I have multiple forms on a single page and all gets redirected to same page when form is submitted but the previously submitted form values disappears when new form is submitted.
I tried using sessions didn't worked for me what else? please help
<script language="javascript">
function row(x,y){
//var len=document.forms[x].name.value;
if(x.value.length >=3)
{
//alert("Message form no> "+y+"will be submited");
document.forms[y].submit();
}
}
</script>
</head>
<body >
<center>
<h2>Database App</h2>
<table>
<tr>
<th><lable>Name :</label></th>
<th><label>E_Id :</label></th>
<th><label>Email :</label></th>
<th><label>Other Info :</label></th></tr>
<tr>
<?php
error_reporting(E_ALL ^ E_NOTICE);
// code check for name in database and if exists,displays in table row
//for($i=0;$i<150;$i++)
//{
//$E_id=array();
if($_POST){
$i = $_GET["uid"];
//echo "fhwefwej==".$i;
$x='name'.$i;
// echo 'dasvds'.$x;
if($_POST[$x])
{
$name = strtolower($_POST[$x]);
$E_id[$i] = "";
$Email[$i] = "";
$Otherinfo[$i] = "";
$con = mysql_connect('localhost','root','') or die("npt");
$db = mysql_select_db("trainee")or die("nptdff");
$query = "Select * from reguser where fname like '".$_POST[$x]."%'";
$result = mysql_query($query);
mysql_num_rows($result);
if(mysql_num_rows($result)>0)
{
while($row=mysql_fetch_array($result))
{
$str=$row['fname'];
$initials = strtolower(substr($str,0,3));
if($name == $initials)
{
//echo "exist"."<br>";
$E_id[$i]= $row['fname'];
$Email[$i]=$row['lastname'];
$Otherinfo[$i]=$row['address'];
break;
}
}
}
else
{
$msg[$i] = "no user with these initials";
}
mysql_close($con);
}
}
for($i=0;$i<150;$i++)
{
//session_start();
//echo session_name($i)."<br>";
echo "<form name='form$i' action='new2.php?uid=$i' method='post'>";
echo "<td><input type='text' name='name$i' id='name$i' onkeyup='row(this,$i);' /><br />";
echo "<span id='availability_status' >";
if($_POST[$x]){echo $msg[$i];}
echo "</span> </td>";
echo "<td><input type='text' name='E_id' id='E_id' value='";
if(isset($_POST[$x])){ echo $E_id[$i];}
echo "' disabled='disabled' />";
echo "</td>";
echo "<td><input type='text' name='email' id='email' value='$Email[$i]' disabled='disabled' />";
echo "</td>";
echo "<td><input type='text' name='otherinfo' id='otherinfo' value='$Otherinfo[$i]' disabled='disabled' />";
echo "</td></tr>";
echo " </form>";
}
//echo '<script language="javascript">document.getElementById(\'name0\').focus();</script>';
?>
</table>
</center>
</body>
</html>
Why don't you Use AJAX. It will help to keep you posed different form information in back-end
you can either store those information in database or in file.
It will be the best way.
Related
I am using 2 pages. Page 1, the user enters name and age. I have given form action as the same page and user selects either one or both occupation and the data gets pushed to page 2 which displays all the results. Below is the code for the same:
Page1:
<?php
echo "<form action=\"page1.php\" method=\"post\">";
echo "<h2>Your Name. *</h2><input type='text' name='user_name'>";
echo "<br><br>";
echo "<h2>Your Age. *</h2><input type='text' name='age'>";
echo "<br><br>";
echo "<div><input type='submit' value='Review'></div>";
?>
<?php
if((empty($_POST['user_name'])) || (empty($_POST['age'])) ) {
echo "<h2>Please enter your user name and age</h2>";
} else {
$user_name = $_POST['user_name'];
$age = $_POST['age'];
echo "<h2>Below are the details entered:</h2><br>";
echo "<h2>Name: </h2>$user_name";
echo "<h2>Age: </h2>$age";
echo "<form action=\"page2.php\" method=\"post\">";
echo '<td bgcolor="#EAEAEA" style="color:#003399"><input type="checkbox"
name="occupation[]" value="QA">QA</td>';
echo '<td bgcolor="#EAEAEA" style="color:#003399"><input type="checkbox"
name="occupation[]" value="Tester">Tester</td>';
echo "<br>";
echo "<input type=\"submit\" value='Add to DB' >";
echo "</form>";
}
?>
Page2:
<?php
$user_name = $_GET['user_name'];
$age = $_GET['junos_version'];
$occupation = $_GET['occupation'];
echo "<h2>Below are the details entered:</h2><br>";
echo "<h2>Name: </h2>$user_name";
echo "<h2>Age: </h2>$age";
echo "<h2>Occupation selected: </h2>";
for ($i=0;$i<sizeof($occupation);$i++) {
echo " $occupation[$i] ";
}
?>
Please help!!!
