Search multidimensional php array by key - php

I have a multidimensional php array like this
Array
(
[0] => Array
(
[size] => M
[colour] => black
[quantity] => 10
)
[1] => Array
(
[size] => S
[colour] => blue
[quantity] => 10
)
)
and i have another array like this
Array
(
[size] => M
[colour] => black
)
How do i transverse to first array to find the array that matches the second one?.
Am totally clueless on how to go about this. Thanks

Taking a different approach:
$multiArray = array(array('size' => 'M',
'color' => 'black',
'quantity' => '10'),
array('size' => 'S',
'color' => 'blue',
'quantity' => 10));
$otherArray = array('size' => 'S',
'color' => 'blue',
'quantity' => 10)
$message = "Match not found!";
foreach($multiArray as $array) {
$result = array_diff($array, $otherArray);
if(isset($result['size']) or isset($result['color'))
continue;
else
$message = "Found a match!\n Size: {$array['size']}\n Color: {$array['color']}\n Quantity: {$array['quantity']}";
}
echo $message;
This solution seems correct to me because from your example I'm guessing you are trying to find the quantity. Therefore, the array_diff will return the quantity in the result regardless, resulting in the need to check for just size and color for a match.

Consider first array is "mainarray" and second one is "comparearray"
$result = array();
foreach($mainarray as $marray)
{
if($marray['size'] == $comparearray['size'] && $marray['colour'] == $comparearray['colour'])
{
$result = $marray;
//echo "match found";
}
}
note: if compare array is single array it is applicable. if that also multidimension array you should put foreach for that array also.

Try this one
<?php
$arr1 = array(array("size"=>"M","colour" => "black"),array("size"=>"S","colour" => "blue"));
$arr2 = array("size"=>"M","colour" => "black");
print_r($arr1);
print_r($arr2);
foreach($arr1 as $array)
{
if($array['size'] == $arr2['size'] && $array['colour'] == $arr2['colour'])
{
echo "matches";
}
}
?>
working example http://codepad.org/iQPxSHKd

Try
$result = array();
foreach ($multi_array as $arr) {
if ($arr['size'] == $one_dimen_arr['size'] && $arr['colour'] == $one_dimen_arr['colour']) {
$result = $arr;
break;
}
}

For Example:
$array1 is your First array and $array2 is your Second array. Then :
$result = array();
foreach ($array1 as $subarray)
{
$check = array_diff($subarray, $array2);
if (empty($check)) {
$result = $subarray;
}
}

Related

How to convert multi-dimensional array into single array using PHP?

