I am trying to get a string to a float so I can do math with it. I have tried many methods including floatval(). The answers always return to a big, fat, 0. I have also tried casting and get the same result. I have tried it with single variables and arrays. Here is the current code I am wrestling with:
<?php
$sim = array("$1.99","$0.75","$0.25");
for($i=0;$i<=2;$i+=1)
$som[$i] = floatval($sim[$i]);
for($i=0;$i<=2;$i+=1)
{
echo $som[$i];
echo "<br/>";
}
?>
Start by removing the dollar sign first with str_replace('$', '', $sim[$i])
You could also use substr to get rid of the $ in your string.
$sim = array("$1.99","$0.75","$0.25");
for($i=0;$i<=2;$i+=1)
$som[$i] = (float)(substr($sim[$i], 1));
for($i=0;$i<=2;$i+=1)
{
echo $som[$i];
echo "<br/>";
}
Here are some useful links.
http://us2.php.net/language.types.type-juggling
http://us2.php.net/manual/en/language.types.string.php#language.types.string.conversion
Related
I have the function get_price_data(); which gives "0,11\u20ac" as return value.
The "0,11" is not static.
I want to do some maths with "0,11" from the string below.
My Code shown down below does not work how i want it to. Has someone any idea how i can complete this task ? I am very new to php.
<?php
function get_price_data() {
$json = file_get_contents("http://steamcommunity.com/market/priceoverview/?currency=3&appid=730&market_hash_name=Chroma%202%20Case");
$decode = json_decode($json,1);
echo $decode['median_price'];
}
$string=get_price_data();
$string2 = str_replace("\u20ac","",$string);
echo $string2 * 1000 - 120;
?>
<?php
function get_price_data() {
$json = file_get_contents("http://steamcommunity.com/market/priceoverview/?currency=3&appid=730&market_hash_name=Chroma%202%20Case");
$decode = json_decode($json,1);
return $decode['median_price']; // return here instead of echo.
}
You are somewhat correct that this return is necessary because this is a function. A return statement is not specifically required in a PHP function (functions will return null by default if there is no explicit return value.) The reason you need it to return is that you are using its returned value in this statement:
$string=get_price_data();
With echo instead of return, $string will be set to null here, and any subsequent operations on it will obviously not do what you intended.
If you change your function to return the value of $decode['median_price'], then $string=get_price_data(); will assign 0,11€ to $string, and then your replacements and calculations should work as expected.
$string=str_replace(array('€','\u20ac'),'',$string);
$string = str_replace(",",".",$string); // replace , with . as noted by mertizci
echo $string * 1000 - 120;
?>
Because of the comma in the changed price value, PHP cant do math things on it. You should change the comma with dot too.
Your code should be (edited):
<?php
$string=get_price_data();
$string=str_replace(array('€','\u20ac'),'',$string);
$string = str_replace(",",".",$string);
echo $string * 1000 - 120;
?>
I'm working on a php function that will compare the components of two arrays. Each value in the arrays are only one english word long. No spaces. No characters.
Array #1: a list of the most commonly used words in the english
language. $common_words_array
Array #2: a user-generated sentence, converted to lowercase, stripped
of punctuation, and exploded() using the space (" ") as a delimiter.
$study_array
There's also a $com_study array, which is used in this case to keep
track of the order of commonly used words which get replaced in the
$study_array by a "_" character.
Using nested for loops, what SHOULD happen is that the script should compare each value in Array #2 to each value in Array #1. When it finds a match (aka. a commonly used english word), it will do some other magic that's irrelevant to the current problem.
As of right now, PHP doesn't recognize when two array string values are equivalent. I'm adding in the code to the problematic function here for reference. I've added in a lot of unnecessary echo commands in order to localize the problem to the if statement.