Put all of that fields in just one form and validate the action or put validation into php before frontend start, I prefer the first one to your case, it's easier:
FILTERING IN THE ACTION
<?php
if (empty($_POST['user_name'])){
$action = 'page1.php';
$structure = "<h2>Please enter your user name and age</h2>";
$submit = 'Review';
} else {
$action = 'page2.php';
$phrase = '';
$user_name = $_POST['user_name'];
$age = $_POST['age'];
$structure = '<h2>Below are the details entered:</h2><br>
<h2>Name: </h2>$user_name
<h2>Age: </h2>$age
<td bgcolor="#EAEAEA" style="color:#003399"><input type="checkbox" name="occupation[]" value="QA">QA</td>
<td bgcolor="#EAEAEA" style="color:#003399"><input type="checkbox" name="occupation[]" value="Tester">Tester</td>';
echo "<br>";
$submit = 'Add to DB';
}
echo "<form action='{$action}' method=\"post\">";
echo "<h2>Your Name. *</h2><input type='text' name='user_name'>";
echo "<br><br>";
echo "<h2>Your Age. *</h2><input type='text' name='age'>";
echo "<br><br>";
echo $structure;
echo "<div><input type='submit' value='{$submit}'></div>";
echo "</form>";
?>
PS: Avoid all those echoes, put just plain html and use php where it needed, it's better. TD's outside tables are utterly wrong, remove then, use divs instead and organize them with CSS.
I tried to retype a code of my groupmate, because the 'textarea' in here is going to be bombarded by a whole lot of string and the problem is that the request URI is too long. So I tried to change of all the $_GET to $_POST, because it won't be posted in the URL.
But the problem is that it won't display the input 'text' and 'textarea' in the isset. I don't know whether it's the isset that is the problem or the or the $_POST, but when I return it back to $_GET it works.
PHP Code for displaying the chapters to be updated and the update function.
<?php
if (isset($_POST['submit'])) {
$id = $_POST['cid'];
$title = $_POST['ctitle'];
$body = $_POST['cbody'];
$result = $db->query("UPDATE chapter set chapter_title='$title', chapter_body='$body' where chapter_id='$id'");
}
$result = $db->query("select * from chapter");
while($row = mysqli_fetch_assoc($result)) {
$update = 'chapterid';
echo "<li id='button' class='btn' ><b id='shadow'><a href='chapter1.php?update={$row['chapter_id']}'>{$row['chapter_title']}</b></a></li></button>";
}
?>
PHP code for displaying the input 'text' and 'textarea'.
<?php
if (isset($_POST['update'])) {
$update = $_POST['update'];
$result1 = $db->query("select * from chapter where chapter_id=$update");
while($row1 = mysqli_fetch_assoc($result1)) {
echo "<center>";
echo "<form class='form' method='POST'>";
echo "<h2>Update Form</h2>";
echo "<hr/>";
echo"<input class='input' type='hidden' name='cid' value='{$row1['chapter_id']}'/>";
echo "<br />";
echo "<label>" . "Chapter Title:" . "</label>" . "<br />";
echo"<input class='input' type='text' name='ctitle' value='{$row1['chapter_title']}' />";
echo "<br />";
echo "<label>" . "Chapter Body:" . "</label>" . "<br />";
echo "<textarea rows='15' cols='95' name='cbody'>{$row1['chapter_body']}";
echo "</textarea>";
echo "<br />";
echo "<input class='submit' type='submit' name='submit' value='update' />";
echo "</form>";
echo "</center>";
}
}
if (isset($_POST['submit'])) {
echo '<div class="form" id="form3"><br><br><br><br><br><br>
<Span>Data Updated Successfuly......!!</span></div>';
}
?>
<div class="clear"></div>
</div>
<div class="clear"></div>
</div>
</div><?php
mysqli_close($db);
?>
if (isset($_POST['update'])) {
This line should stay $_GET['update'], because "update" is not part of you form, but part of the url:
<a href='chapter1.php?update={$row['chapter_id']}'
I currently have these PHP pages which lets me add a record to a database. (in this case its members) It works perfectly in the sense that I can ADD, DELETE and VIEW. But Im not sure how to get the edit(or UPDATE functionality working.
