I have written a code and now i want to view the output of user selected radio button in the same php page?
How can i do it? Here is my code
<html>
<div>
<form>
<input type='submit' name='radiotest' value='1crn' /> </div>
<input type='submit' name='radiotest' value='1FFZ' /> </div>
</form>
</div>
<div>
<head>
<script src="jmol/Jmol.js"></script>
</head>
<script>
jmolInitialize("jmol");
</script>
<script>
jmolSetAppletColor("gray");
jmolApplet(450, "load <?php echo "/jmol/".$_REQUEST['radiotest'].".pdb"; ?>; select all; cartoon on; wireframe off; spacefill off; color chain; ");
</script>
</div>
</html>
Any suggestions?
This should not be done using PHP (javascript would be a better candidate), but to answer the question:
Make the form so it has an action and method attributes. Action will be the current page (you don't need to specify this attribute if it's the same page) and method will be GET or POST.
Something like this:
<form action="" method="GET">
Now, when you click the button, the form gets submitted and the page reloads but the URL is different:
http://site.com/page.php?radiotest=1crn
You can now check to see if the $_GET['radiotest'] is set using isset() function. If it is set, do whatever you want it to do.
isset($_GET['radiotest']) - tells you if radiotest=something is in the URL
$_GET['radiotest'] - gives you the value of "something" from radiotest=something in the URL.
Because PHP is a server-side language, all code gets executed on the server. By the time the page gets sent to the browser, it has already executed and no further computations can be made. If you must have a PHP solution, the request must be sent to the server, the page must reload.
This is the one of the way to display the output in the same page...
<html>
<head>
</head>
<body>
<form name='test' method='GET' action="">
<input type='radio' name='radiotest' value='1crn' />1crn
<input type='radio' name='radiotest' value='1FFZ' />1FFz
<input type='submit' value='submit' name='submit' />
</form>
<?php
if(isset($_GET("submit")))
{
echo $_GET["radiotest"];
}
?>
</body>
</html>
Related
I have been trying to create a form that reads a post from an HTML form and displays an element from that post IF it detects that the post exists.
However, each time the post is submitted, it simply reloads the form as though no post were provided.
<!DOCTYPE html>
<html>
<head>
<title>Upload from Manifest</title>
</head>
<body>
<?php
if (isset($_POST['manifest'])) {
echo 'we are in the IF';
echo($_POST['manifest']);
}
?>
<h1>Submission from manifest into main db</h1>
<div class="container offset-top120">
<form method="post" action="https://nhsggc.cogiva.com/prism/loadFromManifest.php" enctype="multipart/form-data">
<input id="manifest" type="text" />
<input id="submit" value="Submit" type = "submit" />
</form>
</div>
</body>
</html>
Your form is going to either a different page (https://nhsggc.cogiva.com/prism/loadFromManifest.php so check for that first) if you wanted it to go to same page, you can give the action as just '#', or put in the whole URL like you have.
You're missing the name attribute from your submit input and text input. Read up on the name attribute!
<input id="manifest" type="text" name="manifest">
<input id="submit" value="Submit" type="submit" name='submit' />
Then your PHP should look like this:
<?php
if (isset($_POST['submit'])) {
echo 'Inside an if';
echo $_POST['manifest'];
}
Then it should work.
I have a small problem. I want to have a button in my html page that saves every data that is added in the textfields and also when I click it to move to the next page.
My code is the follow...
<input type=button onClick="location.href='education.php'" value='Next'>
but it only moves to next page it does not save the data in the database ...
Can you help me please?
Thanks.
Remove the JavaScript
Change the type to submit
Wrap it in a <form>
Set the action of the form to education.php
Set the method of the form to post
Then, in education.php, read the data from $_POST and use PDO (with bound variables) to insert it into the database.
Try this :
<?php
if(isset($_POST['submit']))
{
// Insert Query Put here
header('Location: education.php');
}
?>
<html>
<head>
</head>
<body>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
<input type="submit" value="Next" name="submit">
</form>
</body>
</html>
education.php :
<?php
echo "Successfully Updated.";
?>
You will have to set an action to your form like below because you are not submitting the form, but just redirection to another page without taking the form data.
<form action="education.php" method="post">
<!-- All your input fields here -->
<input type="submit" name="submit" value="Next">
</form>
and your education.php should be look like this:
<?php
//Get all parameters using $_POST
//Make A connection to database
//Choose a database in which you have to save the data
//Create a SQL query
// run query using mysql_query($query);
//Redirect to anywhere with header("Location:page.php");
?>
I would like to update the value of the first user with the second user without reloading, using HTML and PHP.
user.html
<html>
<head>
</head>
<h1>color</h1>
<body>
<div id="txtHint">
<form name="myForm" action="color.php" method="get">
<tr><td>color<input type='text' name='color' id='clr/></td></tr>
<tr><td><input type='submit' id='submit' name='submit' onclick=''/></td></tr>
</form>
</div>
</body>
</html>
color.php
<?php
$color=$_GET['color'];
?>
For example, user types "red" and therefore displays "red" in the PHP page:
user2.html
<html>
<head>
</head>
<h1>color</h1>
<body>
<div id="txtHint">
<form name="myForm" action="color.php" method="get">
<tr><td>color<input type='text' name='color' id='clr'/></td></tr>
<tr><td><input type='submit' id='submit' name='submit' onclick=''/></td></tr>
</form>
</div>
</body>
</html>
I want the output such that once user 2 types any color, the color of user 1 also gets changed to the user2 color. How can I do that?
