I am trying to do an include(dirname(FILE), '/../file.php?variable=VAR'), but it is unable to find the location when I use the variable.
The directory is located one above the current one where the file is. Is it possible to pass the variables through the include?
You can't, though you won't need this at all, because $_GET's scope is global [i.e. accessible from every script you run].
Just to be clear:
include($path) searches the filesystem for a resource, then processes it.
http://somesite.com/index.php?key=value is a URL, whose part after the ? sign is called query.
No.
By using include, you include the source code from the file as it is. I guess you want to define a function inside the included file and call it to get the result.
Related
So basically I have a file, lets say file1.php and it includes another file2.php.
file1.php contains a variable called $dateString that I have performed some operations on.
file2.php also has the same variable called $dateString however this variable is not being referenced within this include file even though $dateString was initialized prior to including file2.php.
So this is currently how file1.php looks like:
$dateString = 'some expression';
include 'file2.php';
file2.php is basically trying to echo out the variable that was initialized in file1.php
echo $dateString;
Everything else from file2.php is being called properly except that one variable.
Hopefully this makes sense. Is this possible in PHP? I have read in other places that you need to make the variables global and others have mentioned how you cant reference a variable from a parent file within a child file..any thoughts? Thanks in advance!
there is nothing magically happening when you use PHP's include(). the included file's code is basically just inserted at the point where you are including it - resulting in one bigger PHP file.
it doesn't really matter if the "parent" or in the "child" file - it's the position that matters since PHP will parse the single resulting file from top to bottom.
for example: if you set the variable in file A before including file B, file B will know about the variable. but if you set the variable in file A after including file B - file B doesn't know it.
With coding you should always try and test your own things before asking other people, butch like what #bub suggested in the comments.
Variables are global pretty much, you are able to include another file and use variables that are in file1.php in file2.php.
Otherwise, if you are using them in a function, I'd suggest using:
global $var;
the above should only be used in a function.
In my php code there is a section which needs to be retrieved from another php file.
I tried accomplishing this by:
include "teams.php?id=".$matchid;
and in the teams.php
$matchid = $_GET['id'];
echo "MATCH ID IS ".$matchid;
The problem is when i open teams.php?id=".$matchid directly it displays the match id fine
however the include doesn't work - i checked the source code of the original page - no code is being inserted. Is there a way to do what i want? I need to get php code from another file whilst passing 2 variables onto that file
Problem
The problem is related to what $_GET really contains:
An associative array of variables passed to the current script via the URL parameters. (...)
And you do not pass $matchid to the script through URL... And you should not in this case.
Solution
But there is a way. PHP does not separate global variables among files, so variables available in one file are available also in the one included:
in file no. 1:
// Assume $matchid is defined
include "teams.php";
in file no. 2 (the one included):
// No need to redefine $matchid - it was defined in the first file
echo "MATCH ID IS ".$matchid;
Also make sure you add <?php at the beginning of the file (the closing tag is not required). Otherwise it will be treated as text and not executed.
The problem is that you aren't loading that page in the browser when you call the include function, so the variable you are appending is not being processed as a URL query param. You are really just taking everything inside teams.php and dumping it into the other file (the one including teams.php) at that position.
If you want to effectively pass something into teams.php then just declare a variable before the include.
Check out http://php.net/manual/en/function.include.php and all will become clear.
That's not how include's work. When you include a file, it's code is executed as if it was written in the same file it's being included in. So teams.php will have the variable $matchid when the including file has that variable, no need to pass it in. Also the way you called the include was incorrect. Doing what you did causes php to look for a file in the current directory called 'teams.php?id=0' (replace 0 with the $matchid value). This file does not exist, 'teams.php' exists, not the URI. It is possible to specify a url by prefixing it with 'http://' however the result would work with the code in teams.php as it would expect to be able to read the php source.
You can do like this include "include "teams.php?id={$matchid}"; and
$matchid = filter_input(INPUT_GET, 'id', FILTER_SANITIZE_STRING);
echo "MATCH ID IS {$matchid}";
If You will use this code, you will be safe from Injects too!
I hope you will apreciate this.
When I include a page using it's full URL (like include 'http://mysite.tld/mypage.php'), I can't use the $GLOBALS in mypage.php, it returns Undefined index error.
But when I include it using it's relative path (like include 'mypage.php'), then it's OK.
The reason why am I using URL instead of relative path is that I want to include $_GET parameters to mypage.php
Is there any logical explanation of this strange behaviour?
Note that both files are on the same server, in the same directory.
Including files with a URL means the code is run as a separate process, which means it runs under a different variable scope. This is as opposed to if you include the file via a relative path, in which case it is pretty much equivalent to cut and pasting the code into the script.
Essentially this means that the only variables available from your starting script are those that you explicitly pass (as you are in this case using the $_GET variables). This includes the $_SESSION variables, since the caller is your own server rather than the client.
This behaviour is noted in the PHP manual's include page:
If the target server interprets the target file as PHP code, variables
may be passed to the included file using a URL request string as used
with HTTP GET. This is not strictly speaking the same thing as
including the file and having it inherit the parent file's variable
scope; the script is actually being run on the remote server and the
result is then being included into the local script.
Hey guys, Im building a fairly large website here, I am using quite a bit of php along with it, but what I was wondering, I have a header that does't change throughout the website, and I was wondering if I could create a function in some of my php code where all I would have to do is call like a function getHeader() and it will return the header. Now this header has some php in it also like a search bar and a username container... I was just wondering if this was possible on a fairly simple scale so I don't have to place the header code in each php file. which is fine but if I happen to make an update I have to update file which could take some time...
Thanks in advance!
Just create a header file (e.g. header.php) and include it.
http://php.net/manual/en/function.include.php
You can either have the code directly in the header.php not in any functions, and it will run by default, or put it in a function and call it manually.
A simple include() at the top of every file is what you'll need http://php.net/manual/en/function.include.php
You could use a function. That's what WordPress does. You could even put PHP inside them. You'd just have to keep in mind that the PHP inside your function is... well... inside a function. So you'd have to explicitly access global variables, etc.
Another option would be to put the header in its own, single file and just include that file, instead of calling a function. Whatever floats your boat.
On one of my pages I have a require_once('../path/to/url/page.php'); which works with no problems. The moment I add a query string require_once('../path/to/url/page.php?var=test'); it won't include the file anymore. It's just blank. Anyone have any ideas of why? Can you not use a query-string in a require?
Thanks,
Ryan
By using require_once('../path/to/url/page.php?var=test');, php will not make a new request to page.php, it will actually search for the file named page.php?var=test and include it, because in unix, you are allowed to have such a filename. If you want to pass a variable to that script, just define it: $var="test" and it will be available for use in that script.
require loads a File (from a file path) to include. It does not request that file through apache (or other webserver), therefore you cannot pass query strings in this way.
If you need to pass data into the file, you can simply define a standard php variable.
Example
<?php $a_variable = "data"; require_once('../path/to/url/page.php'); ?>
Note, the variable must be set before the include/require is called, otherwise it won't be available.
All answes true. But most importantly: since $_GET is a global, it's present' in all included files as well, so there's absolutely no use in passing those parameters with the include.
require only accepts paths it would be pointless to add any request since it doesn't make any
it simple includes the required code into the current one