Here is my db connection Code:
<?php
// Server Info
$server = 'localhost';
$username = 'root';
$password = '';
$database = 'gamgam';
// Connect to database
$connection = new mysqli($server, $username, $password, $database);
?>
Here is my Add Code:
<!DOCTYPE html>
<html>
<head><title>Insert Users</title></head>
<body>
<h2>Insert User Confirmation</h2>
<form action="<?php $_SERVER['PHP_SELF']?>" method="post"/> <br>
<?php
require_once('connection.php');
echo "<label for='memberID' >Member ID:</label>";
echo "<input type='text' name='memberID' id='memberID' />";
echo "<br /><br />";
echo "<label for='username' >Username:</label>";
echo "<input type='text' name='username' id='username' />";
echo "<br /><br />";
echo "<label for='password' >Password:</label>";
echo "<input type='password' name='password' id='password' />";
echo "<br /><br />";
echo "<label for='fName' >Firstname:</label>";
echo "<input type='text' name='fName' id='fName' />";
echo "<br /><br />";
echo "<label for='lName' >Lastname:</label>";
echo "<input type='text' name='lName' id='lName' />";
echo "<br /><br />";
echo "<label for='address' >Address:</label>";
echo "<input type='text' name='address' id='address' />";
echo "<br /><br />";
echo "<label for='email' >Email:</label>";
echo "<input type='text' name='email' id='email' />";
echo "<br /><br />";
echo "<input type='submit' name='submit' value='Submit' />";
echo "<input type='reset' value='Clear' />";
echo "<br /><br />";
?>
</form>
</section>
<p><a href='login.php'>Login</a></p>
<?php
if(!isset($_POST['submit'])) {
echo 'Please Register';
} else {
$memberID = $_POST['memberID'];
$username = $_POST['username'];
$password = $_POST['password'];
$fName = $_POST['fName'];
$lName = $_POST['lName'];
$address = $_POST['address'];
$email = $_POST['email'];
$query = "INSERT INTO `members`
(MemberID, Username, Password, FirstName, LastName,
StreetAddress, Email)
VALUES ('$memberID', '$username', '$password', '$fName',
'$lName', '$address', '$email')";
mysqli_query($connection, $query)
or die(mysqli_error($connection));
$rc = mysqli_affected_rows($connection);
if ($rc==1)
{
echo '<h4>The database has been updated with the following details: </h4> ';
echo 'MemberID: '.$memberID.'<br />';
echo 'Username: '.$username.'<br />';
echo 'Password: '.$password.'<br />';
echo 'First Name: '.$fName.'<br />';
echo 'Last Name: '.$lName.'<br />';
echo 'Address: '.$address.'<br />';
echo 'Email: '.$email.'<br />';
} else {
echo '<p>The data was not entered into the database this time.</p>';
}
}
?>
</body>
</html>
Here is my View Code:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<html>
<head>
<title>View Records</title>
</head>
<body>
<table border="1" style="width:100%" >
<?php
/*
VIEW.PHP
Displays all data from 'players' table
*/
// connect to the database
include('connection.php');
// get results from database
$result = mysqli_query($connection, "SELECT * FROM members")
or die(mysqli_error());
// loop through results of database query, displaying them in the table
while($row = mysqli_fetch_array( $result )) {
// echo out the contents of each row into a table
echo "<tr>";
echo '<td>' . $row['MemberID'] . '</td>';
echo '<td>' . $row['Username'] . '</td>';
echo '<td>' . $row['Password'] . '</td>';
echo '<td>' . $row['FirstName'] . '</td>';
echo '<td>' . $row['StreetAddress'] . '</td>';
echo '<td>' . $row['Email'] . '</td>';
echo '<td>Edit</td>';
echo '<td>Delete</td>';
echo "</tr>";
}
// close table>
echo "</table>";
?>
<p>Add a new record</p>
</body>
</html>
And here is the Delete Code:
<?php
// Connect to the database
include('connection.php');
// Confirm that the 'code' variable has been set
if (isset($_GET['MemberID']))
{
// Get the 'MemberID' variable from the URL
$MemberID = $_GET['MemberID'];
// Delete record from database
if ($stmt = $connection->prepare("DELETE FROM members WHERE MemberID = ? LIMIT 1")) {
$stmt->bind_param("i",$MemberID);
$stmt->execute();
$stmt->close();
} else {
echo "ERROR: could not prepare SQL statement.";
}
$connection->close();
// Redirect user after delete is successful
header("Location: view.php");
} else {
// If the 'code' variable isn't set, redirect the user
header("Location: view.php");
}
?>
I have gone through many basic php form templates online trying to incorporate what they have done to achieve results but have not had any success. What code needs to be written for my website to have the functionality to edit records already created in the database without going through phpmyadmin. Any help is apreciated.