After implementing database queries, I am getting the multi-dimensional array below.
Two Dimensional Array
Array
(
[0] => Array
(
[t1] => test1
)
[1] => Array
(
[t2] => test2
)
[2] => Array
(
[t3] => test3
)
[3] => Array
(
[t4] => test4
)
[4] => Array
(
[t5] => test5
)
)
but I want to convert it to a single dimensional array, like the format below:
One Dimensional Array
Array (
t1 => test1
t2 => test2
t3 => test3
t4 => test4
t5 => test5
)
How can I do this?
I think you can use array_reduce() function.
For example:
$multi= array(0 => array('t1' => 'test1'),1 => array('t2' => 'test2'),2 => array('t3' => 'test3'),3 => array('t4' => 'test4'));
$single= array_reduce($multi, 'array_merge', array());
print_r($single); //Outputs the reduced aray
You can use as follows :
$newArray = array();
foreach($arrayData as $key => $value) {
foreach($value as $key2 => $value2) {
$newArray[$key2] = $value2;
}
}
Where $arrayData is your DB data array and $newArray will be the result.
Assuming that source array is array of arrays and it has no the same keys:
<?php
$src = [
['t1'=>'test1'],
['t2'=>'test2'],
['t3'=>'test3'],
['t4'=>'test4'],
['t5'=>'test5'],
];
$result = call_user_func_array('array_merge', $src);
result via var_dump():
array(5) {
["t1"]=>
string(5) "test1"
["t2"]=>
string(5) "test2"
["t3"]=>
string(5) "test3"
["t4"]=>
string(5) "test4"
["t5"]=>
string(5) "test5"
}
You can use array_reduce() to change values of array. In callback get key of item using key() and select first item using reset().
$newArr = array_reduce($oldArr, function($carry, $item){
$carry[key($item)] = reset($item);
return $carry;
});
Check result in demo
Try this function,
function custom_function($input_array)
{
$output_array = array();
for ($i = 0; $i < count($input_array); $i++) {
for ($j = 0; $j < count($input_array[$i]); $j++) {
$output_array[key($input_array[$i])] = $input_array[$i][key($input_array[$i])];
}
}
return $output_array;
}
$arr = custom_function($arr);
print_r($arr);
Give it a try, it will work.
You can use this
<?php
$temp = array(array('t1' => 'test1'), array('t2' => 'test2'), array('t3' => 'test3'), array('t4' => 'test4'), array('t5' => 'test5'));
$result_array = array();
foreach ($temp as $val) {
foreach ($val as $key => $inner_val) {
$result_array[$key] = $inner_val;
}
}
print_r($result_array);
?>
// Multidimensional array
$arrdata = Array(
'0' => Array(
't1' => 'test1'
) ,
'1' => Array(
't2' => 'test2'
) ,
'2' => Array(
't3' => 'test3'
)
);
// Convert to a single array
$data = array();
foreach($arrdata as $key => $value) {
foreach($value as $key1 => $value1) {
$data[$key1] = $value1;
}
}
echo $data;
Try array map function.
$singleDimensionArray = array_map('current',$multiDimensionArray);
You can use this if you don't care about keeping the correct array keys
function flattenA(array $array) {
$return = array();
array_walk_recursive($array, function($a) use (&$return) { $return[] = $a; });
return $return;
}
print_r(flattenA($arr));
// Output
Array
(
[0] => test1
[1] => test2
[2] => test3
[3] => test4
[4] => test5
)
Otherwise
function flattenB(array $array) {
$return = array();
array_walk_recursive($array, function($v,$k) use (&$return) { $return[$k] = $v; });
return $return;
}
print_r(flattenB($arr));
// Output
Array
(
[t1] => test1
[t2] => test2
[t3] => test3
[t4] => test4
[t5] => test5
)
Check both on Sandbox
From answer on similar question
For your specific case, I would use array_reduce where I set the initial value with an empty array
array_reduce($arr, function($last, $row) {
return $last + $row;
}, array());
AFTER PHP 7.4
array_reduce($arr, fn ($last, $row) => $last + $row, []);
Result :
[
't1' => 'test1',
't2' => 'test2',
't3' => 'test3',
't4' => 'test4',
't5' => 'test5'
]
Hey #Karan Adhikari Simple like below one:
<?php
$arr1 = array(array("t1" => "test1"), array("t2" => "test2"), array("t3" => "test3"), array("t4" => "test4"), array("t5" => "test5"));
echo "<pre>";
print_r($arr1);//before
$arr2 = array();
foreach($arr1 as $val){
$arr2 = array_merge($arr2, $val);
}
echo "<pre>";
print_r($arr2); // after you get your answer
Please try this function:
function array_merging($multi_array) {
if (is_array($multi_array)) {
$new_arr = array();
foreach ($multi_array as $key => $value) {
if (is_array($value)) {
$new_arr = array_merge($new_arr, array_merging($value));
}
else {
$new_arr[$key] = $value;
}
}
return $new_arr;
}
else {
return false;
}
}
Use this function:
$your_multi_arr = array(array(array('t1'=>'test1'),array('t2'=>'test2'),array('t3'=>'test3'),array('t4'=>'test4')));
$arr1 = array_merging($your_multi_arr);
echo "<pre>";
print_r($arr1);
Hope, this may be useful for you.
You can try traversing the array using PHP while list and each. I took sample code from PHP website the second example you can check it here
$arr = [['t1' => 'test1'],['t2' => 'test2'],['t3' => 'test3'],['t4' => 'test4'],['t5' => 'test5']];
$output = [];
while (list($key, $val) = each($arr)) {
while (list($k, $v) = each($val)) {
$output[$k] = $v;
}
}
print_r($output);
Output created is
Array
(
[t1] => test1
[t2] => test2
[t3] => test3
[t4] => test4
[t5] => test5
)
You can test it on your own in this Sandbox example.
This will do the trick
$array = array_column($array, 't1');
Note: This function array_column introduced in PHP 5.5 so it won't work in earlier versions.
traverse the array and save the key value, Live Demo here.
<?php
$array = array(array('t1' => 'test1'), array('t2' => 'test2'), array('t3' => 'test3'), array('t4' => 'test4'), array('t5' => 'test5'));
$result = [];
array_walk($array, function($value) use(&$result){
foreach($value as $k => $v)
{
$result[$k] = $v;
}
});
var_dump($result);
`$result = "Query"; $key_value = array();`
foreach ($result as $key => $value) {
$key_value[$key['']] = $value[''];
}
//for checking //echo "<pre>" ; print_r($key_value) ; exit;
return $key_value;
pls fill $key['name given in sql query for field'] and $value['name given in sql query for field'] (both are same)
this works for me
$result = [];
foreach($excelEmails as $arr)
{
foreach ($arr as $item){
$result = array_merge($result , $item);
}
}
dd($result);
i would recomment my way to convert all double-dimensional array to single-dimensional array.
<?php
$single_Array = array();
//example array
$array = array(
array('t1' => 'test1'),
array('t2' => 'test2'),
array('t3' => 'test3'),
array('t4' => 'test4'),
array('t5' => 'test5'));
$size = sizeof($array);
//loop to fill the new single-dimensional array
for($count = 0; $count<sizeof($array);$count++)
{
//take the key of multi-dim array
$second_cell = key($array[$count]);
//set the value into the new array
$single_array[$count] = $array[$count][$second_cell];
}
//see the results
var_dump($single_array);
?>
with this script we can take keys and values to create new single-dimensional array.I hope that i was helpfull to you.
you can see the example here: Array Convert Demo

