTag('controller.service_arguments');
$this->registerClasses($definition, 'AppBundle\\Controller\\', '../../src/AppBundle/Controller/*');
And cange the ./app/config/config.yml (. is assumed your ptoject's root)
imports:
- { resource: parameters.yml }
- { resource: security.yml }
#Replace services.yml to services.php
- { resource: services.php }
#Other Configuration
Then you can clace the service as follows (used from my example where I used a Dummy entity named Item):
$container->register(ItemRepository::class,ItemRepository::class)
->setFactory([new Reference(RepositoryFactory::class),'repositoryAsAService'])
->setArguments(['$entityManager'=>new Reference('doctrine.orm.entity_manager'),'$entityName'=>Item::class]);
Also as a generic tip, switching to php service annotation allows you to do trouble-free more advanced service configuration thin one above. For code snippets use a special repository I made using the factory method.

Answer 6

For Symfony 5 it is really simple, without need of services.yml to inject the dependency:
inject the Entity Manager in the service constructor
private $em;
public function __construct(EntityManagerInterface $em)
{
$this->em = $em;
}
Then get the repository :
$this->em->getRepository(ClassName::class)
by replacing ClassName with your entity name.