Edit will be just just like Add, but you need to read the record first and populate the field values.
Start with the code from add and do something like:
<?php $MemberID = (int) $_GET['MemberID']; ?>
<form action="<?php $_SERVER['PHP_SELF']?>" method="post"/> <br>
<input type="hidden" name="MemberID" value="<?php echo $MemberID; ?>"
<?php
require_once('connection.php');
$result = mysqli_query($connection, "SELECT * FROM members where MemberID = $MemberID") or die(mysqli_error());
// loop through results of database query, displaying them in the table
$row = mysqli_fetch_assoc($result);
extract($row);
echo "<label for='memberID' >Member ID:</label>";
echo "$memberID"; // member ID should not be editable
echo "<br /><br />";
echo "<label for='username' >Username:</label>";
echo "<input type='text' name='username' id='username' value="$username" />";
echo "<br /><br />";
The PHP code will have a query like
`UPDATE `members` SET `username` = '$username' ... WHERE `MemberID` = '$MemberID'"
I am required to create a drop down box which gathers the records from a database to populate the drop down. When one of the values is selected, a form is to be displayed which contains the data relating to the value selected.
The form is to have the function of showing the selected data, but also to update the record in the database when filled out and Submit.
I have created a php file to try and accomplish this, but Im getting errors such as undefined index and unknown column.
I am only new to PHP so this is a big task for me. Could someone have a look at my code and inform me if there are any errors.
Ive been trying to piece code together here and there from the net but its been tricky trying to get it all to work.
I am not getting any errors now after some tweaking, but the record wont update. I get a 'record updated successfully' message but the record isn't updated.
I am pretty sure the lack of a record update is coming down to the ID not getting collected properly via the $q=$row["BearId"] but if I use $q=$_GET["q"] I get nothing but errors. I am not completely positive this is the problem though, that is why Im asking the question here.
I would appreciate any help that you can give. Ive gotten so far with this thing and yet I cant get it to update the record.
EDIT: I have pinpointed the problem down to the id in
$sql = "UPDATE //snip WHERE BearId = '$q'";
$q=$row["BearId"];
If I manually change BearId to equal '1' then the record is updated.