Can anybody see something that I've missed? The same algorithm worked perfectly in Python.
function create_question($study_array, $com_study, $common_words_array)
{
for ($study=0; $study<count($study_array); $study++)
{
echo count($study_array)." total in study_array<br>";
echo "study is ".$study."<br>";
for ($common=0; $common<count($common_words_array); $common++)
{
echo count($common_words_array)." total in common_words_array<br>";
echo "common is ".$common."<br>";
echo "-----<br>";
echo $study_array[$study]." is the study list word<br>";
echo $common_words_array[$common]." is the common word<br>";
echo "-----<br>";
// The issue happens right here.
if ($study_array[$study] == $common_words_array[$common])
{
array_push($com_study, $study_array[$study]);
$study_array[$study] = "_";
print_r($com_study);
print_r($study_array);
}
}
}
$create_question_return_array = array();
$create_question_return_array[0] = $study_array;
$create_question_return_array[1] = $com_study;
return $create_question_return_array;
}
EDIT: At the suggestion of you amazing coders, I've updated the if statement to be much more simple for purposes of debugging. See below. Still having the same issue of not activating the if statement.
if (strcmp($study_array[$study],$common_words_array[$common])==0)
{
echo "match found";
//array_push($com_study, $study_array[$study]);
//$study_array[$study] = "_";
//print_r($com_study);
//print_r($study_array);
}
EDIT: At bansi's request, here's the main interface snippet where I'm calling the function.
$testarray = array();
$string = "This is a string";
$testarray = create_study_string_array($string);
$testarray = create_question($testarray, $matching, $common_words_array);
As for the result, I'm just getting a blank screen. I would expect to have the simplified echo statement output "match found" to the screen, but that's not happening.
(EDIT) make sure your that your splitting function removes excess whitespace (e.g. preg_split("\\s+", $input)) and that the input is normalized properly (lowercase'd, special chars stripped out, etc.).
On mobile and can't seem to copy text. You forgot a dollar sign when accessing the study array in your push command.
change
array_push($com_study, $study_array[study]);
to
array_push($com_study, $study_array[$study]);
// You missed a $ ^ here
Edit:
The following code outputs 3 'match found'. i don't know the values of $common_words_array and $matching, so i used some arbitrary values, also instead of using function create_study_string_array i just used explode. still confused, can't figure out what exactly you are trying to achieve.
<?php
$testarray = array ();
$string = "this is a string";
$testarray = explode ( ' ', $string );
$common_words_array = array (
'is',
'a',
'this'
);
$matching = array (
'a',
'and',
'this'
);
$testarray = create_question ( $testarray, $matching, $common_words_array );
function create_question($study_array, $com_study, $common_words_array) {
echo count ( $study_array ) . " total in study_array<br>";
echo count ( $common_words_array ) . " total in common_words_array<br>";
for($study = 0; $study < count ( $study_array ); $study ++) {
// echo "study is " . $study . "<br>";
for($common = 0; $common < count ( $common_words_array ); $common ++) {
// The issue happens right here.
if (strcmp ( $study_array [$study], $common_words_array [$common] ) == 0) {
echo "match found";
}
}
}
$create_question_return_array = array ();
$create_question_return_array [0] = $study_array;
$create_question_return_array [1] = $com_study;
return $create_question_return_array;
}
?>
Output:
4 total in study_array
3 total in common_words_array
match foundmatch foundmatch found
Use === instead of ==
if ($study_array[$study] === $common_words_array[$common])
OR even better use strcmp
if (strcmp($study_array[$study],$common_words_array[$common])==0)
Use built-in functions wherever possible to avoid unnecessary code and typos. Also, providing sample inputs would be helpful too.
$study_array = array("a", "cat", "sat", "on","the","mat");
$common_words_array = array('the','a');
$matching_words = array();
foreach($study_array as $study_word_index=>$study_word){
if(in_array($study_word, $common_words_array)){
$matching_words[] = $study_word;
$study_array[$study_word_index] = "_";
//do something with matching words
}
}
print_r($study_array);
print_r($matching_words);
I have the following code that is not returning as I expected. I was hoping the final result would be a string:
$organizers = array_unique($organizers); // this returns correctly
$organizers = implode(', ', $organizers); // this returns nothing
var_dump($organizers); // no data appears here
exit;
The array_unique() function is returning data correctly and I can see the array it returns. To start, the $organizers array is a simple 1-D array of strings that all have small lengths under 20 chars. I think the issue might be that $organizers is more than 10,000 indices long. Are there limitations on the length of an array that can be imploded? Are there work-arounds for that? I cannot find anything in the manual, but I have tested this code thoroughly and I believe the error must be on implode().
I dont' know if there is a limitation, but what comes to my mind is taht you are also transforming an array into a string. This shouldn't be the problem in PHP, but try calling it a different variable for the result of implode?
$organizers = array_unique($organizers); // this returns correctly
$organizers_string = implode(', ', $organizers); // this returns nothing
// This gives it a different space
Edit: And if for some reason implode() is still problematic.