Get only Numeric values from Array in PHP

I have an array that looks something like this:
Array (
[0] => Array ( [country_percentage] => 5 %North America )
[1] => Array ( [country_percentage] => 0 %Latin America )
)
I want only numeric values from above array. I want my final array like this
Array (
[0] => Array ( [country_percentage] => 5)
[1] => Array ( [country_percentage] => 0)
)
How I achieve this using PHP?? Thanks in advance...
When the number is in first position you can int cast it like so:
$newArray = [];
foreach($array => $value) {
$newArray[] = (int)$value;
}
I guess you can loop the 2 dimensional array and use a preg_replace, i.e.:
for($i=0; $i < count($arrays); $i++){
$arrays[$i]['country_percentage'] = preg_replace( '/[^\d]/', '', $arrays[$i]['country_percentage'] );
}
Ideone Demo
Update Based on your comment:
for($i=0; $i < count($arrays); $i++){
if( preg_match( '/North America/', $arrays[$i]['country_percentage'] )){
echo preg_replace( '/[^\d]/', '', $arrays[$i]['country_percentage'] );
}
}
Try this:
$arr = array(array('country_percentage' => '5 %North America'),array("country_percentage"=>"0 %Latin America"));
$result = array();
foreach($arr as $array) {
$int = filter_var($array['country_percentage'], FILTER_SANITIZE_NUMBER_INT);
$result[] = array('country_percentage' => $int);
}
Try this one:-
$arr =[['country_percentage' => '5 %North America'],
['country_percentage' => '0 %Latin America']];
$res = [];
foreach ($arr as $key => $val) {
$res[]['country_percentage'] = (int)$val['country_percentage'];
}
echo '<pre>'; print_r($res);
output:-
Array
(
[0] => Array
(
[country_percentage] => 5
)
[1] => Array
(
[country_percentage] => 0
)
)
You can use array_walk_recursive to do away with the loop,
passing the first parameter of the callback as a reference to modify the initial array value.
Then just apply either filter_var or intval as already mentioned the other answers.
$array = [
["country_percentage" => "5 %North America"],
["country_percentage" => "0 %Latin America"]
];
array_walk_recursive($array, function(&$value,$key){
$value = filter_var($value,FILTER_SANITIZE_NUMBER_INT);
// or
$value = intval($value);
});
print_r($array);
Will output
Array
(
[0] => Array
(
[country_percentage] => 5
)
[1] => Array
(
[country_percentage] => 0
)
)
You could get all nemeric values by looping through the array. However I don't think this is the most efficient and good looking answer, I'll post it anyways.
// Array to hold just the numbers
$newArray = array();
// Loop through array
foreach ($array as $key => $value) {
// Check if the value is numeric
if (is_numeric($value)) {
$newArray[$key] = $value;
}
}
I missunderstood your question.
$newArray = array();
foreach ($array as $key => $value) {
foreach ($value as $subkey => $subvalue) {
$subvalue = trim(current(explode('%', $subvalue)));
$newArray[$key] = array($subkey => $subvalue);
}
}
If you want all but numeric values :
$array[] = array("country_percentage"=>"5 %North America");
$array[] = array("country_percentage"=>"3 %Latin America");
$newArray = [];
foreach ($array as $arr){
foreach($arr as $key1=>$arr1) {
$newArray[][$key1] = intval($arr1);
}
}
echo "<pre>";
print_R($newArray);
This is kind of a ghetto method to doing it cause I love using not as many pre made functions as possible. But this should work for you :D
$array = array('jack', 2, 5, 'gday!');
$new = array();
foreach ($array as $item) {
// IF Is numeric (each item from the array) will insert into new array called $new.
if (is_numeric($item)) { array_push($new, $item); }
}