updatebears.php
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Update Bears</title>
<script>
function showUser(str)
{
if (str=="")
{
document.getElementById("result").innerHTML="";
return;
}
if (window.XMLHttpRequest)
{
xmlhttp=new XMLHttpRequest();
}
else
{
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("result").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","getvalues.php?q="+str,true);
xmlhttp.send();
}
</script>
<style>
// style elements
</style>
</head>
<body>
<h1>Update Bears</h1>
Select a Bear:
<br />
<select name="bears" onchange="showUser(this.value)">
<option value="">Select a BearId</option>
<?php
$query = "SELECT * FROM bears";
$mysqli = new mysqli('localhost','User','123','bears');
$result = $mysqli->query($query);
while($row = $result->fetch_assoc())
echo '<option value="'.$row["BearId"].'">'.$row["BearId"].'</option>';
?>
</select>
<br />
<?php
$q=$row["BearId"];
$mysqli = new mysqli('localhost','User','123','bears');
$sql = "SELECT * FROM bears WHERE BearId='".$q."'";
if(array_key_exists('_submit_check', $_POST))
{
$weight = $_POST['Weight'];
$sex = $_POST['Sex'];
$type = $_POST['Type'];
$colour = $_POST['Colour'];
$breed = $_POST['BreedId'];
$sql = "UPDATE bears SET Weight = '$weight', Sex = '$sex', Type = '$type', Colour = '$colour', Breed = '$breed' WHERE BearId = '$q'";
if($mysqli->query($sql) === TRUE)
{
echo 'Record updated successfully<br />';
}
else
{
echo $sql.'<br />' . $mysqli->error;
}
$mysqli->close();
}
?>
<br />
<div id="result"></div>
<br />
Click here to Visit Task 2 (Insert Bears) | Click here to Visit Task 3 (Display Bears)
</body>
</html>
getvalues.php
<?php
$q=$_GET["q"];
$mysqli = new mysqli('localhost','User','123','bears');
$sql = "SELECT * FROM bears WHERE BearId='".$q."'";
if($stmt = $mysqli->prepare($sql))
{
$stmt->execute();
$stmt->bind_result($BearId, $Weight, $Sex, $Type, $Colour, $Breed);
while ($stmt->fetch())
{
echo "<form method='post' name='form1' onsubmit='return validateForm()' action='updatebears.php'>";
echo "<p>";
echo "<label for='BreedId'>BreedId:</label>";
echo "<br />";
echo "<select id='BreedId' name='BreedId' />";
echo "<option value='".$Breed."'>".$Breed."</option>";
echo "<option value='1'>1. Polar</option>";
echo "<option value='2'>2. Brown</option>";
echo "<option value='3'>3. Panda</option>";
echo "</select>";
echo "</p>";
echo "<p>";
echo "<label for='Weight'>Weight(kg):</label>";
echo "<br />";
echo "<input type='text' id='Weight' name='Weight' value='".$Weight."' />";
echo "</label>";
echo "</p>";
echo "<p>";
echo "Sex: ";
echo "<br />";
echo "<label for='M'>Male</label><input type='radio' id='M' value='M' name='Sex'";
if($Sex=='M') echo "checked";
echo "/>";
echo "<label for='F'>Female</label><input type='radio' id='F' value='F' name='Sex'";
if($Sex=='F') echo "checked";
echo "/>";
echo "</p>";
echo "<p>";
echo "<label for='Type'>Type:</label> ";
echo "<br />";
echo "<input type='text' id='Type' name='Type' maxlength='100' value='".$Type."' />";
echo "</p>";
echo "<p>";
echo "<label for='Colour'>Colour:</label>";
echo "<br />";
echo "<input type='text' id='Colour' name='Colour' maxlength='20' value='".$Colour."' />";
echo "</p>";
echo "<p>";
echo "<input type='submit' value='Submit' />";
echo "<input type='reset' value='Reset' />";
echo "<input type='hidden' name='_submit_check' value=1 />";
echo "</p>";
echo "</form>";
}
}
else
{
echo 'Unable to connect';
exit();
}
?>
Thanks for the help.
I believe what you need to do is create a hidden input type for the BearId within the getvalues.php file. That way when your form performs the post you can get the BearId from the post as opposed to trying to get it from the $row['BearId']. I'm fairly certain $row['BearId'] is not the same $row['BearId'] that the user selected when he first goes to the getvalues.php form. Have you tried printing $row['BearId'] to html to verify it's a legitimate value?
