User Levels in SQL - php

Question

Okay, so I have created a user table inside of my database to hold all the users data
CREATE TABLE `user` (
`id` INT NOT NULL auto_increment,
`username` VARCHAR(50) NOT NULL default '',
`nicename` VARCHAR(255) NOT NULL default '',
`email` VARCHAR(255) NOT NULL default '',
`password` VARCHAR(255) NOT NULL default '',
`permissions` INT NOT NULL default '1',
UNIQUE KEY `user_n` (`username`),
UNIQUE KEY `user_e` (`email`),
PRIMARY KEY (`id`)
);
I want the permissions field to dictate what users can and cannot see. IE. The permissions for the ACP would require a permissions level of 3 whereas 1 is a registered user and 0 is a guest visiting the site. How could I get a page to block itself depending upon a users permission level? Thanks in advance.
Using MySQL/PHP

Answer 1

have the user login , fetch his permissions from table and depending upon the permission redirect him/her to appropriate page e.g.
 
$dbh = new PDO("mysql:dbname=dbname;host=hostname", "username", "password" );
$result = $dbh->prepare("select check_user_exists(?) as retval");
$result->bindParam(1, $value, PDO::PARAM_STR, 2);
$result->setFetchMode(PDO::FETCH_CLASS, 'stdClass');
$result->execute();
switch($result) {
case 1 : $header('Location:x.php');
case 2 : $header('Location:y.php');
case 3 : $header('Location:z.php');
default 'no suitable page found');
break;
}

Answer 2

If you don't want to use MySQL user-account-management You can use switch case
$permissions = $_GET["permissions"];//Or Post from html page
switch ($permissions)
{
case 1:
//Level 1 code
break;
case 2:
//level 2 code
break;
case 3:
//level 3 code
break;
default:
//default code
}