transfer specific index of array to a new array - php

I want to delete an index from array and insert it into in new array. I want two things which i tried to explain one is
Array
(
[index1] => Deleted
[index4] => Inserted
)
Array
(
[index3] => test
[index4] => Inserted
)
Array
(
[index2] => numbers
[index3] => test
[index4] => Inserted
)
Array
(
[index1] => Deleted
)
now i want if arraysize is 1
foreach($array as $arrays){
array_push($array1,($arrays[0]));
unset ($arrays[0]);
}
i want to remove
Array
(
[index1] => Deleted
)
from $array and $array to be
[index1] => Deleted
second is if $array is
Array
(
[index2_123] => numbers
[index3_level] => test
[index4_test] => Inserted
)
i want a new array with $array1 as
Array
(
[index3_level] => test
)
and $array1 is modified to
Array
(
[index2_123] => numbers
[index4_test] => Inserted
)
Try this way,
$arr = Array
(
'index1' => 'Deleted',
'index2' => 'numbers',
'index3' => 'test',
'index4' => 'Inserted'
);
$arr1 = $arr2 = array();
$i = 0;
foreach($arr as $key => $value){
if($i%2 == 0){
$arr1[$key] = $value;
}else{
$arr2[$key] = $value;
}
$i++;
}
Output
$arr1
Array
(
[index1] => Deleted
[index3] => test
)
$arr2
Array
(
[index2] => numbers
[index4] => Inserted
)
And if you don't need that value then you can use it as
$i = 0;
foreach($arr as $key => $value){
if($i%2 == 0){
$arr[$key] = $value;
}else{
unset($arr[$key]);
}
$i++;
}
print_r($arr);
Output:
Array
(
[index1] => Deleted
[index3] => test
)
Loop through them and generate the array -
$new = array();
foreach($yourarray as $key => $val) {
$index = str_replace('index', '', $key); // get the key index
if($index % 2 != 0) { // check for odd or even
$new[$key] = $val; // set the new array
unset($yourarray[$key]); // delete from the main array
}
}
Update
For any index use a counter
$i = 0;
$new = array();
foreach($yourarray as $key => $val) {
if($i % 2 != 0) { // check for odd or even
$new[$key] = $val; // set the new array
unset($yourarray[$key]); // delete from the main array
}
$i++;
}
You can use a combination of array_flip and array_diff_key to filter the first array, then use array_diff filter the second:
$specificIndex = array('index1', 'index3');
$array1 = array_diff_key($array, array_flip($specificIndex));
$array2 = array_diff($array, $array1);
Demo.
If you want get in an array only certain elements of your choice you can do something like:
$specificIndex = array('index1', 'index3');
$selectedItem = array_intersect_key($array, array_flip($specificIndex));
Demo.
<?php
$array = array(
'index1' => 'Deleted',
'index2' => 'numbers',
'index3' => 'test',
'index4' => 'Inserted',
);
$specificIndex = 'index3';
$array1=array();
foreach($array as $key => $value){
if($key==$specificIndex){
$array1[$key] = $value;
unset($array[$specificIndex]);
}
}
print_r($array);
print_r($array1);
http://3v4l.org/TvZ19

combine arrays and concat value?