if(array_key_exists('_submit_check', $_POST))
{
$id = $_POST['BearId']
$weight = $_POST['Weight'];
$sex = $_POST['Sex'];
$type = $_POST['Type'];
$colour = $_POST['Colour'];
$breed = $_POST['BreedId'];
$sql = "UPDATE bears SET Weight = '$weight', Sex = '$sex', Type = '$type', Colour = '$colour', Breed = '$breed' WHERE BearId = '$id'";
if($mysqli->query($sql) === TRUE)
{
echo 'Record updated successfully<br />';
}
else
{
echo $sql.'<br />' . $mysqli->error;
}
$mysqli->close();
}
?>
<h1>getvalues.php</h1>
<?php
$q=$_GET["q"];
$mysqli = new mysqli('localhost','User','123','bears');
$sql = "SELECT * FROM bears WHERE BearId='".$q."'";
if($stmt = $mysqli->prepare($sql))
{
$stmt->execute();
$stmt->bind_result($BearId, $Weight, $Sex, $Type, $Colour, $Breed);
while ($stmt->fetch())
{
echo "<form method='post' name='form1' onsubmit='return validateForm()' action='updatebears.php'>";
echo <input type="hidden" name="BearId" value='".$q."'>
echo "<p>";
echo "<label for='BreedId'>BreedId:</label>";
echo "<br />";
echo "<select id='BreedId' name='BreedId' />";
echo "<option value='".$Breed."'>".$Breed."</option>";
echo "<option value='1'>1. Polar</option>";
echo "<option value='2'>2. Brown</option>";
echo "<option value='3'>3. Panda</option>";
echo "</select>";
echo "</p>";
echo "<p>";
echo "<label for='Weight'>Weight(kg):</label>";
echo "<br />";
echo "<input type='text' id='Weight' name='Weight' value='".$Weight."' />";
echo "</label>";
echo "</p>";
echo "<p>";
echo "Sex: ";
echo "<br />";
echo "<label for='M'>Male</label><input type='radio' id='M' value='M' name='Sex'";
if($Sex=='M') echo "checked";
echo "/>";
echo "<label for='F'>Female</label><input type='radio' id='F' value='F' name='Sex'";
if($Sex=='F') echo "checked";
echo "/>";
echo "</p>";
echo "<p>";
echo "<label for='Type'>Type:</label> ";
echo "<br />";
echo "<input type='text' id='Type' name='Type' maxlength='100' value='".$Type."' />";
echo "</p>";
echo "<p>";
echo "<label for='Colour'>Colour:</label>";
echo "<br />";
echo "<input type='text' id='Colour' name='Colour' maxlength='20' value='".$Colour."' />";
echo "</p>";
echo "<p>";
echo "<input type='submit' value='Submit' />";
echo "<input type='reset' value='Reset' />";
echo "<input type='hidden' name='_submit_check' value=1 />";
echo "</p>";
echo "</form>";
}
}
else
{
echo 'Unable to connect';
exit();
}
I currently have a guestbook style thing that users post comments. Their username is stored in a cookie when logged on, and when a post is submitted their username is stored alongside their post in a mySQL database. I'm trying to remove the delete button next to the comment if the user logged in is not the one that posted it. Here is the nonworking code:
<?php
$username = $_COOKIE['sqlusername'];
mysqlLogin();
$sql = mysql_query("SELECT * FROM `posts`");
$sqlCnt = mysql_num_rows($sql);
if($sqlCnt != 0) {
echo "<table align='center'><tr><td class='tdno'><u><H4>Message</H4></u></td><td class='tdno'><u><H4>Poster</H4></u></td><td class='tdno'><u><H4>Time</H4></u></td></tr>";
while($row = mysql_fetch_array($sql)) {
if($row['username'] != $username) {
echo "<script type=\"text/javascript\">";
echo "document.getElementById('delete').innerHTML = \"\";";
echo "</script>";
}
$id = $row['id'];
echo "<form action='delete.php' method='POST'>";
echo "<tr><td>";
echo $row['message'];
echo "</td><td>";
echo $row['poster'];
echo "</td><td align='center' width='10'>";
echo $row['date'];
echo "<td align='left' width='1'>";
echo "<input type='hidden' name='id' value='$id'>";
echo "<span id='delete'><input type='submit' class='submit' value='Delete'></span>";
echo "</td></tr>";
echo "</form>";
}
echo "</table>";
} else {
echo "<div align='center'>Sorry, no posts found!</div>";
}
?>
Any thoughts?
Try:
if ($username == $row['poster']) {
echo "<input type='hidden' name='id' value='$id'>";
echo "<span id='delete'><input type='submit' class='submit' value='Delete'></span>";
} else {
echo " "
}
maybe its the issue with your browser and javascript. Try this :
if (document.getElementById) { // DOM3 = IE5, NS6
document.getElementById(id).style.display = 'none';
}
else {
if{ // IE 4
document.all.id.style.display = 'none';
}
}
else your logic looks fine(assuming you are storing the username and posts properly in database.)