$organizers = array_unique($organizers);
$neworganizers = "";
for($i = 0; $i < sizeof($organizers); $i++)
{
$neworganizers .= $organizers[$i];
if($i != sizeof($organizers) - 1)
{
$neworganizers .= ", ";
}
}
//$neworganizers is now the equivalent of what .implode() should return when called on $organizers
$organizers = array();
$organizers[0] = "value1";
$organizers[1] = "value2";
$organizers[2] = "value3";
$organizers[3] = "value3";
$organizers = array_unique($organizers); // strips out last index
$organizers = implode(', ', $organizers); // returns string of "value1, value2, value3"
echo $organizers;
This seemed to work on writecodeline.com/php/
I've also experienced issues with older php builds when I've tried to explode/implode by a string with special characters in it and they were encapsulated by single quotes. I know it sounds crazy, but the double quotes might be necessary on some servers.
Reference: personal experience doing work on older production servers.
I'd hate to think I'm stating the obvious, but doesn't implode only take a string as an argument? Maybe it should be something more like this...
$organizers = array_unique($organizers);
//I'm guessing what you wanted was an array of arrays?
$neworganizers = array();
for($i = 0; $i < sizeof($organizers); $i++)
{
$neworganizers[$i] = implode(", ", $organizers);
}
print_r($neworganizers);
I have a whole bunch of percentages stored as XX% (e.g. 12%, 50%, etc..) I need to remove the percentage sign and then multiply the percent against another variable thats just a number (e.g. 1000, 12000) and then output the result. Is there a simple way to strip the percentage sign and then calculate the output with PHP? Or should I consider some sort of JS solution?
You could use rtrim():
$value = ((int) rtrim('12%', '%')) * 1000';
Edit
You don't strictly need to call rtrim() , as it casts to an int ok with the percentage sign. It is probably cleaner to strip it though.
var_dump (12 === (int) '12%');
//output: bool(true)
You can make use of preg_replace_callback as:
$input = '12%, 50%';
$input = preg_replace_callback("|(\d+)%|","replace_precent",$input);
echo $input; // 12000, 50000
function replace_precent($matches) {
return $matches[1] * 1000;
}
Try this:
$number = str_replace('%', '', '100%');
$result = intval($number) * 5000; // or whatever number
echo $result;
If you use trim() or str_replace() in PHP you can remove the percent sign. Then, you should be able to multiply the resulting number (php is weakly typed after all).
<?php
$number = str_replace("%", "", $percentString);
$newNumber = ((int) $number) * 1000;
echo $newNumber;
?>
You can use str_replace. You can also pass an array of subjects into str_replace to have them all replaced.
<?php
$number = str_replace("%", "", $percentage);
$result = $number * $other_var;
print $result;
?>
<?php
$input=array('15%','50%','10.99%','21.5%');
$multiplier=1000;
foreach($input as $n){
$z=floatval($n)*$multiplier;
print("$z<br>");
}
?>
Consider my variable $result to be 01212.... Now if i add 1 to my variable i get the answer 1213,but i want it to be 01213.... My php code is
echo sprintf('%02u', ($result+1));
Edit:
Answers to this question works.. But what happens if my variable is $result to be 0121212
in future...
You can use %05u instead on %02u
echo sprintf('%05u', ($result+1));
EDIT:
To generalize it:
<?php
$result = "0121211";
$len = strlen($result+1) + 1;
printf("%0${len}d", ($result+1)); // print 0121212
?>
you could try:
str_pad($result, 5, "0", STR_PAD_LEFT);
Maybe I'm missing something here but it could be as simple as
$result = '0'. ($result+1);
edit:
$test = array('01212', '0121212', '012121212121212', '-01212');
foreach( $test as $result ) {
$result = '0'.($result+1);
echo $result, "\n";
}
prints
01213
0121213
012121212121213
0-1211
( you see, there are limitations ;-) )
Read here: http://php.net/manual/en/function.sprintf.php
in sprintf, you also has to specify length you want - so in your case, if you want any number to be shown 5chars long, you haveto write
echo sprintf ('%05d', $d); // 5 places taking decimal
or even better
printf ('%05d', $d);
Seems like you want to have a '0' in front of the number, so here would be the simplest :P
echo '0'. $result;
Or if you insist on using sprintf:
$newresult = $result + 1;
echo sprintf('%0'.(strlen(strval($newresult))+1).'u', $newresult);