Little complex to explain , so here is simple concrete exemple :
array 1 :
Array
(
[4] => bim
[5] => pow
[6] => foo
)
array 2 :
Array
(
[n] => Array
(
[0] => 1
)
[m] => Array
(
[0] => 1
[1] => 2
)
[l] => Array
(
[0] => 1
[1] => 4
[2] => 64
)
And i need to output an array 3 ,
array expected :
Array
(
[bim] => n-1
[pow] => Array
(
[0] => m-1
[1] => m-2
)
[foo] => Array
(
[0] => l-1
[1] => l-4
[2] => l-64
)
Final echoing OUTPUT expected:
bim n-1 , pow m-1 m-2 ,foo l-1 l-4 l-64 ,
I tried this but seems pity:
foreach($array2 as $k1 =>$v1){
foreach($array2[$k1] as $k => $v){
$k[] = $k1.'_'.$v);
}
foreach($array1 as $res =>$val){
$val = $array2;
}
Thanks for helps,
Jess
CHALLENGE ACCEPTED
<?php
$a = array(
4 => 'bim',
5 => 'pow',
6 => 'foo',
);
$b = array(
'n' => array(1),
'm' => array(1, 2),
'l' => array(1, 4, 64),
);
$len = count($a);
$result = array();
$aVals = array_values($a);
$bKeys = array_keys($b);
$bVals = array_values($b);
for ($i = 0; $i < $len; $i++) {
$combined = array();
$key = $aVals[$i];
$prefix = $bKeys[$i];
$items = $bVals[$i];
foreach ($items as $item) {
$combined[] = sprintf('%s-%d', $prefix, $item);
};
if (count($combined) === 1) {
$combined = $combined[0];
}
$result[$key] = $combined;
}
var_dump($result);
?>
Your code may be very easy. For example, assuming arrays:
$one = Array
(
4 => 'bim',
5 => 'pow',
6 => 'foo'
);
$two = Array
(
'n' => Array
(
0 => 1
),
'm' => Array
(
0 => 1,
1 => 2
),
'l' => Array
(
0 => 1,
1 => 4,
2 => 64
)
);
You may get your result with:
$result = [];
while((list($oneKey, $oneValue) = each($one)) &&
(list($twoKey, $twoValue) = each($two)))
{
$result[$oneValue] = array_map(function($item) use ($twoKey)
{
return $twoKey.'-'.$item;
}, $twoValue);
};
-check this demo Note, that code above will not make single-element array as single element. If that is needed, just add:
$result = array_map(function($item)
{
return count($item)>1?$item:array_shift($item);
}, $result);
Version of this solution for PHP4>=4.3, PHP5>=5.0 you can find here
Update: if you need only string, then use this (cross-version):
$result = array();
while((list($oneKey, $oneValue) = each($one)) &&
(list($twoKey, $twoValue) = each($two)))
{
$temp = array();
foreach($twoValue as $item)
{
$temp[] = $twoKey.'-'.$item;
}
$result[] = $oneValue.' '.join(' ', $temp);
};
$result = join(' ', $result);
As a solution to your problem please try executing following code snippet
<?php
$a=array(4=>'bim',5=>'pow',6=>'foo');
$b=array('n'=>array(1),'m'=>array(1,2),'l'=>array(1,4,64));
$keys=array_values($a);
$values=array();
foreach($b as $key=>$value)
{
if(is_array($value) && !empty($value))
{
foreach($value as $k=>$val)
{
if($key=='n')
{
$values[$key]=$key.'-'.$val;
}
else
{
$values[$key][]=$key.'-'.$val;
}
}
}
}
$result=array_combine($keys,$values);
echo '<pre>';
print_r($result);
?>
The logic behind should be clear by reading the code comments.
Here's a demo # PHPFiddle.
//omitted array declarations
$output = array();
//variables to shorten things in the loop
$val1 = array_values($array1);
$keys2 = array_keys($array2);
$vals2 = array_values($array2);
//iterating over each element of the first array
for($i = 0; $i < count($array1); $i++) {
//if the second array has multiple values at the same index
//as the first array things will be handled differently
if(count($vals2[$i]) > 1) {
$tempArr = array();
//iterating over each element of the second array
//at the specified index
foreach($vals2[$i] as $val) {
//we push each element into the temporary array
//(in the form of "keyOfArray2-value"
array_push($tempArr, $keys2[$i] . "-" . $val);
}
//finally assign it to our output array
$output[$val1[$i]] = $tempArr;
} else {
//when there is only one sub-element in array2
//we can assign the output directly, as you don't want an array in this case
$output[$val1[$i]] = $keys2[$i] . "-" . $vals2[$i][0];
}
}
var_dump($output);
Output:
Array (
["bim"]=> "n-1"
["pow"]=> Array (
[0]=> "m-1"
[1]=> "m-2"
)
["foo"]=> Array (
[0]=> "l-1"
[1]=> "l-4"
[2]=> "l-64"
)
)
Concerning your final output you may do something like
$final = "";
//$output can be obtained by any method of the other answers,
//not just with the method i posted above
foreach($output as $key=>$value) {
$final .= $key . " ";
if(count($value) > 1) {
$final .= implode($value, " ") .", ";
} else {
$final .= $value . ", ";
}
}
$final = rtrim($final, ", ");
This will echo bim n-1, pow m-1 m-2, foo l-1 l-4 l-64.