You will need ajax to do this.
Only echo in php page can do nothing. You need to save the color to a database.
In the user.html page you should check periodically for changes in the database. And in the user2.html page you need to update the database using ajax or do a normal post or get method.
It is very difficult for me to put in words my query. But I will try.
I have a site xyz.com which has search facility for listed products. The search page url is generated like this :www.wyz.com/search/search_term
I want to create a iframe page in a third party site with a search facility which can directly communicated with my site xyz.com.
I have tried to create a search box with a submit button. I want to append the search query in as a variable to my form action url string.
So the search string should look like this :www.wyz.com/search/my_string_variable
The code I have written is:
<?php
$url='http://www.xyz.com/search/';
?>
<?php
if (isset($_POST['submit']))
{
$r1=$_POST['num1'];
}
?>
<?php
$result=$url.$r1
?>
<html><body>
<form action="<?php echo $result; ?>" method="post">
Num1:<input name="num1"><br>
<input type="submit" name="submit">
</form>
</body></html>
==================================================================
But output what I get, is only "http://www.xyz.com/search/". It removes my variable from the url. I am not able to find what is the reason? I have also tried to print result via to check the actual output and it shows that it has added the value at the end of url. But when I want to achieve the same thing via form action it does not work. please help?
<?php
$url='http://www.xyz.com/search/';
?>
<?php
if (isset($_POST['submit']))
{
$r1=$_POST['num1'];
$result=$url.$r1;
header("location:$result");
}
?>
<html><body>
<form action="" method="post">
Num1:<input name="num1"><br>
<input type="submit" name="submit">
</form>
</body></html>
Please try the above code. I have made some modifications. The main reason your code is not working is whenever you press the submit button it is going to the the url "http://www.xyz.com/search/" directly .The if condition is never executed. In the above mentioned code it will work properly
action="" - you are submitting to the wrong url. Here is alternate version -
<?php $url='http://www.xyz.com/search/';
if (isset($_POST['submit'])) {
$r1=$_POST['num1']; header("Location: ".$r1); // 302 redirection
}
?>
<html><body> <form target="_SELF" method="post"> Num1:<input name="num1" type="text" /><br /> <input type="submit" name="submit" /> </form> </body></html>
maybe very easy!
I'm php coder and I don't have experience in js but I must do this for one of my codes
suppose I have sub1 in page after clicking it must be that sub1 but value now is sub2
<html>
<head>
<title>pharmacy</title>
</head>
<body>
<form method="post" action="pharmacy.php">
<?php
//some code
if(array_key_exists('update',$_POST)){
//somecode
}
?>
<input type="submit" name="update" value="<?php echo if(isset($_GET['update'])) ? 'Show' : 'Update' ?> ">
</form>
</body>
</html>
show as function name does not really make sense here (imo), but you could do:
<input type="submit" name="sub" value="sub1" onclick="show(this)">
and
function show(element) {
element.value = 'sub2';
}
Important:
But that will actually not solve your problem. As soon as you click the button, the form is submitted, meaning the browser initiates a new request and will load a new page. So every change you made the current page is lost anyway.
The question is: What are you trying to do?
It seems to me that you should change the value of the button on the server side. You have to keep track which form was submitted (or how often, I don't know what you are trying to do) and set the value of the button accordingly.
Update:
I see several possibilities to solve this:
You could keep using JavaScript and send and get the data via Ajax. As you have no experience with JavaScript, I would say you have to learn more about JavaScript and Ajax first before you can use it.
You could add a GET parameter in your URL with which you can know which label to show for the button. Example:
<form method="post" action="?update=1">
and
<input type="submit" name="sub" value="<?php echo isset($_GET['update']) ? 'Show' : 'Update' ?> ">
Similar to 2, but use a session variable (and not a GET parameter) to keep track of the state.
Update2:
As you are already having $_POST['update'] you don't need the URL parameter. It could just be:
<html>
<head>
<title>pharmacy</title>
</head>
<body>
<form method="post" action="pharmacy.php">
<input type="submit" name="update" value="<?php echo isset($_POST['update']) ? 'Update' : 'Show'; ?> ">
</form>
</body>
</html>
This should do it
function show(){
document.getElementsByName('sub')[0].value = 'sub2';
return false;
}
Edit: if you don't want it to submit the form, just add a return false, but then you'd need to change your onclick from your submit button to your forms onsubmit;
<html>
<head>
<title>test</title>
<script>
function show()
{
document.getElementById("sub").value= "sub2";
return true;
}
</script>
</head>
<body>
<form method="post">
<input type='submit' id="sub" name='sub' value="sub1" onclick="return show()">
</form>
</body>
</html>