Using mysql_fetch_array in INSERT statement - php

Question

I am trying to use the result of one mysql query in another mysql query, but I'm obviously doing something wrong. This is what I have:
<?php
$result = mysql_query('SELECT panel_product_no
FROM panelProduct
WHERE length_mm = "' . ($_POST["p_length_mm"]) . '"
AND width_mm = "' . ($_POST["p_width_mm"]) . '"
AND veneer_type = "' . ($_POST["p_veneer"]) . '"
AND lipping = "' . ($_POST["p_lipping"]) . '"');
$panel = mysql_fetch_array($result);
?>
And then I want to use that in this bit:
<?php
if(!empty($_POST[p_length_mm]) && !empty($_POST[p_width_mm]) && !empty($_POST[p_aperture]))
{
$sql3="INSERT INTO estimateDescribesPanelProduct (estimate_no, panel_product_no, quantity)
VALUES ('$_GET[estimate_no]','$panel','$_POST[p_quantity]')";
if (!mysql_query($sql3,$con))
{
die('Error: ' . mysql_error());
}
}
?>
The query is basically working in that it is inserting the posted estimate_no and quantity into the DB, but not the correct panel_product_no (it just inserts '0'). How can I get it to insert the $result value?
P.S. I know that I should not be using mysql functions and I will not be in future, however I am so nearly finished with this project that at this point I am not in a position change.

Answer 1

Your are basicly copying content from one table to another.
Wy not use the MySQL INSERT .. SELECT syntax?

Answer 2

as #Dmitry Makovetskiyd wrote, mysql_fetch_array() returns a resource, not manipulatable results.
For example:
$result = mysql_query('SELECT panel_product_no
FROM panelProduct
WHERE length_mm = "' . ($_POST["p_length_mm"]) . '"
AND width_mm = "' . ($_POST["p_width_mm"]) . '"
AND veneer_type = "' . ($_POST["p_veneer"]) . '"
AND lipping = "' . ($_POST["p_lipping"]) . '"');
$resource = mysql_fetch_object($result);
You need to add in:
$panel = $resource->'panel_product_no';
You can then continue with your second query.
Note the change from mysql_fetch_array() to mysql_fetch_object() - as your query suggests you are only retrieving a singular value from the table (assuming there is only a singular panel with the specified length, width, veneer type and lipping), the object method will work fine.