count of duplicate elements in an array in php

Hi,
How can we find the count of duplicate elements in a multidimensional array ?
I have an array like this
Array
(
[0] => Array
(
[lid] => 192
[lname] => sdsss
)
[1] => Array
(
[lid] => 202
[lname] => testing
)
[2] => Array
(
[lid] => 192
[lname] => sdsss
)
[3] => Array
(
[lid] => 202
[lname] => testing
)
)
How to find the count of each elements ?
i.e, count of entries with id 192,202 etc
You can adopt this trick; map each item of the array (which is an array itself) to its respective ['lid'] member and then use array_count_value() to do the counting for you.
array_count_values(array_map(function($item) {
return $item['lid'];
}, $arr);
Plus, it's a one-liner, thus adding to elite hacker status.
Update
Since 5.5 you can shorten it to:
array_count_values(array_column($arr, 'lid'));
foreach ($array as $value)
{
$numbers[$value[lid]]++;
}
foreach ($numbers as $key => $value)
{
echo 'numbers of '.$key.' equal '.$value.'<br/>';
}
Following code will count duplicate element of an array.Please review it and try this code
$arrayChars=array("green","red","yellow","green","red","yellow","green");
$arrLength=count($arrayChars);
$elementCount=array();
for($i=0;$i<$arrLength-1;$i++)
{
$key=$arrayChars[$i];
if($elementCount[$key]>=1)
{
$elementCount[$key]++;
} else {
$elementCount[$key]=1;
}
}
echo "<pre>";
print_r($elementCount);
OUTPUT:
Array
(
[green] => 3
[red] => 2
[yellow] => 2
)
You can also view similar questions with array handling on following link
http://solvemyquest.com/count-duplicant-element-array-php-without-using-built-function/
The following code will get the counts for all of them - anything > 1 at the end will be repeated.
<?php
$lidCount = array();
$lnameCount = array();
foreach ($yourArray as $arr) {
if (isset($lidCount[$arr['lid']])) {
$lidCount[$arr['lid']]++;
} else {
$lidCount[$arr['lid']] = 1;
}
if (isset($lnameCount [$arr['lname']])) {
$lnameCount [$arr['lname']]++;
} else {
$lnameCount [$arr['lname']] = 1;
}
}
$array = array('192', '202', '192', '202');
print_r(array_count_values($array));
$orders = array(
array(
'lid' => '',
'lname' => '',
))....
$foundIds = array();
foreach ( $orders as $index => $order )
{
if ( isset( $foundIds[$order['lid']] ) )
{
$orders[$index]['is_dupe'] = true;
$orders[$foundIds[$order['lid']]]['is_dupe'] = true;
} else {
$orders[$index]['is_dupe'] = false;
}
$foundIds[$order['lid']] = $index;
}
Try this code :
$array_count = array();
foreach ($array as $arr) :
if (in_array($arr, $array_count)) {
foreach ($array_count as $key => $count) :
if ($key == $arr) {
$array_count[$key]++;
break;
}
endforeach;
} else {
$array_count[$arr] = 1;
}
endforeach;
Check with in_array() function.

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